Electrostatics
Q. For a charged sphere, what happens to the electric field inside the sphere as the radius increases?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Becomes zero
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Solution
The electric field inside a uniformly charged sphere is zero.
Correct Answer: D — Becomes zero
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Q. For a charged spherical conductor, what happens to the electric field inside the conductor when it is charged?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Becomes zero
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Solution
The electric field inside a charged conductor in electrostatic equilibrium is zero.
Correct Answer: D — Becomes zero
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Q. For a closed surface enclosing multiple charges, how is the total electric flux calculated?
A.
Sum of individual fluxes
B.
Product of charges
C.
Sum of enclosed charges divided by ε₀
D.
Average of charges
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Solution
The total electric flux through a closed surface is given by Φ = ΣQ_enc/ε₀, where Q_enc is the total charge enclosed.
Correct Answer: C — Sum of enclosed charges divided by ε₀
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Q. For a closed surface enclosing multiple charges, how is the total electric flux related to the enclosed charges?
A.
It is proportional to the sum of the charges
B.
It is inversely proportional to the sum of the charges
C.
It is independent of the charges
D.
It is proportional to the square of the charges
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Solution
According to Gauss's law, the total electric flux through a closed surface is proportional to the total charge enclosed.
Correct Answer: A — It is proportional to the sum of the charges
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Q. For a point charge, the electric field varies with distance r as?
A.
1/r
B.
1/r²
C.
1/r³
D.
1/r⁴
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Solution
The electric field due to a point charge varies as E = kQ/r², where k is a constant.
Correct Answer: B — 1/r²
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Q. For a spherical Gaussian surface of radius R enclosing a charge Q, what is the electric field at a distance 2R from the center?
A.
Q/4πε₀(2R)²
B.
Q/4πε₀R²
C.
Q/4πε₀(2R)³
D.
0
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Solution
The electric field outside a spherical charge distribution behaves as if all the charge were concentrated at the center, so E = Q/4πε₀r².
Correct Answer: A — Q/4πε₀(2R)²
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Q. For a uniformly charged sphere of radius R and total charge Q, what is the electric field at a distance r from the center where r > R?
A.
Q/(4πε₀r²)
B.
0
C.
Q/(4πε₀R²)
D.
Q/(4πε₀r)
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Solution
For r > R, the electric field behaves as if all the charge were concentrated at the center, given by E = Q/(4πε₀r²).
Correct Answer: A — Q/(4πε₀r²)
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Q. For an infinite plane sheet of charge with surface charge density σ, what is the electric field at a point near the sheet?
A.
σ/2ε₀
B.
σ/ε₀
C.
0
D.
σ/4πε₀
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Solution
Using Gauss's law, the electric field due to an infinite plane sheet of charge is E = σ/2ε₀ on either side of the sheet.
Correct Answer: A — σ/2ε₀
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Q. For an infinite plane sheet of charge with surface charge density σ, what is the electric field at any point?
A.
σ/2ε₀
B.
σ/ε₀
C.
0
D.
σ/4πε₀
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Solution
The electric field due to an infinite plane sheet of charge is constant and given by E = σ/2ε₀ on either side of the sheet.
Correct Answer: A — σ/2ε₀
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Q. If a capacitor has a capacitance of 10 µF and is charged to 5 V, what is the charge on the capacitor?
A.
50 µC
B.
5 µC
C.
2 µC
D.
10 µC
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Solution
The charge (Q) on a capacitor is given by Q = C * V. Here, Q = 10 µF * 5 V = 50 µC.
Correct Answer: A — 50 µC
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Q. If a capacitor is charged and then short-circuited, what happens to the charge on the capacitor?
A.
It remains the same
B.
It is discharged
C.
It increases
D.
It becomes zero
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Solution
When a charged capacitor is short-circuited, the charge flows through the circuit, and the charge on the capacitor becomes zero.
Correct Answer: B — It is discharged
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Q. If a capacitor is charged to a voltage V and then connected in parallel with an uncharged capacitor, what will be the final voltage across both capacitors?
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Solution
When connected in parallel, charge redistributes, and the final voltage across both capacitors will be V/2.
Correct Answer: B — V/2
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Q. If a capacitor is charged to a voltage V and then connected to a resistor R, what is the time constant of the circuit?
A.
RC
B.
R/C
C.
C/R
D.
1/RC
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Solution
The time constant τ of an RC circuit is given by τ = R * C.
Correct Answer: A — RC
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Q. If a capacitor is charged to a voltage V and then short-circuited, what happens to the charge on the capacitor?
A.
It remains the same
B.
It becomes zero
C.
It doubles
D.
It halves
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Solution
Short-circuiting a capacitor allows charge to flow off, resulting in the charge becoming zero.
Correct Answer: B — It becomes zero
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Q. If a capacitor is charged to a voltage V and then short-circuited, what happens to the energy stored in the capacitor?
A.
It is conserved
B.
It is dissipated as heat
C.
It increases
D.
It becomes zero
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Solution
When a capacitor is short-circuited, the stored energy is dissipated as heat in the circuit.
Correct Answer: B — It is dissipated as heat
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Q. If a capacitor is connected to a DC voltage source, what will happen to the current over time?
A.
It remains constant
B.
It increases
C.
It decreases to zero
D.
It oscillates
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Solution
In a DC circuit, the current through a capacitor decreases to zero as it becomes fully charged.
Correct Answer: C — It decreases to zero
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Q. If a capacitor is connected to an AC source, how does the current behave?
A.
It is constant
B.
It leads the voltage
C.
It lags the voltage
D.
It is zero
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Solution
In an AC circuit, the current through a capacitor leads the voltage by 90 degrees.
Correct Answer: B — It leads the voltage
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Q. If a capacitor is fully charged and then short-circuited, what happens to the stored energy?
A.
It is released as heat
B.
It is stored in the circuit
C.
It remains in the capacitor
D.
It is lost
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Solution
When a charged capacitor is short-circuited, the stored energy is released as heat due to the current flow.
Correct Answer: A — It is released as heat
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Q. If a capacitor is fully discharged and then connected to a voltage source, what is the initial current through the circuit?
A.
Zero
B.
Maximum
C.
Depends on resistance
D.
Infinite
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Solution
When a capacitor is fully discharged and connected to a voltage source, the initial current is maximum as it starts charging.
Correct Answer: B — Maximum
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Q. If a capacitor of capacitance 4μF is connected to a 12V battery, what is the charge on the capacitor?
A.
48μC
B.
12μC
C.
4μC
D.
24μC
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Solution
Charge (Q) on a capacitor is given by Q = C * V. Here, Q = 4μF * 12V = 48μC.
Correct Answer: A — 48μC
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Q. If a capacitor of capacitance C is charged to a voltage V, what is the energy stored in the capacitor?
A.
1/2 CV^2
B.
CV
C.
V^2 / C
D.
C / V
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Solution
The energy (U) stored in a capacitor is given by the formula U = 1/2 CV^2.
Correct Answer: A — 1/2 CV^2
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Q. If a capacitor of capacitance C is connected to a voltage source V, what is the charge on the capacitor?
A.
C/V
B.
V/C
C.
CV
D.
V^2/C
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Solution
The charge (Q) on a capacitor is given by Q = CV when connected to a voltage source V.
Correct Answer: C — CV
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Q. If a capacitor with capacitance C is connected to a voltage V, what is the charge stored in the capacitor?
A.
C/V
B.
V/C
C.
C * V
D.
C + V
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Solution
The charge (Q) stored in a capacitor is given by the formula Q = C * V.
Correct Answer: C — C * V
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Q. If a charge of +3μC is placed in a uniform electric field of strength 2000 N/C, what is the force acting on the charge?
A.
6000 N
B.
3000 N
C.
4000 N
D.
2000 N
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Solution
F = qE = (3 × 10^-6 C) * (2000 N/C) = 6 × 10^-3 N = 6000 N.
Correct Answer: A — 6000 N
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Q. If a charge of +3μC is placed in an electric field of 1000 N/C, what is the force acting on it?
A.
3000 N
B.
3 N
C.
0.3 N
D.
30 N
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Solution
F = q * E = (3 × 10^-6 C) * (1000 N/C) = 3 × 10^-3 N = 3000 N.
Correct Answer: A — 3000 N
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Q. If a charge of +3μC is placed in an electric field of 2000 N/C, what is the force experienced by the charge?
A.
6000 N
B.
3000 N
C.
4000 N
D.
2000 N
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Solution
Force F = qE = (3 × 10^-6 C) * (2000 N/C) = 6000 N.
Correct Answer: A — 6000 N
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Q. If a charge of +3μC is placed in an electric field of 500 N/C, what is the force acting on it?
A.
1500 N
B.
300 N
C.
500 N
D.
750 N
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Solution
F = q * E = (3 × 10^-6 C) * (500 N/C) = 1500 N.
Correct Answer: A — 1500 N
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Q. If a charge of +4μC is placed in an electric field of 500 N/C, what is the force acting on the charge?
A.
2 N
B.
0.5 N
C.
4 N
D.
1 N
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Solution
F = q * E = 4 × 10^-6 C * 500 N/C = 2 N.
Correct Answer: A — 2 N
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Q. If a charge of +Q is placed at one corner of a cube, what is the electric flux through one face of the cube?
A.
Q/6ε₀
B.
Q/3ε₀
C.
Q/4ε₀
D.
Q/12ε₀
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Solution
The total flux through the cube is Q/ε₀. Since the charge is at one corner, the flux through one face is Q/6ε₀.
Correct Answer: A — Q/6ε₀
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Q. If a charge of +Q is placed at one corner of a cube, what is the total electric flux through the entire surface of the cube?
A.
Q/ε₀
B.
Q/6ε₀
C.
0
D.
Q/4ε₀
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Solution
The total electric flux through the cube is Q/ε₀, but since only 1/6 of the charge is enclosed by the cube, the flux is Q/6ε₀.
Correct Answer: B — Q/6ε₀
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