When light reflects off a denser medium, a phase change of π occurs, leading to destructive interference for certain path differences.

If destructive interference occurs for blue light, the color seen will be the complementary color, which is red.

The color that appears at the center of the pattern corresponds to the wavelength that experiences constructive interference, which in this case is red light.

At the center of the thin film interference pattern, the color that appears is typically green due to the constructive interference of wavelengths in that range.

The magnetic force is maximum when the angle between the conductor and the magnetic field is 90 degrees, as sin(90°) = 1.

In a vacuum, light travels the fastest at approximately 3 x 10^8 m/s, while sound and water waves require a medium to travel.

Inductive reactance (XL) = 2πfL = 2π(60)(0.2) ≈ 75.36Ω.

Inductive reactance (XL = 2πfL) increases with an increase in frequency.

The angle θ can be found using cos(θ) = power factor. Therefore, θ = cos⁻¹(0.8) ≈ 36.87°.

The impedance Z = √(R² + XL²) = √(10² + 20²) = √(100 + 400) = √500 = 22.36 ohms.

The total impedance Z = √(R² + XL²) = √(10² + 20²) = √(100 + 400) = √500 = 22.36 ohms.

The total impedance Z = √(R² + XL²) = √(10² + 20²) = √(100 + 400) = √500 = 22.36Ω.

Real power P = V * I * power factor = 120 * 10 * 0.8 = 960 W.

Power factor = Real Power / (Voltage × Current) = 600 / (120 × 10) = 0.5.

Real power P = V * I * power factor = 120V * 10A * 0.8 = 960W.

Power factor = Real Power / (Voltage x Current) = 600 / (120 x 10) = 600 / 1200 = 0.5.

The RMS voltage is V_rms = V0/√2 = 100/√2 = 70.7 V.

The peak voltage is given by the coefficient of sin, which is 100√2.

RMS voltage V_rms = V_peak / √2 = 120 / √2 = 84.85 V.

The peak voltage V0 is given directly in the equation as 10V.

The peak voltage in the equation V(t) = V0 sin(ωt) is V0.

In an adiabatic process, as the temperature decreases, the pressure also decreases due to the ideal gas law.

In an isochoric process, the volume remains constant.

Total impedance Z = √(R² + (XL - XC)²) = √(6² + (8 - 4)²) = √(36 + 16) = √52 ≈ 10Ω.

The quality factor Q is inversely proportional to resistance. Increasing resistance decreases Q.

If the inductive reactance (XL) is greater than the capacitive reactance (XC), the circuit is inductive.

The resonant frequency f0 = 1/(2π√(LC)) = 1/(2π√(0.1 * 100e-6)) = 159 Hz.

Using Z = √(R² + (XL)²), solve for XL.

Using Z = √(R² + X²), we find X = √(Z² - R²). Here, Z = 20Ω, R = 15Ω.

Using Z = √(R² + X²), we find X = √(Z² - R²) = √(50² - 30²) = √(2500 - 900) = √1600 = 40 ohms.