Q. A cyclist accelerates from rest to a speed of 10 m/s in 5 seconds. What is the cyclist's acceleration? (2021)
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A.
1 m/s²
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B.
2 m/s²
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C.
3 m/s²
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D.
4 m/s²
Solution
Acceleration a = (final velocity - initial velocity) / time = (10 m/s - 0) / 5 s = 2 m/s².
Correct Answer: B — 2 m/s²
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Q. A force of 15 N is applied to a 3 kg mass. What is the resulting acceleration? (2023)
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A.
3 m/s²
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B.
5 m/s²
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C.
7 m/s²
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D.
10 m/s²
Solution
Using F = ma, acceleration a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A force of 30 N is applied to a 6 kg object. What is the object's acceleration? (2023)
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A.
3 m/s²
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B.
4 m/s²
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C.
5 m/s²
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D.
6 m/s²
Solution
Using F = ma, we find a = F/m = 30 N / 6 kg = 5 m/s².
Correct Answer: B — 4 m/s²
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Q. An object is thrown vertically upwards with a velocity of 20 m/s. How high will it rise? (Assume g = 10 m/s²) (2020)
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A.
20 m
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B.
30 m
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C.
40 m
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D.
50 m
Solution
Using h = v²/(2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.
Correct Answer: A — 20 m
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Q. An object moves with a constant velocity of 10 m/s. What is the net force acting on it? (2023)
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A.
0 N
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B.
10 N
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C.
20 N
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D.
100 N
Solution
If the object moves with constant velocity, the net force acting on it is 0 N.
Correct Answer: A — 0 N
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Q. If a 10 kg object is dropped from a height of 20 m, what is the velocity just before it hits the ground? (Assume g = 10 m/s²) (2019)
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A.
10 m/s
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B.
20 m/s
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C.
14 m/s
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D.
15 m/s
Solution
Using v² = u² + 2gh, v = √(0 + 2 × 10 m/s² × 20 m) = √400 = 20 m/s.
Correct Answer: B — 20 m/s
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Q. If a 2 kg object is dropped from a height, what is its velocity just before hitting the ground (g = 10 m/s²)? (2023)
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A.
10 m/s
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B.
20 m/s
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C.
30 m/s
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D.
40 m/s
Solution
Using v = √(2gh), for h = 10 m, v = √(2 * 10 m/s² * 10 m) = √200 = 20 m/s.
Correct Answer: B — 20 m/s
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Q. If a 2 kg object is dropped from a height, what is its velocity just before hitting the ground? (g = 9.8 m/s², h = 20 m) (2023)
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A.
14 m/s
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B.
19.6 m/s
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C.
20 m/s
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D.
28 m/s
Solution
Using v² = u² + 2gh, where u = 0, we find v = √(2 * 9.8 * 20) = 19.6 m/s.
Correct Answer: B — 19.6 m/s
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Q. If a 5 kg object is moving with a velocity of 3 m/s, what is its momentum? (2023)
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A.
5 kg·m/s
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B.
10 kg·m/s
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C.
15 kg·m/s
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D.
20 kg·m/s
Solution
Momentum p = mv = 5 kg * 3 m/s = 15 kg·m/s.
Correct Answer: C — 15 kg·m/s
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Q. If a 5 kg object is subjected to a net force of 20 N, what is its acceleration? (2023)
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A.
2 m/s²
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B.
4 m/s²
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C.
5 m/s²
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D.
10 m/s²
Solution
Using F = ma, we find a = F/m = 20 N / 5 kg = 4 m/s².
Correct Answer: B — 4 m/s²
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Q. If a force of 10 N is applied to a mass of 2 kg, what is the acceleration of the mass? (2020)
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A.
2 m/s²
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B.
5 m/s²
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C.
10 m/s²
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D.
20 m/s²
Solution
Using F = ma, acceleration a = F/m = 10 N / 2 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. If a force of 15 N is applied to a 3 kg object, what is the net force acting on the object if it is already moving with a velocity of 5 m/s? (2022)
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A.
15 N
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B.
3 N
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C.
0 N
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D.
18 N
Solution
The net force is still 15 N as it does not depend on the velocity of the object.
Correct Answer: A — 15 N
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Q. If a force of 15 N is applied to a mass of 3 kg, what is the acceleration of the mass? (2023)
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A.
3 m/s²
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B.
4 m/s²
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C.
5 m/s²
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D.
6 m/s²
Solution
Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer: B — 4 m/s²
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Q. What is the net force acting on a 12 kg object moving with a constant velocity? (2023)
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A.
0 N
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B.
12 N
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C.
24 N
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D.
36 N
Solution
According to Newton's first law, if the object is moving with constant velocity, the net force is 0 N.
Correct Answer: A — 0 N
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Q. What is the net force acting on a 15 kg object moving with a constant velocity? (2021)
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A.
0 N
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B.
15 N
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C.
30 N
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D.
45 N
Solution
If the object is moving with constant velocity, net force is 0 N (Newton's first law).
Correct Answer: A — 0 N
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