Methyl iodide reacts the fastest in an SN2 reaction due to minimal steric hindrance and the good leaving ability of iodide.

This reaction is an electrophilic aromatic substitution where bromine acts as an electrophile.

The strong base facilitates the E2 elimination, resulting in the formation of 2-methylpropene.

The compound is a four-carbon chain with a chlorine substituent on the second carbon, making it 2-chlorobutane.

The compound with the formula C4H9Br is 1-bromobutane, as it is a straight-chain brominated alkane.

The reaction is a hydrogenation that converts 1-pentene to pentane, a saturated hydrocarbon.

The addition of HBr to ethene results in the formation of bromoethane through an electrophilic addition mechanism.

The reaction produces propyl thiocyanate through an SN2 mechanism, where the thiocyanate ion acts as a nucleophile.

The SN2 mechanism inverts the configuration at the chiral center, resulting in (S)-2-iodobutane.

The reaction of 2-bromobutane with sodium ethoxide is an E2 elimination reaction, leading to the formation of an alkene.

The reaction will proceed via the SN1 mechanism due to the tertiary carbon, which stabilizes the carbocation intermediate.

3-bromobutane is most likely to undergo an E1 reaction due to the stability of the tertiary carbocation formed during the reaction.

3-bromopentane undergoes elimination more readily due to the stability of the tertiary carbocation formed during the reaction.

2-bromobutane undergoes elimination (E2) to form an alkene, while 2-bromo-2-methylpropane does not due to steric hindrance.