Doubling both masses results in a fourfold increase in gravitational force, as it is directly proportional to the product of the masses.

According to Newton's law of gravitation, if the distance is halved, the force increases by a factor of 4 (F ∝ 1/r²).

Gravitational force is directly proportional to the product of the masses. Tripling one mass triples the force.

At a height equal to the radius of the Earth, the gravitational force becomes one-fourth of its value at the surface.

According to the inverse square law, if the distance is doubled, the force becomes 1/(2^2) = 1/4, or four times weaker.

If the distance is halved, the force becomes 1/(1/2)^2 = 4 times stronger.

Gravitational force F ∝ 1/r². If r is doubled, F becomes F/4.

If the Earth shrinks in size while maintaining its mass, the gravitational force at the surface would increase due to the decrease in radius.

If the radius is halved, the gravitational force increases by a factor of 4, since F = GM/R^2.

If the radius is halved, the gravitational acceleration would increase by a factor of 4 (g ∝ 1/R²).

The gravitational force at the surface is inversely proportional to the square of the radius. If the radius is halved, the force becomes four times stronger.

Using F = G * (m1 * m2) / r^2, F = (6.67 x 10^-11) * (6 x 10^24 * 1) / (6.4 x 10^6)^2 = 9.8 N.

Using g = G * M / R², where G = 6.67 x 10^-11 N m²/kg², M = 6 x 10^24 kg, and R = 6.4 x 10^6 m, we find g ≈ 9.8 m/s².

g = G * M / R² = (6.67 × 10^-11) * (6 × 10^24) / (6.4 × 10^6)² = 9.81 m/s²

The gravitational acceleration at the surface of the Earth is given by g = GM/R^2.

The gravitational acceleration at the surface of the Earth is given by g = GM/R^2.

Weight is proportional to mass; thus, if the Earth's mass doubles, the weight of an object on its surface also doubles.

If the mass of the Earth increases, the gravitational force experienced by an object on its surface would increase.

If the radius is halved, the gravitational acceleration becomes four times stronger, as g is inversely proportional to the square of the radius.

g ∝ 1/R². If R is halved, g becomes 4 times greater.

Weight is proportional to 1/r^2; if the radius doubles, the weight becomes four times less.

Gravitational acceleration is inversely proportional to the square of the radius. If the radius doubles, g becomes 1/(2^2) = 1/4 of the original value.

As the distance between two masses decreases, the gravitational force increases according to the inverse square law.

If the distance is halved, the force becomes 1/(1/2)^2 = 4 times stronger.

F = G * (m1 * m2) / r^2 = (6.67 x 10^-11) * (1 * 1) / (1^2) = 6.67 x 10^-11 N.

If the distance is halved, the gravitational force increases by a factor of four, as it is inversely proportional to the square of the distance.

F = G * (m1 * m2) / r² = (6.67 × 10^-11) * (3 * 4) / (1²) = 8.01 × 10^-11 N

The gravitational force is directly proportional to the product of the masses. If one mass is tripled, the force also triples.

The gravitational force is inversely proportional to the square of the distance. If the distance is tripled, the force becomes 1/(3^2) = 1/9 of the original force.

The gravitational force is directly proportional to the product of the masses. If one mass is tripled, the force also triples.