Newtons Law of Gravitation
Q. What happens to the gravitational force if the mass of one object is tripled?
A.
It becomes three times stronger
B.
It becomes six times stronger
C.
It remains the same
D.
It becomes nine times stronger
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Solution
The gravitational force is directly proportional to the product of the masses, so tripling one mass triples the force.
Correct Answer: A — It becomes three times stronger
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Q. What is the acceleration due to gravity at a height equal to the radius of the Earth?
A.
g/2
B.
g/3
C.
g/4
D.
g/5
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Solution
At height equal to radius, g' = g / (1 + h/R)² = g / (2)² = g/4.
Correct Answer: C — g/4
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Q. What is the effect of increasing the mass of both objects on the gravitational force between them?
A.
It decreases the force
B.
It increases the force
C.
It has no effect
D.
It depends on the distance
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Solution
Increasing the mass of either or both objects increases the gravitational force between them.
Correct Answer: B — It increases the force
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Q. What is the escape velocity from the surface of the Earth? (g = 9.8 m/s^2, R = 6.4 x 10^6 m)
A.
7.9 km/s
B.
11.2 km/s
C.
9.8 km/s
D.
5.0 km/s
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Solution
Escape velocity (v) = sqrt(2gR) = sqrt(2 * 9.8 * 6.4 x 10^6) ≈ 11.2 km/s.
Correct Answer: B — 11.2 km/s
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Q. What is the gravitational field strength at the surface of a planet with mass 6 x 10^24 kg and radius 6.4 x 10^6 m?
A.
9.8 N/kg
B.
6.67 N/kg
C.
3.2 N/kg
D.
12.5 N/kg
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Solution
g = GM/R² = (6.67 x 10^-11 * 6 x 10^24) / (6.4 x 10^6)² = 9.8 N/kg
Correct Answer: A — 9.8 N/kg
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Q. What is the gravitational force acting on a 10 kg mass at the surface of the Earth?
A.
98 N
B.
10 N
C.
100 N
D.
9.8 N
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Solution
F = mg = 10 kg * 9.8 m/s^2 = 98 N.
Correct Answer: A — 98 N
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Q. What is the gravitational force acting on a 10 kg object at the surface of the Earth?
A.
98 N
B.
100 N
C.
10 N
D.
9.8 N
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Solution
Using F = mg, where m = 10 kg and g = 9.8 m/s², F = 10 * 9.8 = 98 N.
Correct Answer: A — 98 N
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Q. What is the gravitational force acting on a 10 kg object on the surface of the Earth? (g = 9.8 m/s²)
A.
9.8 N
B.
19.6 N
C.
29.4 N
D.
39.2 N
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Solution
F = mg = 10 * 9.8 = 98 N
Correct Answer: B — 19.6 N
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Q. What is the gravitational force acting on a 70 kg person standing on the surface of the Earth? (g = 9.8 m/s²)
A.
686 N
B.
70 N
C.
9.8 N
D.
700 N
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Solution
Weight W = m * g = 70 kg * 9.8 m/s² = 686 N
Correct Answer: A — 686 N
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Q. What is the gravitational force between two 1 kg masses placed 1 m apart?
A.
6.67 × 10^-11 N
B.
6.67 × 10^-10 N
C.
6.67 × 10^-9 N
D.
6.67 × 10^-8 N
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Solution
F = G * (m1 * m2) / r² = (6.67 × 10^-11) * (1 * 1) / (1²) = 6.67 × 10^-11 N
Correct Answer: A — 6.67 × 10^-11 N
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Q. What is the gravitational force between two 1 kg masses separated by 1 meter?
A.
6.67 x 10^-11 N
B.
9.81 N
C.
1 N
D.
0 N
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Solution
Using F = G * (m1 * m2) / r^2, we find F = 6.67 x 10^-11 N for two 1 kg masses at 1 meter apart.
Correct Answer: A — 6.67 x 10^-11 N
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Q. What is the gravitational force between two 1 kg masses that are 1 m apart?
A.
6.67 x 10^-11 N
B.
6.67 x 10^-9 N
C.
6.67 x 10^-10 N
D.
6.67 x 10^-12 N
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Solution
Using F = G * (m1 * m2) / r^2, F = (6.67 x 10^-11) * (1 * 1) / (1^2) = 6.67 x 10^-11 N.
Correct Answer: A — 6.67 x 10^-11 N
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Q. What is the gravitational force between two 1 kg masses that are 1 meter apart?
A.
6.67 x 10^-11 N
B.
6.67 x 10^-9 N
C.
6.67 x 10^-10 N
D.
6.67 x 10^-12 N
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Solution
Using F = G * (m1 * m2) / r², F = (6.67 x 10^-11) * (1 * 1) / (1^2) = 6.67 x 10^-11 N.
Correct Answer: A — 6.67 x 10^-11 N
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Q. What is the gravitational force between two masses of 5 kg and 10 kg separated by a distance of 2 m? (G = 6.67 × 10^-11 N m²/kg²)
A.
1.67 × 10^-10 N
B.
1.67 × 10^-9 N
C.
1.67 × 10^-8 N
D.
1.67 × 10^-7 N
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Solution
F = G * (m1 * m2) / r² = (6.67 × 10^-11) * (5 * 10) / (2²) = 1.67 × 10^-10 N
Correct Answer: A — 1.67 × 10^-10 N
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Q. What is the gravitational force between two masses of 5 kg and 10 kg separated by a distance of 2 m?
A.
1.67 x 10^-10 N
B.
1.25 x 10^-9 N
C.
1.25 x 10^-10 N
D.
2.5 x 10^-10 N
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Solution
Using Newton's law of gravitation, F = G * (m1 * m2) / r^2, where G = 6.67 x 10^-11 N m^2/kg^2, m1 = 5 kg, m2 = 10 kg, and r = 2 m. F = (6.67 x 10^-11) * (5 * 10) / (2^2) = 1.25 x 10^-9 N.
Correct Answer: B — 1.25 x 10^-9 N
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Q. What is the gravitational force between two objects of mass 3 kg and 4 kg separated by a distance of 3 m?
A.
1.11 x 10^-10 N
B.
1.33 x 10^-10 N
C.
1.67 x 10^-10 N
D.
2.00 x 10^-10 N
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Solution
Using F = G * (m1 * m2) / r^2, F = (6.67 x 10^-11) * (3 * 4) / (3^2) = 1.33 x 10^-10 N.
Correct Answer: B — 1.33 x 10^-10 N
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Q. What is the gravitational force between two objects of masses 5 kg and 10 kg separated by a distance of 2 m?
A.
1.67 x 10^-10 N
B.
1.25 x 10^-9 N
C.
1.25 x 10^-10 N
D.
2.50 x 10^-10 N
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Solution
Using Newton's law of gravitation, F = G * (m1 * m2) / r^2, where G = 6.67 x 10^-11 N m^2/kg^2, m1 = 5 kg, m2 = 10 kg, r = 2 m. F = (6.67 x 10^-11) * (5 * 10) / (2^2) = 1.25 x 10^-9 N.
Correct Answer: B — 1.25 x 10^-9 N
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Q. What is the gravitational force between two objects of masses m1 and m2 separated by a distance r?
A.
F = G * (m1 * m2) / r^2
B.
F = G * (m1 + m2) / r^2
C.
F = G * (m1 * m2) * r^2
D.
F = G * (m1 - m2) / r
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Solution
The gravitational force is given by Newton's law of gravitation: F = G * (m1 * m2) / r^2.
Correct Answer: A — F = G * (m1 * m2) / r^2
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Q. What is the gravitational force experienced by a 1 kg mass at the surface of the Earth?
A.
9.81 N
B.
1 N
C.
0 N
D.
9.81 kg
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Solution
The gravitational force on a 1 kg mass at the surface of the Earth is equal to its weight, which is 9.81 N.
Correct Answer: A — 9.81 N
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Q. What is the gravitational force experienced by a 10 kg mass at the surface of the Earth?
A.
10 N
B.
98 N
C.
100 N
D.
0 N
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Solution
The weight (gravitational force) is calculated as F = m * g = 10 kg * 9.8 m/s^2 = 98 N.
Correct Answer: B — 98 N
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Q. What is the gravitational potential energy of a 2 kg mass at a height of 10 m?
A.
20 J
B.
15 J
C.
10 J
D.
5 J
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Solution
Gravitational potential energy (U) = mgh = 2 kg * 9.8 m/s^2 * 10 m = 196 J.
Correct Answer: A — 20 J
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Q. What is the gravitational potential energy of a 2 kg mass at a height of 5 m? (g = 9.8 m/s²)
A.
19.6 J
B.
39.2 J
C.
49 J
D.
9.8 J
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Solution
Potential Energy PE = m * g * h = 2 kg * 9.8 m/s² * 5 m = 98 J
Correct Answer: B — 39.2 J
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Q. What is the gravitational potential energy of a mass of 2 kg at a height of 10 m? (g = 9.8 m/s²)
A.
19.6 J
B.
39.2 J
C.
78.4 J
D.
98 J
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Solution
PE = mgh = 2 * 9.8 * 10 = 196 J
Correct Answer: B — 39.2 J
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Q. What is the gravitational potential energy of a mass of 2 kg at a height of 10 m above the ground? (g = 9.8 m/s^2)
A.
196 J
B.
98 J
C.
20 J
D.
10 J
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Solution
Gravitational potential energy (U) = mgh = 2 kg * 9.8 m/s^2 * 10 m = 196 J.
Correct Answer: A — 196 J
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Q. What is the gravitational potential energy of a mass of 2 kg at a height of 10 m in a gravitational field of 9.8 m/s²?
A.
19.6 J
B.
39.2 J
C.
78.4 J
D.
98 J
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Solution
Gravitational potential energy (U) = mgh = 2 kg * 9.8 m/s² * 10 m = 196 J.
Correct Answer: B — 39.2 J
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Q. What is the gravitational potential energy of two masses m1 and m2 separated by a distance r?
A.
-G * (m1 * m2) / r
B.
G * (m1 * m2) / r
C.
G * (m1 + m2) / r
D.
-G * (m1 + m2) / r
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Solution
The gravitational potential energy is given by U = -G * (m1 * m2) / r.
Correct Answer: A — -G * (m1 * m2) / r
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Q. What is the gravitational potential energy U of two masses m1 and m2 separated by a distance r?
A.
U = -G * (m1 * m2) / r
B.
U = G * (m1 * m2) / r
C.
U = (m1 + m2) * r
D.
U = G * (m1 - m2) / r
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Solution
The gravitational potential energy is given by U = -G * (m1 * m2) / r.
Correct Answer: A — U = -G * (m1 * m2) / r
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Q. What is the value of gravitational acceleration at the surface of the Earth?
A.
9.8 m/s^2
B.
10 m/s^2
C.
9.81 m/s^2
D.
8.9 m/s^2
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Solution
The standard value of gravitational acceleration at the surface of the Earth is approximately 9.81 m/s^2.
Correct Answer: C — 9.81 m/s^2
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Q. What is the value of the gravitational constant G?
A.
6.67 x 10^-11 N(m/kg)^2
B.
9.81 m/s^2
C.
3.00 x 10^8 m/s
D.
1.60 x 10^-19 C
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Solution
The gravitational constant G is approximately 6.67 x 10^-11 N(m/kg)^2.
Correct Answer: A — 6.67 x 10^-11 N(m/kg)^2
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Q. What is the weight of a 10 kg object on the surface of the Earth? (g = 9.8 m/s²)
A.
9.8 N
B.
19.6 N
C.
98 N
D.
0.98 N
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Solution
Weight W = m * g = 10 kg * 9.8 m/s² = 98 N
Correct Answer: B — 19.6 N
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