The maximum height occurs at t = -b/(2a) = -64/(2*-16) = 2. h(2) = -16(2^2) + 64(2) + 48 = 80.

The maximum number of bright fringes is given by the formula n = d/λ. Here, n = 0.1 mm / 500 nm = 200, which means 20 bright fringes can be observed on either side of the central maximum.

The maximum number of bright fringes depends on the wavelength and the slit separation, as it determines how many integer multiples of the wavelength fit within the observable range.

The d subshell can hold a maximum of 10 electrons.

The f-subshell can hold a maximum of 14 electrons.

The maximum number of electrons in a shell is given by the formula 2n². For n=3, it is 2(3)² = 18.

The maximum number of electrons in a shell is given by the formula 2n². For n=3, it is 2(3)² = 18.

Phosphorus can exhibit a maximum oxidation state of +5 in compounds like PCl5.

The maximum profit occurs at x = -b/(2a) = 10/2 = 5. P(5) = -5^2 + 10*5 - 16 = 9.

The vertex occurs at x = 2. f(2) = -2^2 + 4(2) + 1 = 5.

The vertex occurs at x = 3. f(3) = -9 + 18 - 8 = 1.

Using the distance formula from a point to a line, the minimum distance is calculated to be 2 units.

The minimum energy required is equal to the work function, which is 2 eV.

For constructive interference in a soap bubble, the minimum thickness should be λ/4, accounting for the phase change upon reflection.

The vertex occurs at x = 2. f(2) = 3(2^2) - 12(2) + 12 = 0.

The vertex occurs at x = 2. f(2) = -5.

The vertex occurs at x = 2. f(2) = 3(2^2) - 12(2) + 9 = 0.

The vertex form gives the minimum at x = 2. f(2) = 2.

The vertex occurs at x = 2. f(2) = 2.

The vertex form gives the minimum at x = 2. f(2) = 2, thus minimum value is 3.

The vertex form gives the minimum at x = 3. f(3) = 3^2 - 6(3) + 10 = 1.

The vertex gives the minimum at x = 2. f(2) = 4(2^2) - 16(2) + 20 = 4.

The vertex occurs at x = 2. f(2) = 4(2^2) - 16(2) + 20 = 4.

The modulus is calculated as √(3^2 + 4^2) = √(9 + 16) = √25 = 5.

Molality (m) = moles of solute / kg of solvent = 10 moles / 5 kg = 2 m.

The molar mass of water is calculated as follows: H (1 g/mol) x 2 + O (16 g/mol) = 2 + 16 = 18 g/mol.

Molarity (M) = moles of solute / liters of solution = 5 moles / 2 L = 2.5 M.

Molarity (M) = moles of solute / liters of solution. Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mol. Therefore, M = 1 mol / 1 L = 1 M.

Molarity (M) = moles of solute / liters of solution. Moles of NaCl = 5 g / 58.5 g/mol = 0.0855 moles. Volume of solution = 250 mL = 0.250 L. M = 0.0855 moles / 0.250 L = 0.342 M, approximately 0.34 M.

The molecular formula of Benzoic acid is C7H6O2.