What is the minimum value of f(x) = 3x^2 - 12x + 12? (2021)

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What is the minimum value of f(x) = 3x^2 - 12x + 12? (2021)
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Questions & Step-by-step Solutions

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Q: What is the minimum value of f(x) = 3x^2 - 12x + 12? (2021)
Solution: The vertex occurs at x = 2. f(2) = 3(2^2) - 12(2) + 12 = 0.
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