An OR gate outputs 1 if at least one input is 1. Since both inputs are 0, the output is 0.

According to Kirchhoff's current law, the total current entering a junction equals the total current leaving it. Therefore, total current = 2 A + 3 A = 5 A.

The current through the shared resistor is the difference of the currents in the loops, so 5 A - 3 A = 2 A.

Using the formula for resistors in parallel, 1/R_eq = 1/4 + 1/6, we find R_eq = 2.4 ohms.

First, find the equivalent resistance: 1/R_eq = 1/4 + 1/12 = 1/3. R_eq = 3Ω. Then, I = V/R = 24V / 3Ω = 8A.

Total current I = V / Req; Req = 1/(1/6 + 1/3) = 2Ω; I = 12V / 2Ω = 6A.

Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.

Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.

First, find the equivalent resistance: 1/R_eq = 1/6 + 1/3 = 1/2, R_eq = 2Ω. Then, I = V/R = 12V/2Ω = 6A.

The total resistance in series is R_total = R1 + R2 = 4Ω + 6Ω = 10Ω.

Using the formula for resistors in series, R_total = R1 + R2, we have 12 = 4 + R2, thus R2 = 12 - 4 = 8 ohms.

Using the voltage divider rule, V1 = (R1 / (R1 + R2)) * Vtotal = (4 / (4 + 6)) * 12 = 4.8V.

Using the voltage divider rule, V1 = (R1 / (R1 + R2)) * Vtotal = (4 / (4 + 6)) * 12 = 4.8V.

The time constant (τ) of an RC circuit is given by τ = R * C.

When a capacitor is fully charged, the voltage across it is equal to the voltage of the source it was connected to.

Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which means power quadruples.

According to Ohm's law, I = V/R. If R is doubled, I will be halved.

According to Ohm's law, I = V/R. If R is halved, I will double.

Using Ohm's law, R = V/I = 12V / 3A = 4 ohms.

According to Ohm's law, if voltage is doubled and resistance remains constant, current also doubles.

According to Ohm's law, if voltage is halved while resistance remains constant, current also halves.

Initial current I1 = 5V / 5Ω = 1 A; Final current I2 = 15V / 5Ω = 3 A; Change in current = I2 - I1 = 3 A - 1 A = 2 A.

According to Ohm's Law, if voltage increases and resistance remains constant, the current will increase.

According to Ohm's Law, if the voltage (V) increases and resistance (R) remains constant, the current (I) increases.

The total capacitance C_total in parallel is the sum of individual capacitances: C_total = C1 + C2 = 2μF + 3μF = 5μF.

In parallel, the total capacitance is the sum: C_total = C1 + C2 = 3μF + 6μF = 9μF.

For capacitors in parallel, the total capacitance is the sum of the individual capacitances: C_total = C1 + C2 = 4μF + 6μF = 10μF.

The magnetic field B at the center of a circular loop of radius R carrying current I is given by B = μ₀I/(2R).

The magnetic field at the center of a circular loop of radius R carrying current I is given by B = (μ₀I)/(2R).

The line integral of B around the path is equal to μ₀I by Ampere's Law.