The depletion region is the area in a diode where no current flows under reverse bias.

Using the lens maker's formula, f = (R1 * R2) / (n - 1) * (1/R1 - 1/R2), we find f = 12 cm.

Fringe separation is directly proportional to the distance from the slits to the screen; increasing this distance increases fringe separation.

Fringe width β = λD/d = (600 x 10^-9 m)(1 m)/(0.2 x 10^-3 m) = 0.003 m = 0.6 mm.

Distance between fringes = β = λD/d. For first and second bright fringes, the distance is 2β.

Using the formula for fringe separation, y = (λD)/d, we find y = (500 x 10^-9 m * 2 m) / (0.5 x 10^-3 m) = 2 cm.

Fringe width (β) is given by β = λD/d, where d is the distance between the slits. If d is doubled, β is halved.

Fringe width (β) is inversely proportional to the distance between the slits (d). If d is doubled, β is halved.

Fringe width (β) is given by β = λD/d, where d is the distance between the slits. If d is doubled, β becomes β/2, hence the fringe width halves.

The fringe separation is inversely proportional to the distance between the slits; thus, if the distance is doubled, the fringe separation halves.

The fringe separation is inversely proportional to the distance between the slits; halving the distance doubles the fringe separation.

Increasing the distance between the slits (d) causes the fringe width (β) to decrease, making the fringes narrower.

Increasing the distance between the slits decreases the fringe width, which can lead to more visible fringes within a given distance on the screen.

Increasing the distance to the screen increases the fringe width, as fringe width is proportional to the distance from the slits.

Fringe separation is directly proportional to the distance from the slits to the screen (D), so increasing D increases the fringe separation.

Increasing the distance to the screen increases the fringe width, as fringe width is proportional to the distance from the slits.

At the first minimum, the intensity is 0 due to destructive interference.

Fringe separation is directly proportional to the distance from the slits to the screen (D), hence it increases.

Moving the screen further away increases the distance (D) in the fringe width formula, causing the fringes to become wider.

Moving the screen further away increases the fringe spacing, as fringe width is directly proportional to the distance from the slits.

Fringe width β = λD/d = (600 x 10^-9 m)(1 m)/(0.5 x 10^-3 m) = 0.12 mm.

The distance between the fringes increases with an increase in wavelength, as fringe separation is directly proportional to wavelength.

Increasing the distance between the slits decreases the fringe width, making the pattern narrower.

Increasing the distance between the slits increases the fringe width because the angle of diffraction increases.

In a dynamic equilibrium, the rates of the forward and reverse reactions are equal, but the concentrations of reactants and products may not be equal.

If there are at least 2 boys, the possible combinations are (2B, 2G), (3B, 1G), (4B). Thus, the probability of having at least one girl is 3/4.

The total outcomes for 3 children are 8. The outcomes with at least one boy are 7. The outcomes with at least one girl and one boy are 6. Thus, P(Girl|Boy) = 6/7 ≈ 0.857.

Using the first-order rate equation, k = (ln[A₀] - ln[A]) / t. Here, k = (ln(0.8) - ln(0.2)) / 20 = 0.0347 min⁻¹.

In a first-order reaction, the half-life is independent of the concentration of the reactant, so it remains the same.

t₁/₂ = 0.693 / k = 0.693 / 0.03 = 23.1 min.