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Q. In a simple harmonic motion, if the mass is increased, what happens to the period?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Depends on the spring constant
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Solution
The period T is given by T = 2π√(m/k). If m increases, T increases.
Correct Answer: A — Increases
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Q. In a simple harmonic motion, the maximum displacement from the mean position is called?
A.
Amplitude
B.
Frequency
C.
Wavelength
D.
Period
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Solution
The maximum displacement from the mean position in simple harmonic motion is called Amplitude.
Correct Answer: A — Amplitude
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Q. In a simple harmonic motion, the maximum displacement from the mean position is called what?
A.
Amplitude
B.
Frequency
C.
Wavelength
D.
Period
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Solution
The maximum displacement from the mean position in simple harmonic motion is called the amplitude.
Correct Answer: A — Amplitude
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Q. In a simple harmonic motion, the phase difference between displacement and acceleration is:
A.
0 degrees
B.
90 degrees
C.
180 degrees
D.
270 degrees
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Solution
Acceleration is always opposite to displacement in SHM, hence 180 degrees.
Correct Answer: C — 180 degrees
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Q. In a simple harmonic motion, the restoring force is directly proportional to what?
A.
Displacement
B.
Velocity
C.
Acceleration
D.
Mass
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Solution
In SHM, the restoring force is directly proportional to the displacement from the mean position.
Correct Answer: A — Displacement
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Q. In a simple harmonic motion, the restoring force is directly proportional to which of the following?
A.
Displacement
B.
Velocity
C.
Acceleration
D.
Mass
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Solution
In simple harmonic motion, the restoring force is directly proportional to the displacement from the mean position.
Correct Answer: A — Displacement
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Q. In a simple harmonic motion, the velocity is maximum at which point?
A.
Mean position
B.
Amplitude
C.
Equilibrium position
D.
None of the above
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Solution
The velocity is maximum at the mean position where the displacement is zero.
Correct Answer: A — Mean position
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Q. In a simple harmonic oscillator, if the maximum speed is 4 m/s and the amplitude is 2 m, what is the angular frequency?
A.
2 rad/s
B.
4 rad/s
C.
6 rad/s
D.
8 rad/s
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Solution
Maximum speed (v_max) = ωA. Thus, ω = v_max/A = 4/2 = 2 rad/s.
Correct Answer: B — 4 rad/s
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Q. In a single-slit diffraction experiment, what happens to the width of the central maximum as the slit width decreases?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes zero
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Solution
As the slit width decreases, the central maximum becomes wider due to increased diffraction.
Correct Answer: A — It increases
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Q. In a single-slit diffraction pattern, how does the intensity of the central maximum compare to the first minimum?
A.
Equal
B.
Twice
C.
Four times
D.
Half
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Solution
The intensity of the central maximum is four times that of the first minimum in a single-slit diffraction pattern.
Correct Answer: C — Four times
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Q. In a single-slit diffraction pattern, how does the intensity of the first minimum compare to the intensity of the central maximum?
A.
It is equal
B.
It is half
C.
It is zero
D.
It is one-fourth
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Solution
The intensity at the first minimum is zero, while the central maximum has maximum intensity.
Correct Answer: C — It is zero
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Q. In a single-slit diffraction pattern, the width of the central maximum is 4 mm. If the slit width is halved, what will be the new width of the central maximum?
A.
2 mm
B.
4 mm
C.
8 mm
D.
16 mm
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Solution
The width of the central maximum is inversely proportional to the slit width. Halving the slit width doubles the width of the central maximum to 8 mm.
Correct Answer: C — 8 mm
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Q. In a single-slit diffraction pattern, what is the angle for the first minimum if the slit width is 0.5 mm and the wavelength of light is 600 nm?
A.
30°
B.
60°
C.
45°
D.
15°
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Solution
For single-slit diffraction, the first minimum occurs at sin θ = λ/a. Here, sin θ = 600 x 10^-9 m / 0.5 x 10^-3 m = 0.0012, θ ≈ 0.0698 rad ≈ 4°.
Correct Answer: C — 45°
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Q. In a single-slit diffraction pattern, what is the angle for the first minimum?
A.
sin(θ) = λ/a
B.
sin(θ) = 2λ/a
C.
sin(θ) = 3λ/a
D.
sin(θ) = 0
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Solution
The angle for the first minimum in single-slit diffraction is given by sin(θ) = λ/a, where a is the slit width.
Correct Answer: A — sin(θ) = λ/a
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Q. In a single-slit diffraction pattern, what is the angular position of the first minimum?
A.
sin(θ) = λ/a
B.
sin(θ) = 2λ/a
C.
sin(θ) = 3λ/a
D.
sin(θ) = 0
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Solution
The first minimum in a single-slit diffraction pattern occurs at sin(θ) = λ/a, where a is the width of the slit.
Correct Answer: A — sin(θ) = λ/a
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Q. In a single-slit diffraction pattern, what is the angular width of the central maximum if the slit width is 0.5 mm and the wavelength of light is 500 nm?
A.
0.1 rad
B.
0.2 rad
C.
0.3 rad
D.
0.4 rad
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Solution
Angular width = 2λ/a. Here, a = 0.5 mm = 500 μm, so angular width = 2 * 500 nm / 500 μm = 0.002 rad = 0.2 rad.
Correct Answer: B — 0.2 rad
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Q. In a single-slit diffraction pattern, where is the first minimum located?
A.
At θ = 0
B.
At θ = λ/a
C.
At θ = a/λ
D.
At θ = 2λ/a
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Solution
The first minimum in a single-slit diffraction pattern occurs at θ = λ/a, where a is the width of the slit.
Correct Answer: B — At θ = λ/a
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Q. In a situation where two parallel wires carry currents in the same direction, what is the nature of the force between them?
A.
Attractive
B.
Repulsive
C.
No force
D.
Depends on the distance
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Solution
Two parallel wires carrying currents in the same direction experience an attractive force between them.
Correct Answer: A — Attractive
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Q. In a solenoid carrying current, what is the direction of the magnetic field inside the solenoid according to Ampere's Law?
A.
From south to north
B.
From north to south
C.
Perpendicular to the axis
D.
Radially outward
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Solution
The magnetic field inside a solenoid is directed from the north pole to the south pole of the solenoid.
Correct Answer: B — From north to south
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Q. In a solenoid carrying current, what is the direction of the magnetic field inside the solenoid?
A.
Perpendicular to the axis of the solenoid
B.
Along the axis of the solenoid
C.
Radially outward from the solenoid
D.
Zero inside the solenoid
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Solution
The magnetic field inside a solenoid is uniform and directed along the axis of the solenoid.
Correct Answer: B — Along the axis of the solenoid
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Q. In a solenoid carrying current, what is the magnetic field inside the solenoid?
A.
Zero
B.
μ₀nI
C.
μ₀I
D.
μ₀I/(2n)
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Solution
The magnetic field inside a solenoid carrying current is given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer: B — μ₀nI
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Q. In a solenoid, if the number of turns per unit length is doubled, what happens to the magnetic field inside the solenoid?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
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Solution
The magnetic field inside a solenoid is directly proportional to the number of turns per unit length, so it doubles.
Correct Answer: A — It doubles
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Q. In a solenoid, what factor does NOT affect the strength of the magnetic field inside it?
A.
Number of turns per unit length
B.
Current through the solenoid
C.
Length of the solenoid
D.
Permeability of the core material
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Solution
The length of the solenoid does not affect the strength of the magnetic field inside it; it is determined by the number of turns per unit length, the current, and the permeability of the core material.
Correct Answer: C — Length of the solenoid
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Q. In a solenoid, what is the effect of increasing the number of turns per unit length on the magnetic field strength?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
Increasing the number of turns per unit length in a solenoid increases the magnetic field strength.
Correct Answer: A — Increases
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Q. In a solenoid, what is the expression for the magnetic field inside it when it carries a current I?
A.
B = μ₀nI
B.
B = μ₀I/2πr
C.
B = μ₀I/4πr²
D.
B = μ₀I/n
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Solution
Inside a long solenoid, the magnetic field is given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer: A — B = μ₀nI
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Q. In a solution of 1 mol of solute in 9 mol of solvent, what is the mole fraction of the solute?
A.
0.1
B.
0.2
C.
0.5
D.
0.9
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Solution
Mole fraction of solute = moles of solute / (moles of solute + moles of solvent) = 1 / (1 + 9) = 0.1.
Correct Answer: A — 0.1
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Q. In a solution of 1 mole of solute B in 3 moles of solvent A, what is the mole fraction of solvent A?
A.
0.25
B.
0.75
C.
0.33
D.
0.67
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Solution
Mole fraction of A = moles of A / (moles of A + moles of B) = 3 / (3 + 1) = 0.75.
Correct Answer: B — 0.75
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Q. In a solution of a non-volatile solute, how does the addition of solute affect the boiling point of the solvent?
A.
It decreases the boiling point
B.
It has no effect on the boiling point
C.
It increases the boiling point
D.
It depends on the nature of the solute
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Solution
The addition of a non-volatile solute raises the boiling point of the solvent, a phenomenon known as boiling point elevation.
Correct Answer: C — It increases the boiling point
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Q. In a solution of a non-volatile solute, how does the vapor pressure compare to that of the pure solvent?
A.
Higher than the pure solvent
B.
Lower than the pure solvent
C.
Equal to the pure solvent
D.
Depends on the temperature
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Solution
The presence of a non-volatile solute lowers the vapor pressure of the solvent compared to that of the pure solvent.
Correct Answer: B — Lower than the pure solvent
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Q. In a solution of two volatile components A and B, if the mole fraction of A is 0.6, what is the vapor pressure of the solution if the vapor pressure of pure A is 100 mmHg and that of pure B is 50 mmHg?
A.
80 mmHg
B.
90 mmHg
C.
70 mmHg
D.
60 mmHg
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Solution
Using Raoult's Law, the vapor pressure of the solution is P_total = (0.6 * 100) + (0.4 * 50) = 60 + 20 = 80 mmHg.
Correct Answer: B — 90 mmHg
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