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In a simple harmonic oscillator, if the maximum speed is 4 m/s and the amplitude
In a simple harmonic oscillator, if the maximum speed is 4 m/s and the amplitude is 2 m, what is the angular frequency?
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Practice Questions
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Q1
In a simple harmonic oscillator, if the maximum speed is 4 m/s and the amplitude is 2 m, what is the angular frequency?
2 rad/s
4 rad/s
6 rad/s
8 rad/s
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Maximum speed (v_max) = ωA. Thus, ω = v_max/A = 4/2 = 2 rad/s.
Questions & Step-by-step Solutions
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Q
Q: In a simple harmonic oscillator, if the maximum speed is 4 m/s and the amplitude is 2 m, what is the angular frequency?
Solution:
Maximum speed (v_max) = ωA. Thus, ω = v_max/A = 4/2 = 2 rad/s.
Steps: 6
Show Steps
Step 1: Identify the maximum speed (v_max) given in the problem, which is 4 m/s.
Step 2: Identify the amplitude (A) given in the problem, which is 2 m.
Step 3: Recall the formula for maximum speed in a simple harmonic oscillator, which is v_max = ωA, where ω is the angular frequency.
Step 4: Rearrange the formula to solve for angular frequency (ω): ω = v_max / A.
Step 5: Substitute the values into the formula: ω = 4 m/s / 2 m.
Step 6: Calculate the result: ω = 2 rad/s.
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