Current Electricity
Q. What is the potential difference across a 10Ω resistor if a current of 2A flows through it?
A.
5V
B.
10V
C.
20V
D.
15V
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Solution
Using Ohm's Law, V = I * R = 2A * 10Ω = 20V.
Correct Answer: C — 20V
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Q. What is the potential difference across a 10Ω resistor if a current of 4A flows through it?
A.
20V
B.
40V
C.
10V
D.
30V
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Solution
Using Ohm's Law, V = I * R = 4A * 10Ω = 40V.
Correct Answer: A — 20V
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Q. What is the potential difference across the galvanometer in a balanced Wheatstone bridge?
A.
Zero
B.
Equal to the supply voltage
C.
Depends on the resistances
D.
Half of the supply voltage
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Solution
In a balanced Wheatstone bridge, the potential difference across the galvanometer is zero, indicating no current flows through it.
Correct Answer: A — Zero
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Q. What is the power consumed by a 10 ohm resistor when a current of 2 A flows through it?
A.
20 W
B.
40 W
C.
10 W
D.
5 W
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Solution
Power P = I^2 * R = (2 A)^2 * 10Ω = 4 * 10 = 40 W.
Correct Answer: B — 40 W
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Q. What is the power consumed by a 10 ohm resistor when a current of 3 A flows through it?
A.
30 W
B.
90 W
C.
60 W
D.
15 W
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Solution
Power P = I^2 * R = (3 A)^2 * 10 ohms = 9 * 10 = 90 W.
Correct Answer: B — 90 W
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Q. What is the power consumed by a 10Ω resistor when a current of 2A flows through it?
A.
20W
B.
40W
C.
10W
D.
5W
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Solution
Power P = I^2 * R = (2A)^2 * 10Ω = 4A^2 * 10Ω = 40W.
Correct Answer: A — 20W
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Q. What is the power consumed by a 12 V battery supplying a current of 2 A?
A.
24 W
B.
12 W
C.
6 W
D.
48 W
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Solution
Power is given by P = V * I = 12 V * 2 A = 24 W.
Correct Answer: A — 24 W
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Q. What is the power consumed by a 5 ohm resistor carrying a current of 3 A?
A.
15 W
B.
9 W
C.
5 W
D.
3 W
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Solution
Power P = I^2 * R = (3 A)^2 * 5 ohms = 9 * 5 = 45 W.
Correct Answer: A — 15 W
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Q. What is the power consumed by a 5 ohm resistor when a current of 2A flows through it?
A.
10W
B.
20W
C.
5W
D.
15W
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Solution
Power P = I^2 * R = (2A)^2 * 5 ohms = 4 * 5 = 20W.
Correct Answer: B — 20W
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Q. What is the power consumed by a 5 ohm resistor when a current of 3 A flows through it?
A.
15 W
B.
9 W
C.
5 W
D.
3 W
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Solution
Power P = I^2 * R = (3 A)^2 * 5 ohms = 9 * 5 = 45 W.
Correct Answer: A — 15 W
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Q. What is the power dissipated in a 10Ω resistor carrying a current of 2A?
A.
20W
B.
30W
C.
40W
D.
50W
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Solution
Power P = I^2 * R = (2A)^2 * 10Ω = 4 * 10 = 40W.
Correct Answer: A — 20W
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Q. What is the power dissipated in a 4 ohm resistor carrying a current of 3 A?
A.
12 W
B.
9 W
C.
6 W
D.
3 W
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Solution
Using the power formula P = I^2 * R, we have P = (3 A)^2 * 4 ohms = 9 * 4 = 36 W.
Correct Answer: A — 12 W
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Q. What is the power dissipated in a resistor of 10 ohms carrying a current of 2 A?
A.
20 W
B.
10 W
C.
5 W
D.
40 W
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Solution
Using the power formula P = I^2 * R, we have P = (2 A)^2 * 10 ohms = 4 * 10 = 40 W.
Correct Answer: A — 20 W
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Q. What is the power dissipated in a resistor of 5Ω carrying a current of 2A?
A.
5W
B.
10W
C.
20W
D.
40W
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Solution
Power is given by P = I^2 * R = (2A)^2 * 5Ω = 4A^2 * 5Ω = 20W.
Correct Answer: B — 10W
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Q. What is the power dissipated in a resistor of 5Ω carrying a current of 3A?
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Solution
Power P = I^2 * R = (3A)^2 * 5Ω = 9A^2 * 5Ω = 45W.
Correct Answer: A — 15W
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Q. What is the power dissipated in a resistor of 8Ω when a current of 2A flows through it?
A.
4W
B.
8W
C.
16W
D.
32W
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Solution
Power P = I^2 * R = (2A)^2 * 8Ω = 4A^2 * 8Ω = 32W.
Correct Answer: C — 16W
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Q. What is the primary use of a Wheatstone bridge in practical applications?
A.
To measure voltage
B.
To measure current
C.
To measure resistance
D.
To measure power
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Solution
The primary use of a Wheatstone bridge is to measure unknown resistances by balancing it against known resistances.
Correct Answer: C — To measure resistance
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Q. What is the principle behind a potentiometer?
A.
It measures current in a circuit
B.
It measures voltage by balancing it against a known voltage
C.
It measures resistance directly
D.
It measures power in a circuit
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Solution
A potentiometer measures voltage by balancing it against a known voltage, allowing for accurate voltage measurements without drawing current from the circuit.
Correct Answer: B — It measures voltage by balancing it against a known voltage
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Q. What is the principle of a potentiometer?
A.
It measures current in a circuit.
B.
It measures voltage by balancing it against a known voltage.
C.
It measures resistance directly.
D.
It measures power in a circuit.
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Solution
A potentiometer measures voltage by balancing it against a known voltage, allowing for accurate voltage measurements.
Correct Answer: B — It measures voltage by balancing it against a known voltage.
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Q. What is the purpose of a galvanometer in a Wheatstone bridge?
A.
To measure voltage
B.
To measure current
C.
To detect the balance condition
D.
To provide power
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Solution
A galvanometer is used to detect the balance condition in a Wheatstone bridge by indicating zero current when balanced.
Correct Answer: C — To detect the balance condition
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Q. What is the purpose of the galvanometer in a Wheatstone bridge?
A.
To measure voltage
B.
To measure current
C.
To detect the balance condition
D.
To provide power
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Solution
The galvanometer is used to detect the balance condition by indicating the current flow.
Correct Answer: C — To detect the balance condition
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Q. What is the relationship between voltage, current, and resistance according to Ohm's Law?
A.
V = I * R
B.
V = I / R
C.
V = R / I
D.
V = I + R
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Solution
Ohm's Law states that the voltage (V) across a conductor is directly proportional to the current (I) flowing through it, with resistance (R) as the proportionality constant: V = I * R.
Correct Answer: A — V = I * R
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Q. What is the relationship between voltage, current, and resistance in a circuit according to Ohm's Law?
A.
V = I + R
B.
V = I - R
C.
V = I * R
D.
V = I / R
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Solution
According to Ohm's Law, the relationship is given by V = I * R.
Correct Answer: C — V = I * R
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Q. What is the resistivity of a material if a 5 m long wire with a cross-sectional area of 1 mm² has a resistance of 10 Ω?
A.
2 x 10^-6 Ω·m
B.
5 x 10^-6 Ω·m
C.
1 x 10^-5 Ω·m
D.
2 x 10^-5 Ω·m
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Solution
Resistivity ρ = R * (A / L) = 10 * (1 x 10^-6 / 5) = 2 x 10^-5 Ω·m.
Correct Answer: C — 1 x 10^-5 Ω·m
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Q. What is the resistivity of a material if a wire of length 2 m and cross-sectional area 1 mm² has a resistance of 4 ohms?
A.
2 x 10^-6 Ω·m
B.
4 x 10^-6 Ω·m
C.
8 x 10^-6 Ω·m
D.
1 x 10^-6 Ω·m
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Solution
Resistivity (ρ) = R * (A / L) = 4 * (1 x 10^-6 / 2) = 4 x 10^-6 Ω·m.
Correct Answer: B — 4 x 10^-6 Ω·m
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Q. What is the role of a fuse in an electrical circuit?
A.
To increase current
B.
To decrease voltage
C.
To protect against overload
D.
To store energy
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Solution
A fuse is designed to protect the circuit by breaking the connection when the current exceeds a certain limit.
Correct Answer: C — To protect against overload
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Q. What is the role of the galvanometer in a potentiometer circuit?
A.
To measure current
B.
To measure resistance
C.
To indicate the balance point
D.
To provide a reference voltage
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Solution
The galvanometer indicates the balance point in a potentiometer circuit, showing when the potential difference across the wire equals the unknown voltage.
Correct Answer: C — To indicate the balance point
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Q. What is the role of the galvanometer in a Wheatstone bridge?
A.
To measure voltage
B.
To measure current
C.
To detect balance
D.
To provide power
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Solution
The galvanometer is used to detect whether the bridge is balanced or unbalanced.
Correct Answer: C — To detect balance
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Q. What is the role of the jockey in a potentiometer setup?
A.
To connect the circuit
B.
To measure current
C.
To find the balance point
D.
To provide a fixed voltage
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Solution
The jockey is used to find the balance point in the potentiometer setup by sliding along the wire.
Correct Answer: C — To find the balance point
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Q. What is the role of the jockey in a potentiometer?
A.
To measure current
B.
To connect the circuit
C.
To find the null point
D.
To provide a reference voltage
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Solution
The jockey is used to find the null point where the potential difference is balanced, indicating the measurement of the unknown voltage.
Correct Answer: C — To find the null point
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