Q. Which of the following complexes is an example of a bidentate ligand?
-
A.
[Cu(NH3)4]SO4
-
B.
[Fe(CN)6]3-
-
C.
[Ni(en)3]Cl2
-
D.
[AgCl2]-
Solution
Ethylenediamine (en) is a bidentate ligand as it can form two bonds with the metal ion.
Correct Answer: C — [Ni(en)3]Cl2
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Q. Which of the following complexes is expected to be diamagnetic?
-
A.
[Fe(H2O)6]3+
-
B.
[Cu(NH3)4]2+
-
C.
[Co(NH3)6]3+
-
D.
[Ni(CO)4]
Solution
[Ni(CO)4] is diamagnetic because all electrons are paired in the presence of the strong field ligand CO.
Correct Answer: D — [Ni(CO)4]
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Q. Which of the following complexes is paramagnetic?
-
A.
[Fe(CN)6]3-
-
B.
[Co(NH3)6]3+
-
C.
[CuCl4]2-
-
D.
[MnO4]-
Solution
[Co(NH3)6]3+ has unpaired electrons and is therefore paramagnetic.
Correct Answer: B — [Co(NH3)6]3+
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Q. Which of the following compounds can act as a reducing agent?
-
A.
H2O2
-
B.
Cl2
-
C.
Na
-
D.
O2
Solution
Sodium (Na) can act as a reducing agent as it readily donates electrons.
Correct Answer: C — Na
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Q. Which of the following compounds can act as an oxidizing agent?
-
A.
NaCl
-
B.
H2O
-
C.
KMnO4
-
D.
C6H12O6
Solution
KMnO4 is a strong oxidizing agent due to the presence of Mn in a high oxidation state.
Correct Answer: C — KMnO4
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Q. Which of the following compounds can be classified as a ketone?
-
A.
C3H6O
-
B.
C2H4O
-
C.
C4H8O
-
D.
C5H10O
Solution
C3H6O (acetone) is a ketone, characterized by the carbonyl group (C=O) between two carbon atoms.
Correct Answer: A — C3H6O
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Q. Which of the following compounds can be distinguished from aldehydes using Tollen's reagent?
-
A.
Acetone
-
B.
Formaldehyde
-
C.
Benzaldehyde
-
D.
Propionaldehyde
Solution
Tollen's reagent can oxidize aldehydes but not ketones. Acetone is a ketone and will not react.
Correct Answer: A — Acetone
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Q. Which of the following compounds can be formed by the decarboxylation of a carboxylic acid?
-
A.
Alkane
-
B.
Alkene
-
C.
Alkyne
-
D.
Aldehyde
Solution
Decarboxylation of a carboxylic acid typically yields an alkane.
Correct Answer: A — Alkane
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Q. Which of the following compounds can be formed by the decarboxylation of sodium acetate?
-
A.
Methane
-
B.
Ethane
-
C.
Propane
-
D.
Butane
Solution
Decarboxylation of sodium acetate yields methane.
Correct Answer: A — Methane
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Q. Which of the following compounds can be formed by the elimination reaction of 2-bromobutane?
-
A.
1-Butene
-
B.
2-Butene
-
C.
Butyne
-
D.
All of the above
Solution
2-bromobutane can undergo elimination to form both 1-butene and 2-butene.
Correct Answer: B — 2-Butene
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Q. Which of the following compounds can be formed by the esterification of a carboxylic acid?
-
A.
Alcohol
-
B.
Ester
-
C.
Amide
-
D.
Aldehyde
Solution
Ester is formed by the reaction of a carboxylic acid with an alcohol in an esterification reaction.
Correct Answer: B — Ester
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Q. Which of the following compounds can be formed by the esterification of acetic acid?
-
A.
Ethyl acetate
-
B.
Methyl acetate
-
C.
Butyl acetate
-
D.
All of the above
Solution
All of the listed compounds can be formed by the esterification of acetic acid with the respective alcohols.
Correct Answer: D — All of the above
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Q. Which of the following compounds can be formed by the reaction of an aldehyde with a Grignard reagent?
-
A.
Alcohol
-
B.
Carboxylic acid
-
C.
Ketone
-
D.
Ester
Solution
The reaction of an aldehyde with a Grignard reagent forms a primary alcohol after hydrolysis.
Correct Answer: A — Alcohol
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Q. Which of the following compounds can be oxidized to a ketone?
-
A.
1-butanol
-
B.
2-butanol
-
C.
tert-butanol
-
D.
Cyclohexanol
Solution
2-butanol can be oxidized to form a ketone, specifically butanone.
Correct Answer: B — 2-butanol
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Q. Which of the following compounds can be prepared by the reaction of an alkyl halide with magnesium?
-
A.
Grignard reagent
-
B.
Alkoxide
-
C.
Alcohol
-
D.
Ether
Solution
The reaction of an alkyl halide with magnesium forms a Grignard reagent, which is a key intermediate in organic synthesis.
Correct Answer: A — Grignard reagent
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Q. Which of the following compounds can be reduced to an alcohol using NaBH4?
-
A.
Aldehyde
-
B.
Ketone
-
C.
Both Aldehyde and Ketone
-
D.
None of the above
Solution
Both aldehydes and ketones can be reduced to their corresponding alcohols using sodium borohydride (NaBH4).
Correct Answer: C — Both Aldehyde and Ketone
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Q. Which of the following compounds can be reduced to an alcohol?
-
A.
Aldehyde
-
B.
Ketone
-
C.
Both Aldehyde and Ketone
-
D.
None of the above
Solution
Both aldehydes and ketones can be reduced to their corresponding alcohols.
Correct Answer: C — Both Aldehyde and Ketone
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Q. Which of the following compounds can be used to distinguish between aldehydes and ketones?
-
A.
Benedict's solution
-
B.
Tollens' reagent
-
C.
Fehling's solution
-
D.
All of the above
Solution
Tollens' reagent can be used to distinguish aldehydes from ketones, as it oxidizes aldehydes but not ketones.
Correct Answer: B — Tollens' reagent
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Q. Which of the following compounds can exhibit both cis and trans isomerism?
-
A.
1-hexene
-
B.
2-hexene
-
C.
hexane
-
D.
cyclohexane
Solution
2-hexene can exist in cis and trans forms due to the presence of a double bond.
Correct Answer: B — 2-hexene
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Q. Which of the following compounds can exhibit both geometric and optical isomerism?
-
A.
2-butene
-
B.
3-pentanol
-
C.
2-pentene
-
D.
1,2-dichloropropane
Solution
3-pentanol has a chiral center and can also have geometric isomers due to the presence of a double bond.
Correct Answer: B — 3-pentanol
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Q. Which of the following compounds can exhibit both structural and geometric isomerism?
-
A.
Cis-2-butene
-
B.
1,3-butadiene
-
C.
Cyclohexane
-
D.
2-pentene
Solution
1,3-butadiene can have structural isomers and also exhibit geometric isomerism due to its double bonds.
Correct Answer: B — 1,3-butadiene
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Q. Which of the following compounds can exhibit geometric isomerism?
-
A.
1-Butene
-
B.
2-Butene
-
C.
Cyclohexane
-
D.
Propane
Solution
2-Butene can exhibit geometric isomerism due to the presence of a double bond with different groups attached.
Correct Answer: B — 2-Butene
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Q. Which of the following compounds can exhibit tautomeric isomerism?
-
A.
Acetone
-
B.
Ethanol
-
C.
Acetic acid
-
D.
Phenol
Solution
Acetic acid can exist in two forms (keto and enol) and thus exhibits tautomeric isomerism.
Correct Answer: C — Acetic acid
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Q. Which of the following compounds can show cis-trans isomerism?
-
A.
1-hexene
-
B.
Cyclohexane
-
C.
2-hexene
-
D.
Propane
Solution
2-hexene has a double bond and can have cis and trans configurations.
Correct Answer: C — 2-hexene
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Q. Which of the following compounds can show tautomeric isomerism?
-
A.
Acetone
-
B.
Ethanol
-
C.
Acetic acid
-
D.
Phenol
Solution
Acetic acid can exist in keto and enol forms, thus showing tautomeric isomerism.
Correct Answer: C — Acetic acid
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Q. Which of the following compounds can undergo aldol condensation?
-
A.
Acetone
-
B.
Benzaldehyde
-
C.
Formaldehyde
-
D.
Ethyl acetate
Solution
Acetone can undergo aldol condensation due to the presence of alpha-hydrogens.
Correct Answer: A — Acetone
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Q. Which of the following compounds can undergo elimination reaction to form an alkene?
-
A.
1-chloropropane
-
B.
2-chloropropane
-
C.
3-chloropropane
-
D.
chlorobenzene
Solution
2-chloropropane can undergo elimination to form propene, while the others are less favorable for elimination.
Correct Answer: B — 2-chloropropane
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Q. Which of the following compounds can undergo Friedel-Crafts alkylation?
-
A.
Benzene
-
B.
Cyclohexane
-
C.
Ethylene
-
D.
Acetylene
Solution
Benzene can undergo Friedel-Crafts alkylation, a reaction where an alkyl group is introduced to the aromatic ring.
Correct Answer: A — Benzene
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Q. Which of the following compounds can undergo nucleophilic substitution?
-
A.
Benzene
-
B.
Chloroethane
-
C.
Cyclohexane
-
D.
Ethylene
Solution
Chloroethane can undergo nucleophilic substitution due to the presence of a good leaving group (Cl).
Correct Answer: B — Chloroethane
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Q. Which of the following compounds can undergo oxidation to form a ketone?
-
A.
1-Butanol
-
B.
2-Butanol
-
C.
Cyclohexanol
-
D.
Ethyl alcohol
Solution
2-Butanol can be oxidized to form butanone (a ketone).
Correct Answer: B — 2-Butanol
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