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Q. Which of the following molecules has a bond order of 2?
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Solution
N2 has a bond order of 2, calculated as (number of bonding electrons - number of antibonding electrons)/2 = (10-6)/2 = 2.
Correct Answer: B — N2
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Q. Which of the following molecules has a higher bond order than N2?
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Solution
O2 has a bond order of 2, while N2 has a bond order of 3, so none have a higher bond order than N2.
Correct Answer: A — O2
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Q. Which of the following molecules has a higher bond order: N2 or O2?
A.
N2
B.
O2
C.
Both are equal
D.
Cannot be determined
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Solution
N2 has a bond order of 3, while O2 has a bond order of 2, so N2 has a higher bond order.
Correct Answer: A — N2
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Q. Which of the following molecules has a linear shape?
A.
CH4
B.
H2O
C.
CO2
D.
NH3
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Solution
CO2 has a linear shape due to the arrangement of its double bonds.
Correct Answer: C — CO2
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Q. Which of the following molecules has a trigonal bipyramidal geometry?
A.
NH3
B.
PCl5
C.
H2O
D.
CO2
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Solution
PCl5 has five bonding pairs and no lone pairs, leading to a trigonal bipyramidal geometry.
Correct Answer: B — PCl5
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Q. Which of the following molecules has a triple bond?
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Solution
N2 has a triple bond, consisting of one sigma bond and two pi bonds.
Correct Answer: A — N2
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Q. Which of the following molecules is diamagnetic?
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Solution
F2 is diamagnetic as it has all electrons paired in its molecular orbitals.
Correct Answer: C — F2
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Q. Which of the following molecules is isoelectronic with N2?
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Solution
C2 is isoelectronic with N2, both having 10 electrons.
Correct Answer: B — C2
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Q. Which of the following molecules is isoelectronic with Ne?
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Solution
N2 is isoelectronic with Ne, both having 10 electrons.
Correct Answer: C — N2
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Q. Which of the following molecules is predicted to be stable according to molecular orbital theory?
A.
He2
B.
Li2
C.
Be2
D.
B2
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Solution
Li2 is stable with a bond order of 1, while He2 and Be2 are not stable.
Correct Answer: B — Li2
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Q. Which of the following numbers has 4 significant figures?
A.
0.0025
B.
2500
C.
25.00
D.
0.02500
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Solution
25.00 has 4 significant figures due to the trailing zeros after the decimal.
Correct Answer: C — 25.00
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Q. Which of the following numbers has the least number of significant figures?
A.
0.00345
B.
12.30
C.
100
D.
0.0456
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Solution
The number 100 has only 1 significant figure unless specified otherwise.
Correct Answer: C — 100
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Q. Which of the following numbers has the least significant figures?
A.
0.00560
B.
0.0560
C.
0.560
D.
5.60
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Solution
0.00560 has 3 significant figures, 0.0560 has 3 significant figures, 0.560 has 3 significant figures, and 5.60 has 3 significant figures. However, 0.00560 is the smallest number, but all have the same count of significant figures.
Correct Answer: A — 0.00560
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Q. Which of the following numbers has the most significant figures?
A.
0.00789
B.
7890
C.
7.890 x 10^3
D.
0.07890
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Solution
7.890 x 10^3 has 4 significant figures, while the others have 3, 3, and 4 respectively, but the leading zeros in the first and last options do not count.
Correct Answer: C — 7.890 x 10^3
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Q. Which of the following numbers has three significant figures?
A.
0.00456
B.
123.4
C.
1001
D.
0.0300
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Solution
0.0300 has three significant figures (the zeros after the 3 are significant because they come after a decimal point).
Correct Answer: D — 0.0300
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Q. Which of the following operations will yield a result with the least number of significant figures?
A.
5.00 + 2.0
B.
3.00 x 4.0
C.
6.0 / 2.00
D.
1.5 - 0.50
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Solution
In the operation 3.00 x 4.0, 3.00 has three significant figures and 4.0 has two. The result will have two significant figures, which is the least among the options.
Correct Answer: B — 3.00 x 4.0
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Q. Which of the following orbitals has the highest energy?
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Solution
The 3s orbital has the highest energy among the given options due to its higher principal quantum number.
Correct Answer: D — 3s
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Q. Which of the following orbitals is the highest in energy?
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Solution
The 3d orbital is higher in energy than the 4s orbital due to its shape and electron repulsion.
Correct Answer: D — 3d
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Q. Which of the following orbits allows a satellite to cover the entire surface of the Earth over time?
A.
Geostationary orbit
B.
Polar orbit
C.
Circular orbit
D.
Elliptical orbit
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Solution
A polar orbit allows a satellite to pass over the entire surface of the Earth as the Earth rotates beneath it.
Correct Answer: B — Polar orbit
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Q. Which of the following orbits is used for weather satellites?
A.
Geostationary orbit
B.
Polar orbit
C.
Elliptical orbit
D.
Low Earth orbit
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Solution
Weather satellites typically use polar orbits to cover the entire surface of the Earth as the planet rotates beneath them.
Correct Answer: B — Polar orbit
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Q. Which of the following p-block elements has the highest electronegativity?
A.
Fluorine
B.
Oxygen
C.
Nitrogen
D.
Chlorine
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Solution
Fluorine has the highest electronegativity among all elements.
Correct Answer: A — Fluorine
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Q. Which of the following p-block elements is a metalloid?
A.
Boron
B.
Carbon
C.
Silicon
D.
Phosphorus
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Solution
Boron is a metalloid among the p-block elements.
Correct Answer: A — Boron
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Q. Which of the following p-block elements is essential for life?
A.
Arsenic
B.
Phosphorus
C.
Bismuth
D.
Lead
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Solution
Phosphorus is essential for life, particularly in DNA and ATP.
Correct Answer: B — Phosphorus
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Q. Which of the following p-block elements is essential for plant growth?
A.
Boron
B.
Lead
C.
Arsenic
D.
Bismuth
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Solution
Boron is an essential micronutrient for plant growth.
Correct Answer: A — Boron
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Q. Which of the following p-block elements is known for forming a stable +4 oxidation state?
A.
Carbon
B.
Silicon
C.
Germanium
D.
Tin
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Solution
Tin (Sn) is known for forming a stable +4 oxidation state.
Correct Answer: D — Tin
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Q. Which of the following p-block elements is known for forming stable +3 oxidation state?
A.
Bismuth
B.
Lead
C.
Tin
D.
Thallium
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Solution
Thallium is known for forming a stable +3 oxidation state.
Correct Answer: D — Thallium
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Q. Which of the following p-block elements is known for forming stable +3 oxidation state compounds?
A.
Aluminum
B.
Silicon
C.
Carbon
D.
Lead
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Solution
Aluminum commonly forms stable +3 oxidation state compounds.
Correct Answer: A — Aluminum
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Q. Which of the following pairs are enantiomers?
A.
D-Glucose and L-Glucose
B.
C2H6 and C2H5OH
C.
n-Butane and Isobutane
D.
C3H8 and C3H6
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Solution
D-Glucose and L-Glucose are mirror images of each other, making them enantiomers.
Correct Answer: A — D-Glucose and L-Glucose
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Q. Which of the following pairs are structural isomers?
A.
Cis-2-butene and trans-2-butene
B.
1-pentanol and 2-pentanol
C.
Ethylene and acetylene
D.
Glucose and galactose
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Solution
1-pentanol and 2-pentanol differ in the position of the hydroxyl group, making them structural isomers.
Correct Answer: B — 1-pentanol and 2-pentanol
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Q. Which of the following pairs of atoms will form a bond with the highest bond order?
A.
C and O
B.
N and O
C.
C and N
D.
O and O
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Solution
C and N will form a bond with the highest bond order of 3, as seen in the molecule CN.
Correct Answer: C — C and N
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