The potential V = k * p / r, where p is the dipole moment.

The electric potential V due to a point charge q at a distance r is given by V = k * q / r.

Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (2 m) = 2250 V.

Electric potential energy U = q * V = 1 C * 10 V = 10 J.

Electric potential energy U = q * V = q * E * d = 1 C * 10 N/C * 2 m = 20 J.

Electric potential energy U = q * V = 1 × 10^-6 C * 200 V = 0.2 mJ.

The electric potential energy U = k(q1*q2)/r = k(+q*-q)/r = -kq²/r.

U = k * (q1 * q2) / r = (9 × 10^9 N m²/C²) * (2 × 10^-6 C * -2 × 10^-6 C) / 0.5 m = -72 J.

The electric potential energy U of a system of two point charges is given by U = kQ1Q2/r.

Chromium has an electron configuration of [Ar] 4s1 3d5 due to stability from half-filled d-orbitals.

The electron configuration of Magnesium (Mg) is 1s² 2s² 2p⁶ 3s².

The electron configuration of oxygen (atomic number 8) is 1s2 2s2 2p4.

The electron configuration of potassium (K) is 1s² 2s² 2p⁶ 3s¹.

The electron configuration of potassium (K) is 1s² 2s² 2p⁶ 3s¹.

The electron configuration of magnesium (Mg) is 1s² 2s² 2p⁶ 3s².

The element with atomic number 12 is Magnesium (Mg) with the configuration 1s2 2s2 2p6 3s2.

The electron configuration of iron (Fe), which has an atomic number of 26, is 1s2 2s2 2p6 3s2 3p6 4s2 3d6.

The electron configuration of magnesium (Mg) is 1s² 2s² 2p⁶ 3s².

NH3 has four electron pairs (three bonding pairs and one lone pair), giving it a tetrahedral electron pair geometry.

SF6 has six bonding pairs and no lone pairs, resulting in an octahedral electron pair geometry.

Chlorine ion (Cl-) has gained an electron, resulting in the configuration 1s2 2s2 2p6.

Oxygen has 8 electrons. The electronic configuration is 1s2 2s2 2p4.

Sodium has 11 electrons, and its configuration is 1s2 2s2 2p6 3s1.

Sodium ion (Na+) has lost one electron, resulting in the configuration 1s2 2s2 2p6.

Chlorine (Cl) has 17 electrons, so its configuration is 1s2 2s2 2p6 3s2 3p5.

Iron (Fe) has the configuration [Ar] 4s2 3d6.

Oxygen has 8 electrons, and its electronic configuration is 1s2 2s2 2p4.

The electronic configuration of potassium (K) is 1s² 2s² 2p⁶ 3s¹.

Chloride ion has gained one electron, making its configuration 1s2 2s2 2p6 3s2 3p6.

The electronic configuration of Rutherfordium (atomic number 104) is [Rn] 5f14 6d4.