Q. What is the normality of a solution containing 4 moles of H2SO4 in 2 liters of solution?
A.
4 N
B.
8 N
C.
2 N
D.
1 N
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Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 has 2 equivalents, so 4 moles = 8 equivalents. N = 8 eq / 2 L = 4 N.
Correct Answer: B — 8 N
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Q. What is the normality of a solution that is 1 M in H2SO4?
A.
1 N
B.
2 N
C.
0.5 N
D.
4 N
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Solution
Normality (N) = Molarity (M) x number of equivalents. H2SO4 has 2 acidic protons, so 1 M x 2 = 2 N.
Correct Answer: B — 2 N
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Q. What is the osmotic pressure of a 0.2 M NaCl solution at 25 °C? (R = 0.0821 L atm/(K mol))
A.
4.92 atm
B.
2.46 atm
C.
1.23 atm
D.
0.61 atm
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Solution
Osmotic pressure = iCRT = 2 * 0.2 * 0.0821 * 298 = 4.92 atm (i = 2 for NaCl)
Correct Answer: A — 4.92 atm
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Q. What is the osmotic pressure of a solution containing 0.2 moles of solute in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
4.92 atm
B.
1.64 atm
C.
0.82 atm
D.
2.46 atm
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Solution
Osmotic pressure = (n/V)RT = (0.2/1) * 0.0821 * 298 = 4.92 atm.
Correct Answer: A — 4.92 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
12.3 atm
B.
0.5 atm
C.
1.0 atm
D.
2.5 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 mol)(0.0821 L·atm/(K·mol))(298 K) = 12.3 atm.
Correct Answer: A — 12.3 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 liter of water at 25 °C?
A.
12.3 atm
B.
24.6 atm
C.
6.1 atm
D.
3.1 atm
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Solution
Osmotic pressure (π) = iCRT = 1 * 0.5 * 0.0821 * 298 = 12.3 atm.
Correct Answer: A — 12.3 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 L of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
12.3 atm
B.
10.2 atm
C.
8.2 atm
D.
6.1 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 moles)(0.0821 L·atm/(K·mol))(298 K) = 12.3 atm.
Correct Answer: A — 12.3 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 L of water at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
12.3 atm
B.
1.23 atm
C.
0.5 atm
D.
2.5 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 moles * 0.0821 * 298) / 1 = 12.3 atm.
Correct Answer: B — 1.23 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
6.13 atm
B.
12.26 atm
C.
3.07 atm
D.
1.54 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 moles)(0.0821 L·atm/(K·mol))(298 K) / 2 L = 6.13 atm.
Correct Answer: A — 6.13 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution? (R = 0.0821 L·atm/(K·mol), T = 298 K)
A.
6.14 atm
B.
12.28 atm
C.
3.07 atm
D.
1.54 atm
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Solution
Osmotic pressure (π) = (n/V)RT = (0.5/2) * 0.0821 * 298 = 6.14 atm.
Correct Answer: A — 6.14 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of solute in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
10.25 atm
B.
5.12 atm
C.
2.03 atm
D.
1.23 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 moles * 0.0821 * 298) / 2 = 12.21 atm.
Correct Answer: B — 5.12 atm
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Q. What is the osmotic pressure of a solution containing 1 mole of glucose in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
0.41 atm
B.
0.82 atm
C.
1.23 atm
D.
1.64 atm
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Solution
Osmotic pressure (π) = nRT/V = (1 mol)(0.0821 L·atm/(K·mol))(298 K) / 2 L = 0.82 atm.
Correct Answer: B — 0.82 atm
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Q. What is the osmotic pressure of a solution directly proportional to?
A.
Temperature
B.
Concentration of solute
C.
Volume of solvent
D.
Both A and B
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Solution
Osmotic pressure is directly proportional to both the temperature and the concentration of solute.
Correct Answer: D — Both A and B
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Q. What is the percentage by mass of a solution containing 20 grams of solute in 180 grams of solution?
A.
10%
B.
20%
C.
15%
D.
25%
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Solution
Percentage by mass = (mass of solute / mass of solution) * 100 = (20 g / (20 g + 180 g)) * 100 = 20%.
Correct Answer: B — 20%
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Q. What is the percentage by mass of a solution containing 5 g of NaCl in 95 g of water?
A.
5%
B.
10%
C.
15%
D.
20%
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Solution
Percentage by mass = (mass of solute / total mass) × 100 = (5 g / (5 g + 95 g)) × 100 = 5%.
Correct Answer: A — 5%
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Q. What is the primary factor affecting colligative properties?
A.
Nature of solute
B.
Concentration of solute
C.
Temperature
D.
Volume of solvent
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Solution
Colligative properties depend primarily on the concentration of solute particles in a solution.
Correct Answer: B — Concentration of solute
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Q. What is the primary reason for the elevation of boiling point in a solution?
A.
Increased molecular weight
B.
Decreased vapor pressure
C.
Increased solubility
D.
Decreased temperature
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Solution
The elevation of boiling point occurs because the presence of solute lowers the vapor pressure of the solvent, requiring a higher temperature to reach boiling.
Correct Answer: B — Decreased vapor pressure
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Q. What is the primary reason for the lowering of vapor pressure in a solution?
A.
Increased temperature
B.
Decreased surface area
C.
Presence of solute particles
D.
Increased molecular weight of solvent
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Solution
The presence of solute particles reduces the number of solvent molecules at the surface, leading to a lower vapor pressure.
Correct Answer: C — Presence of solute particles
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Q. What is the relationship between the molality of a solution and its boiling point elevation?
A.
Directly proportional
B.
Inversely proportional
C.
No relationship
D.
Exponential relationship
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Solution
Boiling point elevation is directly proportional to the molality of the solution.
Correct Answer: A — Directly proportional
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Q. What is the solution set of the equation x^2 + 1 = 0?
A.
{0}
B.
{±i}
C.
{1}
D.
{-1}
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Solution
The equation has no real solutions; the solutions are x = i and x = -i.
Correct Answer: B — {±i}
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Q. What is the solution set of the equation x^2 + 4x + 4 = 0?
A.
{-2}
B.
{-4, 0}
C.
{2, 2}
D.
{-2, -2}
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Solution
The equation factors to (x + 2)^2 = 0, giving a double root x = -2.
Correct Answer: D — {-2, -2}
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Q. What is the solution set of the equation x^2 - 5x + 6 = 0?
A.
{2, 3}
B.
{1, 6}
C.
{3, 4}
D.
{0, 5}
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Solution
The equation factors to (x-2)(x-3) = 0, giving solutions x = 2 and x = 3.
Correct Answer: A — {2, 3}
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Q. What is the solution to the equation 2(x - 1) = 4?
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Solution
Dividing both sides by 2 gives x - 1 = 2, thus x = 3.
Correct Answer: C — 3
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Q. What is the solution to the equation 4x + 1 = 9?
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Solution
Subtract 1 from both sides: 4x = 8. Then divide by 4: x = 2.
Correct Answer: B — 2
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Q. What is the solution to the equation 5x - 7 = 3?
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Solution
Adding 7 to both sides gives 5x = 10, then dividing by 5 gives x = 2.
Correct Answer: A — 1
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Q. What is the solution to the equation x^2 - 4 = 0?
A.
-2, 2
B.
0, 4
C.
2, 4
D.
1, 3
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Solution
Factoring gives (x - 2)(x + 2) = 0, leading to solutions x = 2 and x = -2.
Correct Answer: A — -2, 2
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Q. What is the solution to the equation |x - 3| = 5?
A.
{8, -2}
B.
{3, 5}
C.
{5, 1}
D.
{0, 6}
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Solution
The absolute value equation gives two cases: x - 3 = 5 or x - 3 = -5, leading to x = 8 or x = -2.
Correct Answer: A — {8, -2}
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Q. What is the value of k for which the equation x^2 - 2kx + 3 = 0 has roots that are reciprocals of each other?
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Solution
If the roots are reciprocals, then k = sum of roots = 0 and product = 1. Thus, k = 2.
Correct Answer: B — 2
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Q. What is the value of k for which the equation x^2 - 4x + k = 0 has roots that are equal?
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Solution
For equal roots, the discriminant must be zero: (-4)^2 - 4*1*k = 0 => 16 - 4k = 0 => k = 4.
Correct Answer: A — 4
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Q. What is the value of k if the roots of the equation x^2 + kx + 16 = 0 are equal?
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Solution
For equal roots, the discriminant must be zero: k^2 - 4*1*16 = 0 => k^2 = 64 => k = 8 or k = -8.
Correct Answer: B — 8
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