Q. If 200 J of heat is added to a system and 50 J of work is done by the system, what is the change in internal energy of the system?
-
A.
150 J
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B.
250 J
-
C.
200 J
-
D.
100 J
Solution
According to the first law of thermodynamics, ΔU = Q - W = 200 J - 50 J = 150 J.
Correct Answer: A — 150 J
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Q. If 2000 J of heat is added to a system and 500 J of work is done by the system, what is the change in internal energy of the system? (2021)
-
A.
1500 J
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B.
2000 J
-
C.
2500 J
-
D.
3000 J
Solution
Using the first law of thermodynamics: ΔU = Q - W = 2000 J - 500 J = 1500 J.
Correct Answer: A — 1500 J
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Q. If 2x = 10, what is the value of x? (2015)
Solution
Dividing both sides by 2 gives x = 10/2 = 5.
Correct Answer: A — 5
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Q. If 3 moles of glucose are dissolved in 1 liter of solution, what is the molality of the solution? (2023)
-
A.
3 m
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B.
1 m
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C.
2 m
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D.
0.5 m
Solution
Molality (m) = moles of solute / kg of solvent; assuming 1 L of water = 1 kg, m = 3 moles / 1 kg = 3 m
Correct Answer: A — 3 m
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Q. If 3x = 12, what is the value of x? (2019)
Q. If 50 mL of 0.1 M H2SO4 is diluted to 250 mL, what is the new concentration?
-
A.
0.02 M
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B.
0.04 M
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C.
0.1 M
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D.
0.5 M
Solution
C1V1 = C2V2; (0.1 M)(50 mL) = C2(250 mL); C2 = 0.02 M.
Correct Answer: B — 0.04 M
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Q. If 50 mL of a 3 M solution is diluted to 200 mL, what is the new molarity? (2020)
-
A.
0.75 M
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B.
1.5 M
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C.
2 M
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D.
3 M
Solution
Using M1V1 = M2V2, (3 M)(50 mL) = M2(200 mL) => M2 = (3 M × 50 mL) / 200 mL = 0.75 M.
Correct Answer: A — 0.75 M
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Q. If 500 J of heat is added to a system and 200 J of work is done by the system, what is the change in internal energy of the system?
-
A.
300 J
-
B.
500 J
-
C.
700 J
-
D.
200 J
Solution
According to the first law of thermodynamics, ΔU = Q - W. Here, ΔU = 500 J - 200 J = 300 J.
Correct Answer: A — 300 J
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Q. If 500 J of heat is added to a system and it does 200 J of work, what is the change in internal energy? (2022)
-
A.
300 J
-
B.
200 J
-
C.
500 J
-
D.
700 J
Solution
According to the first law of thermodynamics, ΔU = Q - W. Here, ΔU = 500 J - 200 J = 300 J.
Correct Answer: A — 300 J
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Q. If 5x = 25, what is the value of x? (2019)
Solution
5x = 25, so x = 25/5 = 5.
Correct Answer: A — 5
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Q. If a 10 kg object is dropped from a height of 20 m, what is the velocity just before it hits the ground? (Assume g = 10 m/s²) (2019)
-
A.
10 m/s
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B.
20 m/s
-
C.
14 m/s
-
D.
15 m/s
Solution
Using v² = u² + 2gh, v = √(0 + 2 × 10 m/s² × 20 m) = √400 = 20 m/s.
Correct Answer: B — 20 m/s
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Q. If a 10 kg object is moving with a speed of 2 m/s, what is its kinetic energy?
-
A.
10 J
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B.
20 J
-
C.
40 J
-
D.
80 J
Solution
KE = 0.5 × m × v² = 0.5 × 10 kg × (2 m/s)² = 0.5 × 10 × 4 = 20 J.
Correct Answer: B — 20 J
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Q. If a 10 kg object is raised to a height of 5 m, what is the work done against gravity? (g = 9.8 m/s²)
-
A.
490 J
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B.
980 J
-
C.
150 J
-
D.
250 J
Solution
Work = m * g * h = 10 kg * 9.8 m/s² * 5 m = 490 J.
Correct Answer: B — 980 J
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Q. If a 10 N force is applied at an angle of 60 degrees to the horizontal while moving an object 3 m, what is the work done? (2020)
-
A.
15 J
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B.
30 J
-
C.
25 J
-
D.
5 J
Solution
Work done = Force × Distance × cos(θ) = 10 N × 3 m × cos(60°) = 10 N × 3 m × 0.5 = 15 J
Correct Answer: A — 15 J
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Q. If a 1000 kg car is moving at a speed of 15 m/s, what is its kinetic energy?
-
A.
112,500 J
-
B.
225,000 J
-
C.
150,000 J
-
D.
75,000 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (15 m/s)² = 112,500 J
Correct Answer: B — 225,000 J
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Q. If a 1000 kg car is moving with a speed of 15 m/s, what is its kinetic energy?
-
A.
112,500 J
-
B.
225,000 J
-
C.
75,000 J
-
D.
150,000 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (15 m/s)² = 112,500 J
Correct Answer: B — 225,000 J
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Q. If a 1000 W motor runs for 2 hours, how much work does it do? (2000)
-
A.
7200 J
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B.
2000 J
-
C.
3600000 J
-
D.
100000 J
Solution
Work = Power × Time = 1000 W × (2 hours × 3600 s/hour) = 1000 W × 7200 s = 7200000 J
Correct Answer: C — 3600000 J
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Q. If a 100Ω resistor is connected in series with a 200Ω resistor, what is the total resistance? (2023)
-
A.
300Ω
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B.
100Ω
-
C.
200Ω
-
D.
400Ω
Solution
In series, R_total = R1 + R2 = 100Ω + 200Ω = 300Ω.
Correct Answer: A — 300Ω
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Q. If a 10Ω resistor is connected in parallel with a 5Ω resistor, what is the equivalent resistance? (2022)
-
A.
3.33Ω
-
B.
5Ω
-
C.
7.5Ω
-
D.
15Ω
Solution
For parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/5 = 1/10 + 2/10 = 3/10. Therefore, R_eq = 10/3 = 3.33Ω.
Correct Answer: A — 3.33Ω
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Q. If a 10Ω resistor is connected in parallel with a 5Ω resistor, what is the total resistance? (2022)
-
A.
3.33Ω
-
B.
5Ω
-
C.
7.5Ω
-
D.
15Ω
Solution
For resistors in parallel, 1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/5 = 1/10 + 2/10 = 3/10. Therefore, R_eq = 10/3 = 3.33Ω.
Correct Answer: A — 3.33Ω
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Q. If a 1500 kg car is moving at a speed of 30 m/s, what is its kinetic energy?
-
A.
675,000 J
-
B.
450,000 J
-
C.
225,000 J
-
D.
900,000 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1500 kg × (30 m/s)² = 675,000 J
Correct Answer: B — 450,000 J
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Q. If a 15Ω resistor is connected in parallel with a 30Ω resistor, what is the equivalent resistance? (2021)
-
A.
10Ω
-
B.
7.5Ω
-
C.
5Ω
-
D.
12Ω
Solution
For resistors in parallel, 1/R_eq = 1/R1 + 1/R2 = 1/15 + 1/30 = 2/30 + 1/30 = 3/30. Therefore, R_eq = 30/3 = 10Ω.
Correct Answer: B — 7.5Ω
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Q. If a 15Ω resistor is connected in parallel with a 5Ω resistor, what is the equivalent resistance? (2023)
-
A.
3.75Ω
-
B.
4Ω
-
C.
5Ω
-
D.
10Ω
Solution
1/R_eq = 1/15 + 1/5 = 1/15 + 3/15 = 4/15; R_eq = 15/4 = 3.75Ω.
Correct Answer: A — 3.75Ω
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Q. If a 2 kg object is dropped from a height, what is its velocity just before hitting the ground (g = 10 m/s²)? (2023)
-
A.
10 m/s
-
B.
20 m/s
-
C.
30 m/s
-
D.
40 m/s
Solution
Using v = √(2gh), for h = 10 m, v = √(2 * 10 m/s² * 10 m) = √200 = 20 m/s.
Correct Answer: B — 20 m/s
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Q. If a 2 kg object is dropped from a height, what is its velocity just before hitting the ground? (g = 9.8 m/s², h = 20 m) (2023)
-
A.
14 m/s
-
B.
19.6 m/s
-
C.
20 m/s
-
D.
28 m/s
Solution
Using v² = u² + 2gh, where u = 0, we find v = √(2 * 9.8 * 20) = 19.6 m/s.
Correct Answer: B — 19.6 m/s
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Q. If a 2 kg object is lifted to a height of 10 m, what is the potential energy gained by the object? (g = 9.8 m/s²)
-
A.
19.6 J
-
B.
98 J
-
C.
39.2 J
-
D.
78.4 J
Solution
Potential Energy (PE) = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.
Correct Answer: B — 98 J
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Q. If a 2 kg object is lifted to a height of 3 m, what is the potential energy gained by the object? (g = 9.8 m/s²)
-
A.
58.8 J
-
B.
19.6 J
-
C.
29.4 J
-
D.
39.2 J
Solution
Potential Energy (PE) = mgh = 2 kg × 9.8 m/s² × 3 m = 58.8 J.
Correct Answer: A — 58.8 J
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Q. If a 2 kg object is moving with a velocity of 15 m/s, what is its kinetic energy?
-
A.
225 J
-
B.
150 J
-
C.
300 J
-
D.
450 J
Solution
Kinetic Energy = 1/2 * m * v^2 = 1/2 * 2 kg * (15 m/s)^2 = 225 J.
Correct Answer: A — 225 J
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Q. If a 2 kg object is moving with a velocity of 3 m/s, what is its kinetic energy?
-
A.
9 J
-
B.
6 J
-
C.
3 J
-
D.
12 J
Solution
Kinetic Energy = 0.5 * m * v² = 0.5 * 2 kg * (3 m/s)² = 9 J.
Correct Answer: A — 9 J
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Q. If a 3 kg object is moving with a speed of 4 m/s, what is its kinetic energy?
-
A.
12 J
-
B.
24 J
-
C.
36 J
-
D.
48 J
Solution
KE = 0.5 × m × v² = 0.5 × 3 kg × (4 m/s)² = 0.5 × 3 × 16 = 24 J.
Correct Answer: B — 24 J
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