If 200 J of heat is added to a system and 50 J of work is done by the system, what is the change in internal energy of the system?
Practice Questions
1 question
Q1
If 200 J of heat is added to a system and 50 J of work is done by the system, what is the change in internal energy of the system?
150 J
250 J
200 J
100 J
According to the first law of thermodynamics, ΔU = Q - W = 200 J - 50 J = 150 J.
Questions & Step-by-step Solutions
1 item
Q
Q: If 200 J of heat is added to a system and 50 J of work is done by the system, what is the change in internal energy of the system?
Solution: According to the first law of thermodynamics, ΔU = Q - W = 200 J - 50 J = 150 J.
Steps: 6
Step 1: Identify the amount of heat added to the system, which is 200 J. This is represented as Q.
Step 2: Identify the amount of work done by the system, which is 50 J. This is represented as W.
Step 3: Use the formula from the first law of thermodynamics, which states that the change in internal energy (ΔU) is equal to the heat added (Q) minus the work done (W).
Step 4: Substitute the values into the formula: ΔU = Q - W = 200 J - 50 J.
Step 5: Calculate the result: 200 J - 50 J = 150 J.
Step 6: Conclude that the change in internal energy of the system is 150 J.
