Electric Potential
Q. What is the electric potential at a point due to a point charge?
A.
kQ/r
B.
Q/(4πε₀r²)
C.
kQ/(4πε₀r)
D.
Q/(4πr²)
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Solution
The electric potential V at a distance r from a point charge Q is given by V = kQ/r, where k is Coulomb's constant.
Correct Answer: A — kQ/r
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Q. What is the electric potential at a point due to a positive point charge?
A.
Zero
B.
Positive
C.
Negative
D.
Depends on distance
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Solution
The electric potential due to a positive point charge is positive and decreases with distance from the charge.
Correct Answer: B — Positive
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Q. What is the electric potential at a point in space where the electric field is zero?
A.
Zero
B.
Positive
C.
Negative
D.
Undefined
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Solution
The electric potential can be positive or negative; it is not necessarily zero when the electric field is zero.
Correct Answer: B — Positive
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Q. What is the electric potential due to a dipole at a point along the axial line at a distance 'r' from the center of the dipole?
A.
0
B.
k * p / r²
C.
k * p / r
D.
k * p / 2r
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Solution
The potential V = k * p / r, where p is the dipole moment.
Correct Answer: C — k * p / r
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Q. What is the electric potential due to a point charge of 5 μC at a distance of 2 m?
A.
0 V
B.
2250 V
C.
1125 V
D.
4500 V
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Solution
Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (2 m) = 2250 V.
Correct Answer: B — 2250 V
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Q. What is the electric potential energy of a charge of 1 C at a point where the electric potential is 10 V?
A.
10 J
B.
1 J
C.
0 J
D.
100 J
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Solution
Electric potential energy U = q * V = 1 C * 10 V = 10 J.
Correct Answer: A — 10 J
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Q. What is the electric potential energy of a charge of 1 C placed in an electric field of 10 N/C at a distance of 2 m?
A.
20 J
B.
10 J
C.
5 J
D.
2 J
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Solution
Electric potential energy U = q * V = q * E * d = 1 C * 10 N/C * 2 m = 20 J.
Correct Answer: A — 20 J
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Q. What is the electric potential energy of a charge of 1 μC placed in an electric potential of 200 V?
A.
0.2 mJ
B.
0.1 mJ
C.
0.4 mJ
D.
0.5 mJ
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Solution
Electric potential energy U = q * V = 1 × 10^-6 C * 200 V = 0.2 mJ.
Correct Answer: A — 0.2 mJ
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Q. What is the electric potential energy of a system of two charges +q and -q separated by a distance r?
A.
0
B.
kq²/r
C.
-kq²/r
D.
kq/r
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Solution
The electric potential energy U = k(q1*q2)/r = k(+q*-q)/r = -kq²/r.
Correct Answer: C — -kq²/r
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Q. What is the electric potential energy of a system of two charges of +2 μC and -2 μC separated by 0.5 m?
A.
-72 J
B.
72 J
C.
0 J
D.
-36 J
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Solution
U = k * (q1 * q2) / r = (9 × 10^9 N m²/C²) * (2 × 10^-6 C * -2 × 10^-6 C) / 0.5 m = -72 J.
Correct Answer: D — -36 J
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Q. What is the electric potential energy of a system of two point charges Q1 and Q2 separated by a distance r?
A.
kQ1Q2/r
B.
kQ1Q2/2r
C.
kQ1Q2/r²
D.
kQ1Q2
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Solution
The electric potential energy U of a system of two point charges is given by U = kQ1Q2/r.
Correct Answer: A — kQ1Q2/r
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Q. What is the potential at a distance of 1 m from a dipole with a dipole moment of 2 × 10^-9 C·m?
A.
0 V
B.
1 V
C.
2 V
D.
4 V
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Solution
Potential due to a dipole V = (1/4πε₀) * (p * cosθ) / r². At 1 m, it is negligible.
Correct Answer: A — 0 V
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Q. What is the potential difference across a 5 Ω resistor carrying a current of 2 A?
A.
10 V
B.
5 V
C.
2 V
D.
0 V
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Solution
Using Ohm's law, V = I * R = 2 A * 5 Ω = 10 V.
Correct Answer: A — 10 V
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Q. What is the potential difference between two points A and B if the electric field is 5 N/C and the distance between them is 3 m?
A.
15 V
B.
5 V
C.
3 V
D.
0 V
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Solution
Potential difference V = E * d = 5 N/C * 3 m = 15 V.
Correct Answer: A — 15 V
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Q. What is the potential difference between two points in an electric field if the work done in moving a charge of 3 C from one point to another is 15 J?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
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Solution
Potential difference V = Work done / Charge = 15 J / 3 C = 5 V.
Correct Answer: B — 10 V
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Q. What is the potential energy of a charge q placed in an electric potential V?
A.
qV
B.
q/V
C.
V/q
D.
q²V
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Solution
The potential energy U of a charge q in an electric potential V is given by U = qV.
Correct Answer: A — qV
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Q. What is the potential energy of a system of two point charges +q and -q separated by a distance r?
A.
0
B.
kq²/r
C.
-kq²/r
D.
kq/r
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Solution
The potential energy U of a system of two point charges is given by U = k(q1q2)/r = -kq²/r for +q and -q.
Correct Answer: C — -kq²/r
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Q. What is the relationship between electric field E and electric potential V?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/d
D.
E = -V/d
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Solution
The electric field E is the negative gradient of the electric potential V, given by E = -dV/dx.
Correct Answer: A — E = -dV/dx
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Q. What is the relationship between electric potential (V) and electric field (E) in a uniform field?
A.
V = E × d
B.
V = E/d
C.
E = V × d
D.
E = V/d
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Solution
In a uniform electric field, the electric potential difference V is given by V = E × d, where d is the distance moved in the direction of the field.
Correct Answer: A — V = E × d
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Q. What is the relationship between electric potential and electric field?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/d
D.
E = -V/d
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Solution
The electric field E is the negative gradient of the electric potential V, expressed as E = -dV/dx.
Correct Answer: A — E = -dV/dx
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Q. What is the unit of electric potential?
A.
Coulomb
B.
Volt
C.
Joule
D.
Newton
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Solution
The unit of electric potential is the Volt (V), which is defined as one Joule per Coulomb.
Correct Answer: B — Volt
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Q. What is the work done in moving a charge of 2 μC from a point at 50 V to a point at 100 V?
A.
0.1 mJ
B.
0.2 mJ
C.
0.3 mJ
D.
0.4 mJ
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Solution
Work done W = q * ΔV = 2 × 10^-6 C * (100 V - 50 V) = 2 × 10^-6 * 50 = 0.1 mJ.
Correct Answer: B — 0.2 mJ
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Q. What is the work done in moving a charge of 2 μC from a point at 50 V to another at 100 V?
A.
100 μJ
B.
200 μJ
C.
150 μJ
D.
50 μJ
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Solution
Work done W = q * ΔV = (2 × 10^-6 C) * (100 V - 50 V) = 100 μJ.
Correct Answer: B — 200 μJ
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Q. Which of the following statements is true about equipotential surfaces?
A.
They are always parallel to each other
B.
No work is done moving a charge along them
C.
They can intersect
D.
They are always spherical
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Solution
No work is done when moving a charge along an equipotential surface because the potential is constant.
Correct Answer: B — No work is done moving a charge along them
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