Potential difference ΔV = E * d = (150 V / 3 m) * 3 m = 150 V.

Potential energy U = q * V = -1 C * 200 V = -200 J.

Work done W = q * (V1 - V2) = 0.5 C * (200 V - 100 V) = 50 J.

Work done W = q * V = 0.5 C * 200 V = 100 J.

The force on a charge in a static electric field is not determined by potential alone; it depends on the electric field, which is not given.

Work done W = q * ΔV = 3 × 10^-6 C * (600 V - 300 V) = 3 × 10^-6 * 300 = 0.9 mJ.

Distance d = V/E = 50 V / 5 N/C = 10 m.

Change in potential energy ΔU = qΔV = 3 C × (15 V - 5 V) = 30 J.

An increase in electric potential at a point generally indicates a stronger electric field, as the electric field is related to the rate of change of potential.

If the electric potential increases, the work done by the external force must increase to move the positive charge against the electric field.

The work done (W) by the electric field is given by W = q(V_A - V_B). For a unit charge, W = 10 V - 5 V = 5 J.

Potential difference (V_AB) = V_A - V_B = 15 V - 5 V = 10 V.

Work done W = Q(V_B - V_A) = 2 C * (15 V - 5 V) = 20 J.

The potential difference V_AB = V_B - V_A = 15 V - 5 V = 10 V.

If the electric potential is constant, the electric field in that region is zero, as E = -dV/dx.

The electric potential energy increases as the charges are brought closer together if they are of the same sign.

The electric potential V is directly proportional to the distance d between the plates, so if d is doubled, V also doubles.

In a uniform electric field, the electric potential changes linearly with distance.

The potential difference is directly proportional to both the distance between the points and the magnitude of the electric field.

In a uniform electric field, the potential difference (V) between two points separated by a distance (d) is given by V = E × d, where E is the electric field strength.

In a uniform electric field, the potential difference (V) between two points is given by V = Ed, where d is the distance between the points.

The work done in moving a charge in an electric field is equal to the change in electric potential energy.

The potentials due to both charges at the midpoint cancel each other, so V = 0 V.

The electric potential at the midpoint is zero because the potentials due to +Q and -Q cancel each other out.

At the midpoint, the potentials due to both charges cancel each other out, resulting in a net potential of 0 V.

The electric potential decreases as you move away from a positive charge.

When a charge moves against an electric field, its electric potential energy increases.

The electric potential energy of a system of charges decreases when they are brought closer together, especially if they are of opposite signs.

V = k * q / r = (9 × 10^9 N m²/C²) * (10 × 10^-6 C) / (3 m) = 30000 V / 3 = 9000 V.

Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (8 × 10^-6 C) / (4 m) = 1800 V.