Diffraction
Q. In a single-slit diffraction pattern, how does the intensity of the first minimum compare to the intensity of the central maximum?
A.
It is equal
B.
It is half
C.
It is zero
D.
It is one-fourth
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Solution
The intensity at the first minimum is zero, while the central maximum has maximum intensity.
Correct Answer: C — It is zero
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Q. In a single-slit diffraction pattern, how many minima are there on either side of the central maximum?
A.
One
B.
Two
C.
Three
D.
Infinite
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Solution
In a single-slit diffraction pattern, there are theoretically infinite minima on either side of the central maximum.
Correct Answer: D — Infinite
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Q. In a single-slit diffraction pattern, the width of the central maximum is 4 mm. If the slit width is halved, what will be the new width of the central maximum?
A.
2 mm
B.
4 mm
C.
8 mm
D.
16 mm
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Solution
The width of the central maximum is inversely proportional to the slit width. Halving the slit width doubles the width of the central maximum to 8 mm.
Correct Answer: C — 8 mm
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Q. In double-slit diffraction, what is the effect of increasing the distance between the slits on the fringe width?
A.
Fringe width increases
B.
Fringe width decreases
C.
Fringe width remains constant
D.
Fringe width becomes zero
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Solution
Increasing the distance between the slits increases the fringe width because the angle of diffraction increases.
Correct Answer: A — Fringe width increases
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Q. In double-slit diffraction, what is the path difference for constructive interference at the first order maximum?
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Solution
For constructive interference, the path difference must be an integer multiple of the wavelength, so for the first order maximum, it is λ.
Correct Answer: B — λ
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Q. In the context of diffraction, what does the term 'angular width' refer to?
A.
The angle between the first and second minima
B.
The angle of incidence
C.
The angle of reflection
D.
The angle of diffraction
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Solution
Angular width refers to the angle between the first and second minima in a diffraction pattern.
Correct Answer: A — The angle between the first and second minima
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Q. In the context of diffraction, what does the term 'coherence' refer to?
A.
The ability of waves to interfere
B.
The speed of light
C.
The intensity of light
D.
The wavelength of light
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Solution
Coherence refers to the ability of waves to maintain a constant phase relationship, which is essential for producing clear interference patterns.
Correct Answer: A — The ability of waves to interfere
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Q. In the context of diffraction, what does the term 'resolution' refer to?
A.
The ability to distinguish between two closely spaced objects
B.
The intensity of the diffracted light
C.
The wavelength of the light used
D.
The width of the slit
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Solution
Resolution refers to the ability to distinguish between two closely spaced objects, which is affected by diffraction.
Correct Answer: A — The ability to distinguish between two closely spaced objects
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Q. What happens to the diffraction pattern when monochromatic light is replaced with white light?
A.
It becomes monochromatic
B.
It disappears
C.
It becomes colored
D.
It remains unchanged
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Solution
Replacing monochromatic light with white light results in a colored diffraction pattern due to the different wavelengths.
Correct Answer: C — It becomes colored
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Q. What happens to the diffraction pattern when the distance between the slits in a double-slit experiment is increased?
A.
Fringe width increases
B.
Fringe width decreases
C.
Fringe pattern disappears
D.
Fringe intensity increases
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Solution
Increasing the distance between the slits decreases the fringe width, as fringe width is inversely proportional to the slit separation.
Correct Answer: B — Fringe width decreases
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Q. What happens to the diffraction pattern when the distance to the screen is increased?
A.
Fringe width decreases
B.
Fringe width increases
C.
Fringe intensity increases
D.
Fringe intensity decreases
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Solution
Increasing the distance to the screen results in an increase in fringe width in the diffraction pattern.
Correct Answer: B — Fringe width increases
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Q. What is the condition for the first minimum in single-slit diffraction?
A.
a = λ
B.
a = 2λ
C.
a = λ/2
D.
a = 3λ
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Solution
The first minimum occurs at a = λ, where 'a' is the slit width and 'λ' is the wavelength.
Correct Answer: A — a = λ
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Q. What is the effect of increasing the number of slits in a diffraction grating on the sharpness of the maxima?
A.
Maxima become sharper
B.
Maxima become broader
C.
No effect on sharpness
D.
Maxima disappear
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Solution
Increasing the number of slits in a diffraction grating results in sharper maxima due to increased constructive interference.
Correct Answer: A — Maxima become sharper
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Q. What is the effect of increasing the slit width in single-slit diffraction?
A.
Increases the width of the central maximum
B.
Decreases the width of the central maximum
C.
No effect on the central maximum
D.
Increases the intensity of the central maximum
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Solution
Increasing the slit width decreases the width of the central maximum due to the diffraction pattern becoming narrower.
Correct Answer: B — Decreases the width of the central maximum
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Q. What is the effect of increasing the wavelength of light in a diffraction grating experiment?
A.
Fringe spacing decreases
B.
Fringe spacing increases
C.
No effect on fringe spacing
D.
Fringe intensity increases
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Solution
Increasing the wavelength of light increases the fringe spacing in a diffraction grating experiment.
Correct Answer: B — Fringe spacing increases
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Q. What is the effect of increasing the wavelength of light in a diffraction pattern?
A.
Fringe spacing decreases
B.
Fringe spacing increases
C.
No effect on fringe spacing
D.
Fringe intensity increases
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Solution
Increasing the wavelength of light increases the fringe spacing in a diffraction pattern.
Correct Answer: B — Fringe spacing increases
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Q. What is the effect of increasing the wavelength of light in a double-slit diffraction experiment?
A.
Fringe separation decreases
B.
Fringe separation increases
C.
No effect on fringe separation
D.
Fringe visibility decreases
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Solution
Increasing the wavelength increases the fringe separation, as it is directly proportional to the wavelength.
Correct Answer: B — Fringe separation increases
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Q. What is the effect of increasing the wavelength of light on the diffraction pattern produced by a single slit?
A.
The pattern becomes sharper
B.
The pattern becomes broader
C.
The pattern remains unchanged
D.
The pattern disappears
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Solution
Increasing the wavelength results in a broader diffraction pattern due to increased spreading of the waves.
Correct Answer: B — The pattern becomes broader
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Q. What is the effect of increasing the wavelength on the diffraction pattern of a single slit?
A.
Fringes become narrower
B.
Fringes become wider
C.
Fringes disappear
D.
Fringes become brighter
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Solution
Increasing the wavelength results in wider fringes in the diffraction pattern, as the angular width of the central maximum increases.
Correct Answer: B — Fringes become wider
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Q. What is the effect of increasing the wavelength on the diffraction pattern?
A.
Fringes become narrower
B.
Fringes become wider
C.
No effect
D.
Fringes disappear
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Solution
Increasing the wavelength results in wider fringes in the diffraction pattern, as fringe width is directly proportional to the wavelength.
Correct Answer: B — Fringes become wider
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Q. What is the formula for the angular position of the first minimum in a double-slit diffraction pattern?
A.
d sin(θ) = mλ
B.
d sin(θ) = (m + 1/2)λ
C.
d sin(θ) = (m - 1/2)λ
D.
d sin(θ) = 2mλ
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Solution
The angular position of the first minimum in a double-slit diffraction pattern is given by d sin(θ) = mλ, where m = 1 for the first minimum.
Correct Answer: A — d sin(θ) = mλ
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Q. What is the formula for the angular position of the m-th order maximum in a double-slit experiment?
A.
d sin θ = mλ
B.
d cos θ = mλ
C.
d tan θ = mλ
D.
d = mλ/sin θ
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Solution
The correct formula for the angular position of the m-th order maximum is d sin θ = mλ.
Correct Answer: A — d sin θ = mλ
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Q. What is the main difference between diffraction and interference?
A.
Diffraction involves multiple sources, interference does not
B.
Interference involves multiple sources, diffraction does not
C.
Diffraction occurs with sound waves only
D.
Interference occurs with light waves only
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Solution
Interference involves the superposition of waves from multiple sources, while diffraction is the spreading of waves when they encounter an obstacle or aperture.
Correct Answer: B — Interference involves multiple sources, diffraction does not
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Q. What is the main reason for the appearance of a diffraction pattern when light passes through a narrow slit?
A.
Interference of light waves
B.
Refraction of light
C.
Absorption of light
D.
Reflection of light
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Solution
The diffraction pattern arises due to the interference of light waves that spread out after passing through the slit.
Correct Answer: A — Interference of light waves
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Q. What is the maximum number of diffraction maxima that can be observed for a double-slit experiment with a slit separation of 0.1 mm and light of wavelength 500 nm?
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Solution
The maximum number of observable maxima is given by d/λ, where d = 0.1 mm and λ = 500 nm. This gives approximately 10 maxima.
Correct Answer: B — 10
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Q. What is the phenomenon of diffraction primarily associated with?
A.
Reflection of light
B.
Bending of waves around obstacles
C.
Interference of waves
D.
Polarization of light
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Solution
Diffraction is the bending of waves around obstacles and the spreading of waves when they pass through small openings.
Correct Answer: B — Bending of waves around obstacles
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Q. What is the phenomenon of diffraction primarily responsible for?
A.
Bending of light around obstacles
B.
Reflection of light
C.
Refraction of light
D.
Polarization of light
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Solution
Diffraction is the bending of waves around obstacles and the spreading of waves when they pass through small openings.
Correct Answer: A — Bending of light around obstacles
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Q. What is the primary reason for the occurrence of diffraction in waves?
A.
Wave interference
B.
Wave reflection
C.
Wave refraction
D.
Wave nature of light
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Solution
Diffraction occurs due to the wave nature of light, allowing it to bend around obstacles and spread out.
Correct Answer: D — Wave nature of light
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Q. What is the primary reason for the occurrence of diffraction?
A.
The wave nature of light
B.
The particle nature of light
C.
The speed of light
D.
The frequency of light
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Solution
Diffraction occurs due to the wave nature of light, allowing it to bend around obstacles.
Correct Answer: A — The wave nature of light
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Q. What is the relationship between the number of slits in a diffraction grating and the sharpness of the maxima?
A.
More slits, sharper maxima
B.
More slits, broader maxima
C.
No relationship
D.
Fewer slits, sharper maxima
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Solution
Increasing the number of slits in a diffraction grating results in sharper maxima due to increased constructive interference.
Correct Answer: A — More slits, sharper maxima
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