Q. What is the molecular formula of fructose?
A.
C6H12O6
B.
C5H10O5
C.
C6H10O5
D.
C5H12O6
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Solution
Fructose has the same molecular formula as glucose, which is C6H12O6.
Correct Answer: A — C6H12O6
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Q. What is the molecular formula of hydrogen peroxide?
A.
H2O
B.
H2O2
C.
H2
D.
O2
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Solution
Hydrogen peroxide has the molecular formula H2O2.
Correct Answer: B — H2O2
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Q. What is the molecular formula of water?
A.
H2O
B.
H2O2
C.
HO
D.
H2
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Solution
The molecular formula of water is H2O.
Correct Answer: A — H2O
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Q. What is the molecular geometry of ammonia (NH3)?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Trigonal pyramidal
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Solution
Ammonia has a trigonal pyramidal geometry due to the presence of a lone pair on nitrogen.
Correct Answer: D — Trigonal pyramidal
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Q. What is the molecular geometry of BF3 according to VSEPR theory?
A.
Trigonal planar
B.
Tetrahedral
C.
Octahedral
D.
Linear
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Solution
BF3 has three bonding pairs and no lone pairs, resulting in a trigonal planar geometry.
Correct Answer: A — Trigonal planar
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Q. What is the molecular geometry of BF3?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Bent
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Solution
BF3 has a trigonal planar geometry due to the three bonding pairs and no lone pairs on the central atom.
Correct Answer: B — Trigonal planar
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Q. What is the molecular geometry of CH4 according to VSEPR theory?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Octahedral
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Solution
According to VSEPR theory, CH4 has four bonding pairs and no lone pairs, resulting in a tetrahedral geometry.
Correct Answer: C — Tetrahedral
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Q. What is the molecular geometry of CH4?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Octahedral
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Solution
CH4 has a tetrahedral geometry due to four bonding pairs around the central carbon atom.
Correct Answer: C — Tetrahedral
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Q. What is the molecular geometry of methane (CH4)?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Octahedral
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Solution
Methane has a tetrahedral molecular geometry due to sp3 hybridization of the carbon atom.
Correct Answer: C — Tetrahedral
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Q. What is the molecular geometry of NH3 according to VSEPR theory?
A.
Trigonal planar
B.
Tetrahedral
C.
Bent
D.
Trigonal pyramidal
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Solution
NH3 has three bonding pairs and one lone pair, resulting in a trigonal pyramidal geometry.
Correct Answer: D — Trigonal pyramidal
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Q. What is the molecular geometry of SF4?
A.
Tetrahedral
B.
Trigonal bipyramidal
C.
Seesaw
D.
Square planar
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Solution
SF4 has four bonding pairs and one lone pair, resulting in a seesaw molecular geometry.
Correct Answer: C — Seesaw
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Q. What is the molecular geometry of SO2?
A.
Linear
B.
Trigonal planar
C.
Bent
D.
Tetrahedral
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Solution
SO2 has two bonding pairs and one lone pair, resulting in a bent molecular geometry.
Correct Answer: C — Bent
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Q. What is the molecular geometry of the molecule with the electronic configuration of 1s2 2s2 2p2?
A.
Linear
B.
Trigonal Planar
C.
Tetrahedral
D.
Octahedral
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Solution
The electronic configuration corresponds to C2, which has a tetrahedral geometry due to sp3 hybridization.
Correct Answer: C — Tetrahedral
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Q. What is the molecular orbital configuration of F2?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(π2p)⁴(π*2p)²
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³(π*2p)²
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Solution
The correct configuration for F2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)².
Correct Answer: A — (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
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Q. What is the molecular orbital configuration of O2?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)²
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)⁴
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Solution
The correct configuration for O2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹.
Correct Answer: A — (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
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Q. What is the molecular orbital configuration of the F2 molecule?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)⁴
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)¹
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³(π*2p)²
Show solution
Solution
The correct configuration for F2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)².
Correct Answer: A — (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
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Q. What is the molecular orbital configuration of the O2 molecule?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)²
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)¹(π*2p)¹
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)¹(π*2p)²
Show solution
Solution
The correct configuration for O2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹.
Correct Answer: A — (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
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Q. What is the molecular shape of a molecule with the formula AX3E?
A.
Trigonal planar
B.
Tetrahedral
C.
Trigonal pyramidal
D.
Bent
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Solution
AX3E indicates three bonding pairs and one lone pair, resulting in a trigonal pyramidal shape.
Correct Answer: C — Trigonal pyramidal
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Q. What is the molecular shape of BF3 according to VSEPR theory?
A.
Bent
B.
Trigonal planar
C.
Tetrahedral
D.
Octahedral
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Solution
BF3 has three bonding pairs and no lone pairs, resulting in a trigonal planar shape.
Correct Answer: B — Trigonal planar
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Q. What is the molecular shape of NH3 according to VSEPR theory?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Trigonal pyramidal
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Solution
NH3 has three bonding pairs and one lone pair, resulting in a trigonal pyramidal shape.
Correct Answer: D — Trigonal pyramidal
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Q. What is the molecular weight of water (H2O)?
A.
16 g/mol
B.
18 g/mol
C.
20 g/mol
D.
22 g/mol
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Solution
The molecular weight of water is calculated as (2*1) + (16) = 18 g/mol.
Correct Answer: B — 18 g/mol
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Q. What is the name of the reaction where benzene is converted to phenol?
A.
Hydrogenation
B.
Nitration
C.
Sulfonation
D.
Hydroxylation
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Solution
The conversion of benzene to phenol is known as hydroxylation, typically involving the addition of a hydroxyl group (-OH) to the aromatic ring.
Correct Answer: D — Hydroxylation
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Q. What is the Nernst equation used for?
A.
Calculating pH
B.
Determining cell potential
C.
Finding molarity
D.
Measuring temperature
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Solution
The Nernst equation is used to determine the cell potential under non-standard conditions.
Correct Answer: B — Determining cell potential
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Q. What is the normality of a solution containing 1 mole of H2SO4 in 1 liter of solution?
A.
1 N
B.
2 N
C.
0.5 N
D.
4 N
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Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 provides 2 equivalents, so N = 2 moles / 1 L = 2 N.
Correct Answer: B — 2 N
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Q. What is the normality of a solution containing 2 moles of H2SO4 in 1 liter of solution?
A.
2 N
B.
4 N
C.
1 N
D.
0.5 N
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Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 provides 2 equivalents, so 2 moles × 2 = 4 N.
Correct Answer: B — 4 N
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Q. What is the normality of a solution containing 3 moles of H2SO4 in 2 liters of solution? (H2SO4 is a diprotic acid)
A.
3 N
B.
6 N
C.
1.5 N
D.
1 N
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Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 has 2 equivalents per mole, so 3 moles = 6 equivalents. Normality = 6 equivalents / 2 L = 3 N.
Correct Answer: B — 6 N
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Q. What is the normality of a solution containing 4 moles of H2SO4 in 2 liters of solution? (H2SO4 is a diprotic acid)
A.
4 N
B.
2 N
C.
8 N
D.
1 N
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Solution
Normality (N) = number of equivalents / liters of solution. H2SO4 has 2 equivalents per mole, so 4 moles = 8 equivalents. Normality = 8 equivalents / 2 L = 4 N.
Correct Answer: C — 8 N
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Q. What is the normality of a solution containing 4 moles of H2SO4 in 2 liters of solution?
A.
4 N
B.
8 N
C.
2 N
D.
1 N
Show solution
Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 has 2 equivalents, so 4 moles = 8 equivalents. N = 8 eq / 2 L = 4 N.
Correct Answer: B — 8 N
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Q. What is the normality of a solution that is 1 M in H2SO4?
A.
1 N
B.
2 N
C.
0.5 N
D.
4 N
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Solution
Normality (N) = Molarity (M) x number of equivalents. H2SO4 has 2 acidic protons, so 1 M x 2 = 2 N.
Correct Answer: B — 2 N
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Q. What is the number of atoms in 2 moles of aluminum (Al)? (2044)
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
3.011 x 10^23
D.
12.044 x 10^24
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Solution
Number of atoms = moles x Avogadro's number = 2 moles x 6.022 x 10^23 atoms/mole = 1.2044 x 10^24 atoms.
Correct Answer: B — 1.2044 x 10^24
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