Q. In the reaction 2H2 + O2 → 2H2O, how many grams of oxygen are required to completely react with 4 grams of hydrogen?
A.
16 g
B.
8 g
C.
32 g
D.
4 g
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Solution
4 g of H2 = 2 moles. 1 mole of O2 is needed for 2 moles of H2, so 1 mole of O2 = 32 g is required.
Correct Answer: B — 8 g
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Q. In the reaction 2H2 + O2 → 2H2O, how many grams of oxygen are required to react with 4 grams of hydrogen?
A.
16 g
B.
8 g
C.
4 g
D.
2 g
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Solution
First, calculate moles of H2: 4 g / 2 g/mol = 2 moles. From the reaction, 2 moles of H2 require 1 mole of O2. Therefore, 2 moles of O2 = 32 g.
Correct Answer: B — 8 g
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Q. In the reaction 2H2 + O2 → 2H2O, how many grams of water are produced from 4 grams of hydrogen?
A.
18 g
B.
36 g
C.
54 g
D.
72 g
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Solution
4 grams of H2 is 2 moles (4 g / 2 g/mol). According to the equation, 2 moles of H2 produce 2 moles of H2O, which is 36 g (2 moles x 18 g/mol).
Correct Answer: B — 36 g
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Q. In the reaction 2H2 + O2 → 2H2O, how many grams of water can be produced from 4 grams of hydrogen?
A.
36 g
B.
18 g
C.
72 g
D.
9 g
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Solution
4 g of H2 = 2 moles. 2 moles of H2 produce 2 moles of H2O = 2 * 18 g = 36 g.
Correct Answer: A — 36 g
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Q. In the reaction 2H2 + O2 → 2H2O, how many liters of H2O vapor are produced from 4 liters of H2?
A.
4 L
B.
8 L
C.
2 L
D.
6 L
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Solution
4 L of H2 produces 4 L of H2O vapor at STP.
Correct Answer: B — 8 L
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Q. In the reaction 2H2 + O2 → 2H2O, how many liters of water vapor are produced from 4 liters of hydrogen at STP?
A.
4 L
B.
8 L
C.
2 L
D.
6 L
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Solution
4 L of H2 produces 4 L of H2O since the ratio is 1:1.
Correct Answer: B — 8 L
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Q. In the reaction 2H2 + O2 → 2H2O, how many moles of O2 are required to completely react with 6 moles of H2?
A.
2 moles
B.
3 moles
C.
4 moles
D.
6 moles
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Solution
From the balanced equation, 2 moles of H2 require 1 mole of O2. Therefore, 6 moles of H2 will require (6/2) = 3 moles of O2.
Correct Answer: B — 3 moles
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Q. In the reaction 2H2 + O2 → 2H2O, how many moles of O2 are required to react with 6 moles of H2?
A.
3 moles
B.
4 moles
C.
6 moles
D.
2 moles
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Solution
According to the stoichiometry of the reaction, 2 moles of H2 require 1 mole of O2. Therefore, 6 moles of H2 will require (6/2) = 3 moles of O2.
Correct Answer: A — 3 moles
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Q. In the reaction 2H2 + O2 → 2H2O, how many moles of water are produced from 4 moles of hydrogen?
A.
2 moles
B.
4 moles
C.
6 moles
D.
8 moles
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Solution
According to the stoichiometry of the reaction, 2 moles of H2 produce 2 moles of H2O. Therefore, 4 moles of H2 will produce 4 moles of H2O.
Correct Answer: B — 4 moles
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Q. In the reaction 2H2 + O2 → 2H2O, if 3 moles of O2 are available, how many moles of H2 are required?
A.
3 moles
B.
6 moles
C.
1.5 moles
D.
4.5 moles
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Solution
According to the stoichiometry, 1 mole of O2 requires 2 moles of H2. Therefore, 3 moles of O2 will require 3 x 2 = 6 moles of H2.
Correct Answer: B — 6 moles
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Q. In the reaction 2H2 + O2 → 2H2O, if you start with 3 moles of O2, how many moles of H2 are required?
A.
3 moles
B.
6 moles
C.
1.5 moles
D.
4 moles
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Solution
According to the stoichiometry, 1 mole of O2 requires 2 moles of H2. Therefore, 3 moles of O2 will require 6 moles of H2.
Correct Answer: B — 6 moles
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Q. In the reaction 2H2 + O2 → 2H2O, what is the ratio of moles of hydrogen to moles of oxygen?
A.
1:1
B.
2:1
C.
2:2
D.
1:2
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Solution
The balanced equation shows that 2 moles of H2 react with 1 mole of O2, giving a ratio of 2:1.
Correct Answer: B — 2:1
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Q. In the reaction 2Na + Cl2 → 2NaCl, how many grams of NaCl can be produced from 5 g of Na?
A.
10 g
B.
15 g
C.
20 g
D.
25 g
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Solution
5 g of Na = 0.217 moles. 2 moles of Na produce 2 moles of NaCl, so 0.217 moles of NaCl = 0.217 * 58.5 g = 12.7 g.
Correct Answer: A — 10 g
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Q. In the reaction 3A + 2B → 4C, if 6 moles of A are used, how many moles of C will be produced?
A.
4 moles
B.
6 moles
C.
8 moles
D.
12 moles
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Solution
From the stoichiometry, 3 moles of A produce 4 moles of C. Therefore, 6 moles of A will produce (6 moles A) x (4 moles C / 3 moles A) = 8 moles of C.
Correct Answer: C — 8 moles
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Q. In the reaction 3H2 + N2 → 2NH3, how many moles of nitrogen are required to produce 6 moles of ammonia?
A.
3 moles
B.
2 moles
C.
1 mole
D.
4 moles
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Solution
According to the stoichiometry, 2 moles of NH3 require 1 mole of N2. Therefore, 6 moles of NH3 will require 3 moles of N2.
Correct Answer: A — 3 moles
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Q. In the reaction 4Al + 3O2 → 2Al2O3, how many moles of Al2O3 are produced from 12 moles of Al?
A.
2 moles
B.
3 moles
C.
6 moles
D.
8 moles
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Solution
According to the stoichiometry, 4 moles of Al produce 2 moles of Al2O3. Therefore, 12 moles of Al will produce (12/4) x 2 = 6 moles of Al2O3.
Correct Answer: C — 6 moles
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Q. In the reaction 4Fe + 3O2 → 2Fe2O3, how many grams of Fe2O3 can be produced from 8 grams of Fe?
A.
16 g
B.
32 g
C.
48 g
D.
24 g
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Solution
8 g of Fe = 0.143 moles. 4 moles of Fe produce 2 moles of Fe2O3, so 0.0715 moles of Fe2O3 = 0.0715 * 160 g = 11.44 g.
Correct Answer: C — 48 g
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Q. In the reaction 4Fe + 3O2 → 2Fe2O3, how many moles of Fe are required to react with 6 moles of O2?
A.
4 moles
B.
6 moles
C.
8 moles
D.
12 moles
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Solution
From the balanced equation, 3 moles of O2 react with 4 moles of Fe. Therefore, 6 moles of O2 will require (4/3) * 6 = 8 moles of Fe.
Correct Answer: C — 8 moles
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Q. In the reaction 4Fe + 3O2 → 2Fe2O3, how many moles of Fe2O3 are produced from 12 moles of Fe?
A.
2 moles
B.
3 moles
C.
4 moles
D.
6 moles
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Solution
From the balanced equation, 4 moles of Fe produce 2 moles of Fe2O3. Therefore, 12 moles of Fe will produce (12/4) x 2 = 6 moles of Fe2O3.
Correct Answer: C — 4 moles
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Q. In the reaction 4Fe + 3O2 → 2Fe2O3, how many moles of Fe2O3 can be produced from 8 moles of Fe?
A.
2 moles
B.
4 moles
C.
6 moles
D.
8 moles
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Solution
From the balanced equation, 4 moles of Fe produce 2 moles of Fe2O3. Therefore, 8 moles of Fe will produce 4 moles of Fe2O3.
Correct Answer: B — 4 moles
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Q. In the reaction 4Fe + 3O2 → 2Fe2O3, how many moles of Fe2O3 can be produced from 12 moles of Fe?
A.
3 moles
B.
6 moles
C.
9 moles
D.
12 moles
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Solution
From the stoichiometry, 4 moles of Fe produce 2 moles of Fe2O3. Therefore, 12 moles of Fe will produce (12/4) x 2 = 6 moles of Fe2O3.
Correct Answer: B — 6 moles
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Q. What is the empirical formula of a compound containing 40% carbon, 6.7% hydrogen, and 53.3% oxygen by mass?
A.
CH2O
B.
C2H4O2
C.
C3H6O3
D.
C4H8O4
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Solution
Convert percentages to grams (assume 100 g total): 40 g C, 6.7 g H, 53.3 g O. Convert to moles: C=3.33, H=6.67, O=3.33. The simplest ratio is 1:2:1, giving CH2O.
Correct Answer: A — CH2O
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Q. What is the empirical formula of a compound containing 40% carbon, 6.7% hydrogen, and 53.3% oxygen?
A.
CH2O
B.
C2H4O2
C.
C3H6O3
D.
C4H8O4
Show solution
Solution
Converting percentages to moles gives C: 40/12 = 3.33, H: 6.7/1 = 6.7, O: 53.3/16 = 3.33. The simplest ratio is 1:2:1, giving the empirical formula CH2O.
Correct Answer: A — CH2O
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Q. What is the empirical formula of C6H12O6?
A.
C2H4O2
B.
CH2O
C.
C3H6O3
D.
C6H12O6
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Solution
The empirical formula is the simplest whole number ratio, which is CH2O.
Correct Answer: B — CH2O
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Q. What is the empirical formula of glucose (C6H12O6)?
A.
C6H12O6
B.
CH2O
C.
C3H6O3
D.
C2H4O2
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Solution
The empirical formula is the simplest whole number ratio of the elements in a compound. For glucose, it is CH2O.
Correct Answer: B — CH2O
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Q. What is the formula for calculating the number of moles?
A.
Moles = Mass / Volume
B.
Moles = Mass x Volume
C.
Moles = Mass / Molar Mass
D.
Moles = Molar Mass / Mass
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Solution
The number of moles is calculated using the formula: Moles = Mass / Molar Mass.
Correct Answer: C — Moles = Mass / Molar Mass
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Q. What is the limiting reagent when 3 moles of A react with 2 moles of B to produce 4 moles of C?
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Solution
The reaction requires 1.5 moles of B for 3 moles of A. Since only 2 moles of B are available, B is the limiting reagent.
Correct Answer: B — B
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Q. What is the limiting reagent when 5 moles of A react with 3 moles of B in the reaction A + 2B → C?
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Solution
The reaction requires 2 moles of B for every mole of A. For 5 moles of A, 10 moles of B are needed. Since only 3 moles of B are available, B is the limiting reagent.
Correct Answer: B — B
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Q. What is the main component of air?
A.
Oxygen
B.
Nitrogen
C.
Carbon Dioxide
D.
Argon
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Solution
Nitrogen makes up about 78% of the Earth's atmosphere, making it the main component of air.
Correct Answer: B — Nitrogen
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Q. What is the main component of natural gas?
A.
Ethane
B.
Propane
C.
Methane
D.
Butane
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Solution
The main component of natural gas is methane (CH4).
Correct Answer: C — Methane
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