Molar mass of H2 = 2 g/mol. Number of moles = 10g/2g/mol = 5 moles.

Moles = Molarity x Volume (L) = 2 M x 0.250 L = 0.5 moles.

The molar mass of CO2 is 44 g/mol. Therefore, 44 g of CO2 corresponds to 1 mole.

Molar mass of CO2 = 12 + 16*2 = 44 g/mol. Number of moles = mass/molar mass = 44g/44g/mol = 1 mole.

Moles = Molarity x Volume (L) = 2 moles/L x 0.5 L = 1 mole.

Osmotic pressure (π) = nRT/V = (0.1 mol)(0.0821 L atm/K mol)(298 K) = 2.06 atm.

Osmotic pressure (π) = nRT/V = (0.5 moles * 0.0821 L·atm/(K·mol) * 298 K) / 1 L = 12.3 atm.

Osmotic pressure (π) = iCRT = 1 * 2 * 0.0821 * 298 = 4.0 atm (i = 1 for glucose).

The outermost layer of a plant stem is called the epidermis, which protects the plant from environmental damage.

The outermost whorl of a flower is called the calyx, which is made up of sepals.

In NaClO3, the oxidation state of chlorine is +5. Sodium is +1 and each oxygen is -2, leading to the equation: +1 + x + 3(-2) = 0, solving gives x = +5.

In K2Cr2O7, the total charge from potassium (K) is +2, and oxygen (O) contributes -14. Let the oxidation state of Cr be x. The equation is 2x - 14 + 2 = 0, solving gives x = +6.

In NH4+, nitrogen has an oxidation state of -3. Each hydrogen is +1, leading to the equation: x + 4(+1) = +1, solving gives x = -3.

In NH4Cl, the oxidation state of nitrogen is -3, as it is bonded to four hydrogens.

In H3PO4, phosphorus has an oxidation state of +5.

In H2SO4, the oxidation state of sulfur is +6. Each hydrogen is +1 and each oxygen is -2, leading to the equation: 2(+1) + x + 4(-2) = 0, solving gives x = +6.

In H2SO4, the oxidation state of sulfur is +6.

The packing efficiency of a body-centered cubic (BCC) structure is approximately 68%.

The general solution is y = Ce^(4x). Using the initial condition y(0) = 2, we find C = 2, thus y = 2e^(4x).

The peak voltage (V_peak) is related to the RMS voltage (V_rms) by the formula V_peak = V_rms × √2. Therefore, V_peak = 220 V × √2 ≈ 311 V.

The peak voltage (V_peak) is related to the RMS voltage (V_rms) by the formula V_peak = V_rms × √2. Therefore, V_peak = 220 V × √2 ≈ 311 V.

Percentage by mass = (mass of solute / total mass) × 100 = (15 g / (15 g + 85 g)) × 100 = 17.65%.

Percentage concentration = (mass of solute / mass of solution) × 100 = (15 g / 150 g) × 100 = 10%

Percentage concentration = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.

Percentage error = (|Measured - True| / True) × 100 = (|20.0 - 19.5| / 19.5) × 100 ≈ 2.56%.

Percentage error = |(True value - Measured value) / True value| * 100 = |(50 - 48) / 50| * 100 = 4%.

Argon is located in Period 3 of the periodic table.

Lithium is located in period 2 of the periodic table.

Lithium is located in period 2 of the periodic table.

Sodium is in period 3 of the periodic table.