Current Electricity
Q. In a circuit with a 5Ω and a 10Ω resistor in parallel, what is the total current if the voltage across them is 20V? (2022)
Solution
First, find the equivalent resistance: 1/R_eq = 1/5 + 1/10 = 3/10, R_eq = 10/3Ω. Then, I = V/R_eq = 20V / (10/3)Ω = 6A.
Correct Answer: A — 4A
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the current flowing through the resistor? (2023)
Solution
Using Ohm's law, I = V/R = 9V / 3Ω = 3A.
Correct Answer: B — 2A
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated by the resistor? (2021)
Solution
Power is given by P = V²/R = (9V)² / 3Ω = 81V² / 3Ω = 27W.
Correct Answer: B — 9W
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated in the resistor? (2023)
Solution
Power P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.
Correct Answer: B — 9W
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Q. In a circuit, if the current is doubled while the resistance remains constant, what happens to the power consumed? (2020)
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A.
It doubles
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B.
It triples
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C.
It remains the same
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D.
It halves
Solution
Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which means power quadruples.
Correct Answer: A — It doubles
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Q. In a circuit, if the resistance is halved while the voltage remains constant, what happens to the current? (2022)
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A.
It halves
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B.
It doubles
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C.
It remains the same
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D.
It quadruples
Solution
According to Ohm's law, I = V/R. If R is halved, I will double.
Correct Answer: B — It doubles
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Q. In a circuit, if the voltage is doubled and the resistance remains constant, what happens to the current? (2020)
-
A.
Doubles
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B.
Halves
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C.
Remains the same
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D.
Quadruples
Solution
According to Ohm's law, I = V/R. If V is doubled, I also doubles.
Correct Answer: A — Doubles
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Q. In a parallel circuit with two resistors of 6Ω and 3Ω, what is the total current if a 12V battery is connected? (2021)
Solution
First, find the equivalent resistance: 1/R_eq = 1/6 + 1/3 = 1/2, so R_eq = 2Ω. Then, I = V/R_eq = 12V / 2Ω = 6A.
Correct Answer: C — 6A
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Q. In a parallel circuit with two resistors of 6Ω and 3Ω, what is the total resistance? (2019)
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A.
2Ω
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B.
4Ω
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C.
1.5Ω
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D.
9Ω
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, thus R_eq = 2Ω.
Correct Answer: B — 4Ω
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Q. In a parallel circuit, if one branch has a resistance of 4Ω and another has 8Ω, what is the equivalent resistance? (2020)
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A.
2.67Ω
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B.
3Ω
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C.
4Ω
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D.
6Ω
Solution
1/R_eq = 1/4 + 1/8 = 2/8 + 1/8 = 3/8, so R_eq = 8/3Ω ≈ 2.67Ω.
Correct Answer: A — 2.67Ω
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Q. What is the current through a 10Ω resistor connected to a 20V battery? (2020)
Solution
Using Ohm's law, I = V/R = 20V / 10Ω = 2A.
Correct Answer: B — 2A
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Q. What is the current through a 12Ω resistor connected to a 24V battery? (2023)
Solution
Using Ohm's law, I = V/R = 24V / 12Ω = 2A.
Correct Answer: B — 2A
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Q. What is the current through a 12Ω resistor when a voltage of 48V is applied? (2023)
Solution
Using Ohm's law, I = V/R = 48V / 12Ω = 4A.
Correct Answer: B — 6A
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Q. What is the current through a 15Ω resistor connected to a 45V source? (2021)
Solution
Using Ohm's law, I = V/R = 45V / 15Ω = 3A.
Correct Answer: A — 3A
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Q. What is the effect on the total resistance in a series circuit if one resistor is removed? (2023)
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A.
Increases
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B.
Decreases
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C.
Remains the same
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D.
Becomes zero
Solution
Removing a resistor from a series circuit decreases the total resistance since the sum of the remaining resistances is less.
Correct Answer: B — Decreases
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Q. What is the equivalent resistance of two 4Ω resistors in parallel? (2019)
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/4 + 1/4 = 1/2, thus R_eq = 2Ω.
Correct Answer: A — 2Ω
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Q. What is the equivalent resistance of two resistors of 4Ω and 12Ω in parallel? (2022)
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/4 + 1/12 = 1/3, so R_eq = 3Ω.
Correct Answer: A — 3Ω
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Q. What is the potential difference across a 5Ω resistor carrying a current of 2A? (2023)
Solution
Using Ohm's law, V = IR = 2A * 5Ω = 10V.
Correct Answer: A — 10V
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Q. What is the power consumed by a 6Ω resistor when a current of 2A flows through it? (2023)
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A.
12W
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B.
24W
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C.
6W
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D.
8W
Solution
Power (P) is given by P = I²R = (2A)² * 6Ω = 4 * 6 = 24W.
Correct Answer: A — 12W
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Q. What is the power consumed by a 6Ω resistor when a current of 3A flows through it? (2021)
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A.
18W
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B.
9W
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C.
36W
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D.
12W
Solution
Power (P) is given by P = I^2 * R = (3A)^2 * 6Ω = 9 * 6 = 54W.
Correct Answer: A — 18W
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Q. What is the total current flowing through a circuit with a 9V battery and a total resistance of 3Ω? (2022)
Solution
Using Ohm's law, I = V/R = 9V / 3Ω = 3A.
Correct Answer: B — 2A
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Q. What is the total current in a circuit with a 15V battery and two 5Ω resistors in series? (2023)
Solution
Total resistance R = 5Ω + 5Ω = 10Ω; I = V/R = 15V / 10Ω = 1.5A.
Correct Answer: B — 2A
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Q. What is the total current in a parallel circuit with two branches carrying 3A and 5A? (2020)
Solution
In a parallel circuit, the total current (I_total) is the sum of the currents in each branch: I_total = 3A + 5A = 8A.
Correct Answer: A — 8A
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Q. What is the total power consumed in a circuit with two 10Ω resistors in series connected to a 20V source? (2020)
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A.
20W
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B.
40W
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C.
10W
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D.
30W
Solution
Total resistance R = 10Ω + 10Ω = 20Ω. Power P = V²/R = 20² / 20 = 20W.
Correct Answer: B — 40W
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Q. What is the total power consumed in a circuit with two 5Ω resistors in series connected to a 30V battery? (2023)
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A.
90W
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B.
60W
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C.
30W
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D.
45W
Solution
Total resistance R = 5Ω + 5Ω = 10Ω; Power P = V²/R = 30²/10 = 90W.
Correct Answer: B — 60W
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Q. What is the total resistance in a circuit with a 10Ω resistor and a 20Ω resistor in series? (2022)
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A.
30Ω
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B.
20Ω
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C.
10Ω
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D.
15Ω
Solution
In series, R_eq = R1 + R2 = 10Ω + 20Ω = 30Ω.
Correct Answer: A — 30Ω
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Q. What is the total resistance of two resistors of 4Ω and 6Ω connected in parallel? (2021)
-
A.
2.4Ω
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B.
10Ω
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C.
24Ω
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D.
1.5Ω
Solution
For parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/4 + 1/6. Finding a common denominator gives R_eq = 2.4Ω.
Correct Answer: A — 2.4Ω
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Q. What is the voltage across a 10Ω resistor carrying a current of 3A? (2022)
-
A.
30V
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B.
20V
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C.
10V
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D.
15V
Solution
Using Ohm's law, V = IR = 3A * 10Ω = 30V.
Correct Answer: A — 30V
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Q. What is the voltage across a 12Ω resistor carrying a current of 1.5A? (2023)
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A.
18V
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B.
12V
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C.
6V
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D.
24V
Solution
Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.
Correct Answer: A — 18V
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Q. What is the voltage across a 12Ω resistor carrying a current of 3A? (2023)
-
A.
36V
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B.
24V
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C.
12V
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D.
18V
Solution
Using Ohm's law, V = IR = 3A * 12Ω = 36V.
Correct Answer: A — 36V
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