0.1 M K2SO4 will exhibit the greatest freezing point depression due to its van 't Hoff factor of 3.

CaCl2 dissociates into three ions (Ca2+ and 2 Cl-), leading to the greatest vapor pressure lowering among the options.

The 0.1 M NaCl solution will exhibit the lowest vapor pressure due to the presence of more solute particles (2 ions per formula unit).

C6H12O6 does not dissociate, while the others do, leading to higher boiling points.

0.1 m MgCl2 produces 3 particles (Mg2+ and 2 Cl-), leading to the lowest freezing point among the options.

0.1 M CaCl2 produces the most particles in solution (3 ions), leading to the lowest vapor pressure.

Raoult's Law applies most accurately to ideal solutions, where interactions between different molecules are similar to those in pure substances.