Q. If 5 moles of KCl are dissolved in 3 kg of water, what is the molality of the solution?
A.
1.67 m
B.
2.5 m
C.
1.25 m
D.
0.5 m
Show solution
Solution
Molality (m) = moles of solute / kg of solvent = 5 moles / 3 kg = 1.67 m.
Correct Answer: A — 1.67 m
Learn More →
Q. If 50 g of KCl is dissolved in 250 mL of solution, what is the molarity? (Molar mass of KCl = 74.5 g/mol)
A.
2.68 M
B.
1.34 M
C.
0.67 M
D.
0.25 M
Show solution
Solution
Moles of KCl = 50 g / 74.5 g/mol = 0.672 moles. Molarity = 0.672 moles / 0.25 L = 2.688 M.
Correct Answer: B — 1.34 M
Learn More →
Q. If 50 grams of a solute is dissolved in 200 mL of solution, what is the mass/volume percent concentration?
A.
25%
B.
20%
C.
15%
D.
10%
Show solution
Solution
Mass/volume percent = (mass of solute / volume of solution) * 100 = (50 g / 200 mL) * 100 = 25%.
Correct Answer: A — 25%
Learn More →
Q. If 50 grams of NaCl is dissolved in 1 liter of solution, what is the molarity? (Molar mass of NaCl = 58.5 g/mol)
A.
0.85 M
B.
1.0 M
C.
1.5 M
D.
2.0 M
Show solution
Solution
Moles of NaCl = 50 g / 58.5 g/mol = 0.854 moles. Molarity = 0.854 moles / 1 L = 0.854 M.
Correct Answer: B — 1.0 M
Learn More →
Q. If 50 grams of NaOH is dissolved in 1 liter of solution, what is the molarity? (Molar mass of NaOH = 40 g/mol)
A.
1.25 M
B.
2.5 M
C.
0.5 M
D.
1 M
Show solution
Solution
Moles of NaOH = 50 g / 40 g/mol = 1.25 moles. Molarity = 1.25 moles / 1 L = 1.25 M.
Correct Answer: B — 2.5 M
Learn More →
Q. If 50 mL of a 2 M HCl solution is diluted to 200 mL, what is the new molarity?
A.
0.25 M
B.
0.5 M
C.
1 M
D.
2 M
Show solution
Solution
Using the dilution formula M1V1 = M2V2, (2 M)(50 mL) = M2(200 mL) => M2 = 0.5 M.
Correct Answer: B — 0.5 M
Learn More →
Q. What is the concentration in g/L of a solution containing 0.5 moles of KCl in 1.5 L of solution? (Molar mass of KCl = 74.5 g/mol)
A.
24.83 g/L
B.
49.67 g/L
C.
37.25 g/L
D.
50 g/L
Show solution
Solution
Mass of KCl = 0.5 moles × 74.5 g/mol = 37.25 g. Concentration = 37.25 g / 1.5 L = 24.83 g/L.
Correct Answer: B — 49.67 g/L
Learn More →
Q. What is the concentration in molality of a solution made by dissolving 5 moles of solute in 3 kg of solvent?
A.
1.67 m
B.
2 m
C.
1.5 m
D.
2.5 m
Show solution
Solution
Molality (m) = moles of solute / kg of solvent = 5 moles / 3 kg = 1.67 m.
Correct Answer: B — 2 m
Learn More →
Q. What is the concentration in molarity of a solution that contains 0.5 moles of solute in 1.5 liters of solution?
A.
0.33 M
B.
0.5 M
C.
0.75 M
D.
1 M
Show solution
Solution
Molarity (M) = moles of solute / liters of solution = 0.5 moles / 1.5 L = 0.33 M.
Correct Answer: C — 0.75 M
Learn More →
Q. What is the concentration in ppm of a solution containing 1 gram of solute in 1 liter of solution?
A.
1000 ppm
B.
100 ppm
C.
10 ppm
D.
1 ppm
Show solution
Solution
PPM = (mass of solute in grams / volume of solution in liters) * 10^6 = (1 g / 1 L) * 10^6 = 1000 ppm.
Correct Answer: A — 1000 ppm
Learn More →
Q. What is the equivalent weight of H2SO4 if its molar mass is 98 g/mol?
A.
49 g
B.
98 g
C.
196 g
D.
24.5 g
Show solution
Solution
Equivalent weight = molar mass / number of equivalents = 98 g/mol / 2 = 49 g.
Correct Answer: A — 49 g
Learn More →
Q. What is the mass percent of a solution containing 20 g of NaCl in 180 g of water?
A.
10%
B.
20%
C.
25%
D.
15%
Show solution
Solution
Mass percent = (mass of solute / total mass) x 100 = (20 g / (20 g + 180 g)) x 100 = 10%.
Correct Answer: A — 10%
Learn More →
Q. What is the mass percent of a solution containing 20 g of solute in 180 g of solution?
A.
10%
B.
20%
C.
25%
D.
15%
Show solution
Solution
Mass percent = (mass of solute / mass of solution) x 100 = (20 g / 200 g) x 100 = 10%.
Correct Answer: B — 20%
Learn More →
Q. What is the mass percent of a solution containing 20 g of solute in 200 g of solution?
A.
10%
B.
20%
C.
5%
D.
15%
Show solution
Solution
Mass percent = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.
Correct Answer: B — 20%
Learn More →
Q. What is the molality of a solution containing 3 moles of KCl dissolved in 1 kg of water?
A.
3 m
B.
1.5 m
C.
2 m
D.
4 m
Show solution
Solution
Molality (m) = moles of solute / kg of solvent = 3 moles / 1 kg = 3 m.
Correct Answer: A — 3 m
Learn More →
Q. What is the molality of a solution prepared by dissolving 3 moles of KCl in 1 kg of water?
A.
3 m
B.
1.5 m
C.
2 m
D.
4 m
Show solution
Solution
Molality (m) = moles of solute / kg of solvent = 3 moles / 1 kg = 3 m.
Correct Answer: A — 3 m
Learn More →
Q. What is the molarity of a solution if 10 g of glucose (C6H12O6) is dissolved in 250 mL of water? (Molar mass = 180 g/mol)
A.
0.22 M
B.
0.5 M
C.
0.75 M
D.
1 M
Show solution
Solution
Moles of glucose = 10 g / 180 g/mol = 0.0556 moles. Molarity = 0.0556 moles / 0.25 L = 0.222 M.
Correct Answer: A — 0.22 M
Learn More →
Q. What is the molarity of a solution if 10 grams of CaCl2 is dissolved in 250 mL of solution? (Molar mass of CaCl2 = 110 g/mol)
A.
0.25 M
B.
0.5 M
C.
1 M
D.
2 M
Show solution
Solution
Moles of CaCl2 = 10 g / 110 g/mol = 0.0909 moles. Molarity = 0.0909 moles / 0.25 L = 0.3636 M.
Correct Answer: B — 0.5 M
Learn More →
Q. What is the molarity of a solution prepared by dissolving 5 moles of NaCl in 2 liters of water?
A.
2.5 M
B.
5 M
C.
10 M
D.
1 M
Show solution
Solution
Molarity (M) = moles of solute / liters of solution = 5 moles / 2 L = 2.5 M.
Correct Answer: A — 2.5 M
Learn More →
Q. What is the mole fraction of solute in a solution containing 2 moles of solute and 8 moles of solvent?
A.
0.2
B.
0.25
C.
0.5
D.
0.1
Show solution
Solution
Mole fraction of solute = moles of solute / (moles of solute + moles of solvent) = 2 / (2 + 8) = 2 / 10 = 0.2.
Correct Answer: B — 0.25
Learn More →
Q. What is the normality of a solution containing 1 mole of H2SO4 in 1 liter of solution?
A.
1 N
B.
2 N
C.
0.5 N
D.
4 N
Show solution
Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 provides 2 equivalents, so N = 2 moles / 1 L = 2 N.
Correct Answer: B — 2 N
Learn More →
Q. What is the normality of a solution containing 2 moles of H2SO4 in 1 liter of solution?
A.
2 N
B.
4 N
C.
1 N
D.
0.5 N
Show solution
Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 provides 2 equivalents, so 2 moles × 2 = 4 N.
Correct Answer: B — 4 N
Learn More →
Q. What is the normality of a solution containing 3 moles of H2SO4 in 2 liters of solution? (H2SO4 is a diprotic acid)
A.
3 N
B.
6 N
C.
1.5 N
D.
1 N
Show solution
Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 has 2 equivalents per mole, so 3 moles = 6 equivalents. Normality = 6 equivalents / 2 L = 3 N.
Correct Answer: B — 6 N
Learn More →
Q. What is the normality of a solution containing 4 moles of H2SO4 in 2 liters of solution?
A.
4 N
B.
8 N
C.
2 N
D.
1 N
Show solution
Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 has 2 equivalents, so 4 moles = 8 equivalents. N = 8 eq / 2 L = 4 N.
Correct Answer: B — 8 N
Learn More →
Q. What is the normality of a solution containing 4 moles of H2SO4 in 2 liters of solution? (H2SO4 is a diprotic acid)
A.
4 N
B.
2 N
C.
8 N
D.
1 N
Show solution
Solution
Normality (N) = number of equivalents / liters of solution. H2SO4 has 2 equivalents per mole, so 4 moles = 8 equivalents. Normality = 8 equivalents / 2 L = 4 N.
Correct Answer: C — 8 N
Learn More →
Q. What is the normality of a solution that is 1 M in H2SO4?
A.
1 N
B.
2 N
C.
0.5 N
D.
4 N
Show solution
Solution
Normality (N) = Molarity (M) x number of equivalents. H2SO4 has 2 acidic protons, so 1 M x 2 = 2 N.
Correct Answer: B — 2 N
Learn More →
Q. What is the percentage by mass of a solution containing 20 grams of solute in 180 grams of solution?
A.
10%
B.
20%
C.
15%
D.
25%
Show solution
Solution
Percentage by mass = (mass of solute / mass of solution) * 100 = (20 g / (20 g + 180 g)) * 100 = 20%.
Correct Answer: B — 20%
Learn More →
Q. What is the percentage by mass of a solution containing 5 g of NaCl in 95 g of water?
A.
5%
B.
10%
C.
15%
D.
20%
Show solution
Solution
Percentage by mass = (mass of solute / total mass) × 100 = (5 g / (5 g + 95 g)) × 100 = 5%.
Correct Answer: A — 5%
Learn More →
Q. What is the volume of 1 M NaOH solution required to obtain 0.5 moles of NaOH?
A.
0.5 L
B.
1 L
C.
2 L
D.
0.25 L
Show solution
Solution
Using the formula M = moles/volume, Volume = moles/M = 0.5 moles / 1 M = 0.5 L.
Correct Answer: A — 0.5 L
Learn More →
Q. What is the volume of a 2 M solution that contains 4 moles of solute?
A.
2 L
B.
4 L
C.
1 L
D.
0.5 L
Show solution
Solution
Volume = moles of solute / molarity = 4 moles / 2 M = 2 L.
Correct Answer: B — 4 L
Learn More →
Showing 31 to 60 of 69 (3 Pages)
