The solvent can influence the reaction rate by stabilizing the transition state and the reactants involved in the nucleophilic substitution.

E2 reactions require a good leaving group to facilitate the elimination of the leaving group and the formation of a double bond.

The reaction proceeds via an E2 mechanism due to the strong base (KOH) and the presence of a good leaving group (Br).

The longest carbon chain has five carbons, and the methyl group is on the third carbon, making it 3-methylpentane.

The compound is a carboxylic acid with a methyl group on the second carbon, making it 2-methylbutanoic acid.

The reaction is an SN2 substitution where the nucleophile (OH-) attacks the carbon bonded to Br, resulting in the formation of CH3OH.

The reaction favors elimination due to the bulky substrate, leading to the formation of 2-methylpropene.

The major product is but-2-ene due to the formation of the more stable alkene through elimination.

The reaction follows Markovnikov's rule, leading to the formation of 2-bromopentane as the major product.

The reaction proceeds via an SN2 mechanism, leading to inversion of configuration at the chiral center.

The reaction is an electrophilic addition where HBr adds across the double bond of 1-hexene.

3-bromopropane is a tertiary alkyl halide, which favors the SN1 mechanism due to the stability of the carbocation formed.

SN2 reactions are bimolecular, meaning the rate depends on the concentration of both the substrate and the nucleophile.

The reaction of a tertiary alkyl halide with water is an SN1 mechanism due to the formation of a stable carbocation.

The reaction can lead to both R and S isomers due to the nature of the nucleophilic substitution mechanism.