Q. What is the mass of 0.75 moles of sulfuric acid (H2SO4)?
A.
75 g
B.
98 g
C.
147 g
D.
50 g
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Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = moles x molar mass = 0.75 moles x 98 g/mol = 73.5 g.
Correct Answer: B — 98 g
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Q. What is the mass of 2 moles of sulfuric acid (H2SO4)?
A.
98 g
B.
196 g
C.
294 g
D.
392 g
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Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 2 moles x 98 g/mol = 196 g.
Correct Answer: B — 196 g
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Q. What is the mass of 3 moles of NaCl?
A.
87 g
B.
58.5 g
C.
174 g
D.
3 g
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Solution
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.
Correct Answer: C — 174 g
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Q. What is the mass of 3 moles of sulfuric acid (H2SO4)?
A.
98 g
B.
196 g
C.
294 g
D.
392 g
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Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 3 moles x 98 g/mol = 294 g.
Correct Answer: B — 196 g
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Q. What is the molar mass of CaCO3?
A.
100 g/mol
B.
120 g/mol
C.
80 g/mol
D.
60 g/mol
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Solution
Molar mass of CaCO3 = 40 + 12 + 16*3 = 100 g/mol.
Correct Answer: A — 100 g/mol
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Q. What is the molar mass of sulfuric acid (H2SO4)?
A.
98 g/mol
B.
96 g/mol
C.
100 g/mol
D.
92 g/mol
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Solution
Molar mass = 2*1 + 32 + 4*16 = 98 g/mol.
Correct Answer: A — 98 g/mol
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Q. What is the number of atoms in 2 moles of aluminum (Al)? (2044)
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
3.011 x 10^23
D.
12.044 x 10^24
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Solution
Number of atoms = moles x Avogadro's number = 2 moles x 6.022 x 10^23 atoms/mole = 1.2044 x 10^24 atoms.
Correct Answer: B — 1.2044 x 10^24
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Q. What is the number of atoms in 2 moles of CaCO3?
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
3.011 x 10^23
D.
1.8066 x 10^24
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Solution
Each CaCO3 has 5 atoms (1 Ca, 1 C, 3 O). Number of atoms = moles x atoms per molecule x Avogadro's number = 2 moles x 5 x 6.022 x 10^23 = 1.206 x 10^24 atoms.
Correct Answer: D — 1.8066 x 10^24
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Q. What is the number of atoms in 2 moles of Na2SO4?
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
1.2044 x 10^25
D.
3.011 x 10^23
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Solution
Na2SO4 has 2 Na + 1 S + 4 O = 7 atoms. Number of atoms = moles x atoms per mole = 2 moles x 7 atoms = 14 atoms = 1.2044 x 10^24 atoms.
Correct Answer: B — 1.2044 x 10^24
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Q. What is the number of atoms in 2 moles of NaCl? (2044)
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
1.2044 x 10^25
D.
3.011 x 10^23
Show solution
Solution
Each NaCl unit has 2 atoms (Na and Cl). Therefore, 2 moles of NaCl contain 2 x 6.022 x 10^23 x 2 = 1.2044 x 10^24 atoms.
Correct Answer: B — 1.2044 x 10^24
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Q. What is the number of moles in 10 grams of Na?
A.
0.43
B.
0.22
C.
0.5
D.
0.1
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Solution
Molar mass of Na = 23 g/mol. Number of moles = mass / molar mass = 10 g / 23 g/mol = 0.43 moles.
Correct Answer: A — 0.43
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Q. What is the number of moles in 10 grams of NaOH?
A.
0.25
B.
0.5
C.
0.75
D.
1
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Solution
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol. Number of moles = mass/molar mass = 10 g / 40 g/mol = 0.25 moles.
Correct Answer: B — 0.5
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Q. What is the number of moles in 100 grams of NaOH?
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Solution
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol. Number of moles = mass/molar mass = 100 g / 40 g/mol = 2.5 moles.
Correct Answer: A — 1
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Q. What is the number of moles in 180 grams of glucose (C6H12O6)?
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Solution
Molar mass of C6H12O6 = 6*12 + 12*1 + 6*16 = 180 g/mol. Number of moles = mass/molar mass = 180 g / 180 g/mol = 1 mole.
Correct Answer: A — 1
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Q. What is the number of moles in 44 grams of CO2?
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Solution
Molar mass of CO2 = 12 + 16*2 = 44 g/mol. Number of moles = mass/molar mass = 44 g / 44 g/mol = 1 mole.
Correct Answer: A — 1
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Q. What is the number of moles in 5 liters of a 2 M NaCl solution?
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Solution
Moles = Molarity x Volume = 2 moles/L x 5 L = 10 moles.
Correct Answer: A — 2.5
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Q. What is the volume occupied by 1 mole of an ideal gas at STP?
A.
22.4 L
B.
24 L
C.
20 L
D.
18 L
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Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer: A — 22.4 L
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Q. What is the volume occupied by 4 moles of an ideal gas at STP?
A.
22.4 L
B.
44.8 L
C.
67.2 L
D.
89.6 L
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Solution
At STP, 1 mole of gas occupies 22.4 L. Therefore, 4 moles occupy 4 x 22.4 L = 89.6 L.
Correct Answer: B — 44.8 L
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Q. What is the volume of 1 mole of an ideal gas at STP?
A.
22.4 L
B.
24 L
C.
10 L
D.
1 L
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Solution
At STP (Standard Temperature and Pressure), 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer: A — 22.4 L
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Q. What is the volume of 4 moles of an ideal gas at STP?
A.
22.4 L
B.
44.8 L
C.
89.6 L
D.
112 L
Show solution
Solution
Volume = moles x volume per mole = 4 moles x 22.4 L/mole = 89.6 L.
Correct Answer: C — 89.6 L
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