Physics
Q. A car moving at 30 m/s applies brakes and comes to a stop in 6 seconds. What is the distance covered during braking? (2023)
A.
90 m
B.
120 m
C.
150 m
D.
180 m
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Solution
Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, acceleration = (0 - 30) / 6 = -5 m/s². Distance = 30 * 6 + 0.5 * (-5) * 6^2 = 180 - 90 = 90 m.
Correct Answer: B — 120 m
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Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the kinetic energy gained?
A.
200,000 J
B.
100,000 J
C.
50,000 J
D.
20,000 J
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Solution
Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (20 m/s)² = 200,000 J.
Correct Answer: B — 100,000 J
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Q. A charge of +4 µC is placed in a uniform electric field of strength 500 N/C. What is the work done in moving the charge 0.2 m in the direction of the field?
A.
400 J
B.
200 J
C.
100 J
D.
50 J
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Solution
W = F * d = (E * q) * d = (500 N/C * 4 × 10^-6 C) * 0.2 m = 0.4 J.
Correct Answer: B — 200 J
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Q. A charged particle moves in a magnetic field. What is the path of the particle if it enters the field perpendicularly? (2023)
A.
Straight line
B.
Circular path
C.
Elliptical path
D.
Parabolic path
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Solution
A charged particle moving perpendicularly to a magnetic field experiences a magnetic force that acts as a centripetal force, causing it to move in a circular path.
Correct Answer: B — Circular path
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Q. A charged particle moves in a magnetic field. What is the path of the particle? (2019)
A.
Straight line
B.
Circular
C.
Elliptical
D.
Parabolic
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Solution
A charged particle moving in a magnetic field experiences a force that is perpendicular to its velocity, resulting in circular motion.
Correct Answer: B — Circular
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Q. A circuit consists of a 9V battery and two resistors of 3Ω and 6Ω in series. What is the current flowing through the circuit? (2021)
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Solution
Total resistance R = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V / 9Ω = 1A.
Correct Answer: B — 2A
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Q. A circuit has a 9V battery and two resistors of 3Ω and 6Ω in series. What is the current flowing through the circuit? (2022)
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Solution
Total resistance R = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V / 9Ω = 1A.
Correct Answer: B — 2A
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Q. A circuit has a resistance of 10 Ω and a reactance of 10 Ω. What is the impedance of the circuit? (2020)
A.
10 Ω
B.
14.14 Ω
C.
20 Ω
D.
5 Ω
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Solution
The impedance Z = √(R² + X²) = √(10² + 10²) = √200 = 14.14 Ω.
Correct Answer: B — 14.14 Ω
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Q. A circuit has a resistance of 10Ω and a reactance of 5Ω. What is the impedance? (2020)
A.
5Ω
B.
10Ω
C.
√125Ω
D.
√(10² + 5²)Ω
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Solution
The impedance Z = √(R² + X²) = √(10² + 5²) = √125Ω.
Correct Answer: D — √(10² + 5²)Ω
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Q. A circuit has a resistance of 4 ohms and a current of 2 A. What is the voltage across the circuit?
A.
2 V
B.
4 V
C.
6 V
D.
8 V
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Solution
Using Ohm's Law, V = I × R. Here, I = 2 A and R = 4 ohms. Thus, V = 2 × 4 = 8 V.
Correct Answer: D — 8 V
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Q. A circuit has a total resistance of 12Ω and a current of 1.5A. What is the voltage across the circuit? (2021)
A.
18V
B.
12V
C.
15V
D.
9V
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Solution
Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.
Correct Answer: A — 18V
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Q. A circuit has a total resistance of 20Ω and a current of 2A flowing through it. What is the voltage across the circuit? (2023)
A.
30V
B.
40V
C.
20V
D.
10V
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Solution
Using Ohm's law, V = I * R = 2A * 20Ω = 40V.
Correct Answer: B — 40V
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Q. A circuit has a total voltage of 24V and a total resistance of 8Ω. What is the total current in the circuit? (2020)
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Solution
Using Ohm's law, I = V/R = 24V / 8Ω = 3A.
Correct Answer: A — 3A
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Q. A coil has an inductance of 0.5 H and is connected to a 50 Hz AC supply. What is the inductive reactance? (2020)
A.
25.13 Ω
B.
31.42 Ω
C.
50 Ω
D.
100 Ω
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Solution
Inductive reactance Xl = 2πfL = 2π(50)(0.5) = 31.42 Ω.
Correct Answer: B — 31.42 Ω
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Q. A current-carrying conductor experiences a force in a magnetic field. What is the direction of this force? (2020)
A.
Parallel to the field
B.
Opposite to the field
C.
Perpendicular to both current and field
D.
In the direction of current
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Solution
According to Fleming's left-hand rule, the force on a current-carrying conductor in a magnetic field is perpendicular to both the current and the magnetic field.
Correct Answer: C — Perpendicular to both current and field
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Q. A current-carrying conductor experiences a force in a magnetic field. What is the direction of this force given by Fleming's left-hand rule? (2020)
A.
Parallel to the field
B.
Opposite to the field
C.
Perpendicular to the field
D.
In the direction of current
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Solution
According to Fleming's left-hand rule, the force is perpendicular to both the magnetic field and the direction of current.
Correct Answer: C — Perpendicular to the field
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Q. A cyclist accelerates at 3 m/s² for 4 seconds. What is the final velocity if the initial velocity is 2 m/s? (2023)
A.
10 m/s
B.
11 m/s
C.
14 m/s
D.
20 m/s
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Solution
Using v = u + at, we have v = 2 m/s + (3 m/s² * 4 s) = 2 + 12 = 14 m/s.
Correct Answer: B — 11 m/s
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Q. A cyclist accelerates from rest to a speed of 10 m/s in 5 seconds. What is the acceleration? (2023)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Acceleration = (final velocity - initial velocity) / time = (10 m/s - 0) / 5 s = 2 m/s².
Correct Answer: B — 2 m/s²
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Q. A cyclist accelerates from rest to a speed of 10 m/s in 5 seconds. What is the cyclist's acceleration? (2021)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Acceleration a = (final velocity - initial velocity) / time = (10 m/s - 0) / 5 s = 2 m/s².
Correct Answer: B — 2 m/s²
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Q. A cyclist does 1500 J of work to climb a hill. If he takes 5 minutes, what is his average power output?
A.
5 W
B.
10 W
C.
15 W
D.
20 W
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Solution
Power = Work / Time = 1500 J / (5 * 60 s) = 5 W.
Correct Answer: B — 10 W
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Q. A cyclist does 600 J of work to climb a hill. If he takes 30 seconds, what is his average power output? (2022)
A.
10 W
B.
20 W
C.
30 W
D.
40 W
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Solution
Power = Work / Time = 600 J / 30 s = 20 W.
Correct Answer: B — 20 W
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Q. A cyclist is moving at a speed of 15 m/s. If the total mass of the cyclist and the bicycle is 75 kg, what is the kinetic energy?
A.
843.75 J
B.
562.5 J
C.
1687.5 J
D.
1125 J
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Solution
Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 75 kg × (15 m/s)² = 0.5 × 75 × 225 = 8437.5 J.
Correct Answer: A — 843.75 J
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Q. A cyclist travels at a speed of 10 m/s for 5 seconds. What distance does he cover? (2023)
A.
25 m
B.
50 m
C.
75 m
D.
100 m
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Solution
Distance = speed * time = 10 m/s * 5 s = 50 m.
Correct Answer: B — 50 m
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Q. A cyclist travels at a speed of 15 m/s for 2 minutes. How far does he travel?
A.
1800 m
B.
1200 m
C.
900 m
D.
600 m
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Solution
Distance = speed * time. Time in seconds = 2 * 60 = 120 s. Distance = 15 m/s * 120 s = 1800 m.
Correct Answer: A — 1800 m
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Q. A cyclist travels at a speed of 15 m/s for 20 seconds. What distance does the cyclist cover?
A.
150 m
B.
300 m
C.
400 m
D.
600 m
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Solution
Distance = speed * time = 15 m/s * 20 s = 300 m.
Correct Answer: B — 300 m
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Q. A cylinder rolls down an incline without slipping. If its mass is M and radius is R, what is the acceleration of its center of mass? (2020)
A.
g/2
B.
g/3
C.
g/4
D.
g/5
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Solution
For rolling without slipping, a_cm = (2/3)g sin(θ).
Correct Answer: B — g/3
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Q. A disc of radius R and mass M is rotating about its axis with an angular velocity ω. What is its rotational kinetic energy? (2020)
A.
(1/2)Iω²
B.
(1/2)Mω²
C.
Iω
D.
Mω²
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Solution
Rotational kinetic energy K.E. = (1/2)Iω². For a disc, I = (1/2)MR², thus K.E. = (1/4)MR²ω².
Correct Answer: A — (1/2)Iω²
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Q. A flywheel has a moment of inertia I and is rotating with an angular velocity ω. If a torque τ is applied, what is the angular acceleration? (2021)
A.
τ/I
B.
I/τ
C.
ω/τ
D.
Iω
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Solution
From Newton's second law for rotation, τ = Iα, thus α = τ/I.
Correct Answer: A — τ/I
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Q. A force of 10 N is applied to an object, causing it to accelerate at 2 m/s². What is the mass of the object? (2020)
A.
5 kg
B.
10 kg
C.
15 kg
D.
20 kg
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Solution
Using F = ma, mass m = F/a = 10 N / 2 m/s² = 5 kg.
Correct Answer: A — 5 kg
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Q. A force of 10 N is applied to move a box 5 m across a floor. What is the work done by the force?
A.
10 J
B.
20 J
C.
50 J
D.
5 J
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Solution
Work done = Force × Distance = 10 N × 5 m = 50 J
Correct Answer: B — 20 J
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