Using the median formula: m_a = 1/2 * sqrt(2b^2 + 2c^2 - a^2), where a = BC, b = AC, c = AB. m_a = 1/2 * sqrt(2*6^2 + 2*10^2 - 8^2) = 7 cm.

Using the identity 1 - cos(x) = 2sin^2(x/2), we have lim (x -> 0) (1 - cos(x))/(x^2) = lim (x -> 0) (2sin^2(x/2))/(x^2) = 1/2.

Using the Taylor series expansion for cos(x), we find that lim (x -> 0) (cos(x) - 1)/x^2 = -1/2.

Using the derivative of e^x at x = 0, we find that lim (x -> 0) (e^x - 1)/x = 1.

Using L'Hôpital's Rule, we differentiate the numerator and denominator to find lim (x -> 0) (1/(1 + x)) = 1.

Factoring gives (x - 1)(x + 1)/(x - 1), which simplifies to x + 1. Thus, lim (x -> 1) (x + 1) = 2.

Magnitude |C| = √(5^2 + (-12)^2) = √(25 + 144) = √169 = 13.

The maximum occurs at x = -b/(2a) = -10/(-4) = 2. f(2) = -2(2^2) + 10(2) - 12 = 6.

The vertex is at x = -12/(2*(-3)) = 2. The maximum value is f(2) = -3(2^2) + 12(2) - 5 = 7.

The vertex occurs at x = -b/(2a) = 2. f(2) = -2(2^2) + 8(2) - 5 = 9.

Mean = (4 + 8 + 6 + 5 + 3) / 5 = 26 / 5 = 5.2, rounded down to 5.

Supplementary angles sum up to 180 degrees. Therefore, the angle measures 180 - 110 = 70 degrees.

Complementary angles sum up to 90 degrees. If one angle is 30 degrees, the other angle is 90 - 30 = 60 degrees.

The measure of each interior angle in a regular hexagon can be calculated using the formula (n-2) * 180/n, where n is the number of sides. For a hexagon, n=6, so the measure is (6-2) * 180/6 = 120 degrees.

A regular quadrilateral is a square, and each angle in a square measures 90 degrees.

The sum of angles in a triangle is always 180 degrees. If one angle is 40 degrees and another is 60 degrees, the third angle is 180 - (40 + 60) = 80 degrees.

The sum of angles in a triangle is 180 degrees. Therefore, the third angle = 180 - (50 + 60) = 70 degrees.

The exterior angle of a triangle is equal to the sum of the two opposite interior angles. Therefore, the exterior angle = 50 + 60 = 110 degrees.

The exterior angle of a triangle is equal to the sum of the two opposite interior angles. Therefore, the exterior angle = 50 + 60 = 110 degrees.

First, arrange the data in ascending order: 10, 12, 14, 15, 18. The median is the middle value, which is 14.

The numbers are in order. The median is the 4th number, which is 40.

Arranging the numbers: 18, 20, 22, 25, 30. The median is the middle number, which is 22.

Arrange the numbers: 3, 5, 7, 8, 10, 12. The median is the average of the 3rd and 4th numbers: (7 + 8) / 2 = 7.5.

To find the median, first arrange the numbers in ascending order: 1, 3, 5, 7, 9. The median is the middle number, which is 5.

Arranging the numbers: 1, 2, 3, 4, 7, 9. The median is the average of the 3rd and 4th numbers: (3 + 4) / 2 = 3.5.

The minimum occurs at x = -b/(2a) = 8/(2*2) = 2. f(2) = 2(2^2) - 8(2) + 10 = 2.

The vertex is at x = -4/(2*2) = -1. The minimum value is f(-1) = 2(-1)^2 + 4(-1) + 1 = -1.

Mode is the number that appears most frequently. Here, 2 appears 3 times.

Mode is the number that appears most frequently. Here, 5 appears 3 times.

The number 4 appears most frequently (3 times). Hence, mode = 4.