Major Competitive Exams

Engineering & Architecture Admissions Undergraduate

Q. What is the vertex of the parabola represented by the equation y = x² - 4x + 3? (2022)

A. (2, -1)
B. (2, 1)
C. (1, 2)
D. (3, 0)

Solution

The vertex can be found using the formula x = -b/2a. Here, x = 2, and substituting back gives y = -1.

Correct Answer: A — (2, -1)

Learn More →

Q. What is the vertex of the parabola represented by the equation y = x² - 6x + 8? (2023)

A. (3, -1)
B. (3, -5)
C. (2, -4)
D. (2, -2)

Solution

The vertex can be found using the formula x = -b/2a = 6/2 = 3. Substituting x = 3 into the equation gives y = -1.

Correct Answer: A — (3, -1)

Learn More →

Q. What is the viscosity of water at 20°C?

A. 0.001 Pa·s
B. 0.01 Pa·s
C. 0.1 Pa·s
D. 1 Pa·s

Solution

The viscosity of water at 20°C is approximately 0.001 Pa·s.

Correct Answer: A — 0.001 Pa·s

Learn More →

Q. What is the voltage across a 10 ohm resistor carrying a current of 0.5 A?

A. 5 V
B. 10 V
C. 15 V
D. 20 V

Solution

Using Ohm's law, V = I * R = 0.5 A * 10 Ω = 5 V.

Correct Answer: A — 5 V

Learn More →

Q. What is the voltage across a 10Ω resistor carrying a current of 3A? (2022)

A. 30V
B. 20V
C. 10V
D. 15V

Solution

Using Ohm's law, V = IR = 3A * 10Ω = 30V.

Correct Answer: A — 30V

Learn More →

Q. What is the voltage across a 12Ω resistor carrying a current of 1.5A? (2023)

A. 18V
B. 12V
C. 6V
D. 24V

Solution

Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.

Correct Answer: A — 18V

Learn More →

Q. What is the voltage across a 12Ω resistor carrying a current of 3A? (2023)

A. 36V
B. 24V
C. 12V
D. 18V

Solution

Using Ohm's law, V = IR = 3A * 12Ω = 36V.

Correct Answer: A — 36V

Learn More →

Q. What is the voltage across a 5Ω resistor carrying a current of 3A? (2023)

A. 15V
B. 10V
C. 5V
D. 20V

Solution

Using Ohm's law, V = IR = 3A * 5Ω = 15V.

Correct Answer: A — 15V

Learn More →

Q. What is the voltage drop across a 3 ohm resistor carrying a current of 2 A?

A. 3 V
B. 6 V
C. 9 V
D. 12 V

Solution

Using Ohm's law, V = I * R = 2 A * 3 ohms = 6 V.

Correct Answer: B — 6 V

Learn More →

Q. What is the voltage drop across a 5 ohm resistor carrying a current of 2 A?

A. 5 V
B. 10 V
C. 15 V
D. 20 V

Solution

Using Ohm's law, V = I * R = 2 A * 5 ohms = 10 V.

Correct Answer: B — 10 V

Learn More →

Q. What is the voltage drop across a 5 ohm resistor carrying a current of 3 A?

A. 15 V
B. 10 V
C. 5 V
D. 20 V

Solution

Using Ohm's law, V = I * R = 3 A * 5Ω = 15 V.

Correct Answer: A — 15 V

Learn More →

Q. What is the voltage drop across a 5Ω resistor carrying a current of 3A?

A. 5V
B. 10V
C. 15V
D. 20V

Solution

Using Ohm's law, V = I * R = 3A * 5Ω = 15V.

Correct Answer: C — 15V

Learn More →

Q. What is the volume occupied by 1 mole of an ideal gas at STP (Standard Temperature and Pressure)?

A. 22.4 L
B. 24.0 L
C. 18.0 L
D. 20.0 L

Solution

At STP, 1 mole of an ideal gas occupies 22.4 liters.

Correct Answer: A — 22.4 L

Learn More →

Q. What is the volume occupied by 1 mole of an ideal gas at STP?

A. 22.4 L
B. 24 L
C. 20 L
D. 18 L

Solution

At STP, 1 mole of an ideal gas occupies 22.4 liters.

Correct Answer: A — 22.4 L

Learn More →

Q. What is the volume occupied by 4 moles of an ideal gas at STP?

A. 22.4 L
B. 44.8 L
C. 67.2 L
D. 89.6 L

Solution

At STP, 1 mole of gas occupies 22.4 L. Therefore, 4 moles occupy 4 x 22.4 L = 89.6 L.

Correct Answer: B — 44.8 L

Learn More →

Q. What is the volume of 0.2 M NaOH required to neutralize 0.1 M HCl in 250 mL? (2020)

A. 125 mL
B. 250 mL
C. 500 mL
D. 100 mL

Solution

Using the formula M1V1 = M2V2, (0.1 M)(0.25 L) = (0.2 M)(V2). V2 = 0.125 L = 125 mL.

Correct Answer: A — 125 mL

Learn More →

Q. What is the volume of 1 liter in cubic meters?

A. 0.001
B. 0.01
C. 1
D. 1000

Solution

1 liter is equal to 0.001 cubic meters.

Correct Answer: A — 0.001

Learn More →

Q. What is the volume of 1 M HCl solution needed to obtain 0.5 moles of HCl? (2022)

A. 0.5 L
B. 1 L
C. 2 L
D. 0.25 L

Solution

Volume = moles / molarity = 0.5 moles / 1 M = 0.5 L.

Correct Answer: A — 0.5 L

Learn More →

Q. What is the volume of 1 M NaOH solution required to obtain 0.5 moles of NaOH?

A. 0.5 L
B. 1 L
C. 2 L
D. 0.25 L

Solution

Using the formula M = moles/volume, Volume = moles/M = 0.5 moles / 1 M = 0.5 L.

Correct Answer: A — 0.5 L

Learn More →

Q. What is the volume of 1 mole of an ideal gas at STP (Standard Temperature and Pressure)?

A. 22.4 L
B. 24.0 L
C. 18.0 L
D. 20.0 L

Solution

At STP, 1 mole of an ideal gas occupies 22.4 liters.

Correct Answer: A — 22.4 L

Learn More →

Q. What is the volume of 1 mole of an ideal gas at STP?

A. 22.4 L
B. 24 L
C. 10 L
D. 1 L

Solution

At STP (Standard Temperature and Pressure), 1 mole of an ideal gas occupies 22.4 liters.

Correct Answer: A — 22.4 L

Learn More →

Q. What is the volume of 1 mole of an ideal gas at STP? (2019) 2019

A. 22.4 L
B. 24 L
C. 1 L
D. 10 L

Solution

At STP, 1 mole of an ideal gas occupies 22.4 liters.

Correct Answer: A — 22.4 L

Learn More →

Q. What is the volume of 1 mole of gas at STP?

A. 22.4 L
B. 24 L
C. 20 L
D. 18 L

Solution

At STP, 1 mole of gas occupies 22.4 liters.

Correct Answer: A — 22.4 L

Learn More →

Q. What is the volume of 4 moles of an ideal gas at STP?

A. 22.4 L
B. 44.8 L
C. 89.6 L
D. 112 L

Solution

Volume = moles x volume per mole = 4 moles x 22.4 L/mole = 89.6 L.

Correct Answer: C — 89.6 L

Learn More →

Q. What is the volume of a 2 M NaOH solution needed to obtain 4 moles of NaOH? (2021) 2021

A. 2 L
B. 1 L
C. 0.5 L
D. 4 L

Solution

Volume (L) = moles / molarity = 4 moles / 2 M = 2 L.

Correct Answer: A — 2 L

Learn More →

Q. What is the volume of a 2 M solution that contains 4 moles of solute?

A. 2 L
B. 4 L
C. 1 L
D. 0.5 L

Solution

Volume = moles of solute / molarity = 4 moles / 2 M = 2 L.

Correct Answer: B — 4 L

Learn More →

Q. What is the volume of a cube with a side length of 2 meters?

A. 4 m³
B. 6 m³
C. 8 m³
D. 10 m³

Solution

Volume = side³ = 2³ = 8 m³.

Correct Answer: C — 8 m³

Learn More →

Q. What is the volume of a cube with a side length of 3 cm?

A. 9 cm³
B. 18 cm³
C. 27 cm³
D. 36 cm³

Solution

The volume of a cube is given by side³, so 3 cm³ = 27 cm³.

Correct Answer: C — 27 cm³

Learn More →

Q. What is the volume of a cube with side length 3 units? (2023)

A. 9
B. 27
C. 81
D. 6

Solution

Volume = side³ = 3³ = 27 cubic units.

Correct Answer: B — 27

Learn More →

Q. What is the volume of a cylinder with radius 2 and height 5? (2023)

A. 20π
B. 10π
C. 15π
D. 25π

Solution

Volume = πr²h = π(2²)(5) = 20π cubic units.

Correct Answer: A — 20π

Learn More →

Showing 10381 to 10410 of 12915 (431 Pages)

Major Competitive Exams

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?