Total resistance R = R1 + R2 = 5Ω + 5Ω = 10Ω. Using Ohm's law, I = V/R = 10V/10Ω = 1A.

According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving. Here, 5A = 3A + 2A.

Total resistance R_total = 4 + 4 + 4 = 12 ohms. Current I = V/R_total = 12V / 12 ohms = 1A.

Total resistance R = R1 + R2 = 4 + 4 = 8 ohms. Current I = V/R = 12V / 8 ohms = 1.5 A.

Total resistance R = R1 + R2 + R3 = 2Ω + 4Ω + 6Ω = 12Ω. Using Ohm's law, I = V/R = 24V / 12Ω = 2A.

In a parallel circuit, the total current is the sum of the currents in each branch: I_total = I1 + I2 = 2 A + 3 A = 5 A.

The total electric flux through a closed surface is given by Φ = Q_enc/ε₀, where Q_enc is the enclosed charge.

1 mole of CO2 contains 1 carbon atom and 2 oxygen atoms, totaling 3 atoms.

C4H10 has 4 carbon atoms and 10 hydrogen atoms, totaling 14 atoms.

The decomposition of CaCO3 produces CaO and CO2: CaCO3 → CaO + CO2. This results in 1 mole of gas (CO2) being produced.

The decomposition reaction is CaCO3 → CaO + CO2. This produces 1 mole of CaO and 1 mole of CO2, totaling 2 moles of gas.

The total number of orbitals in an energy level is given by n^2. For n=2, it is 2^2 = 4.

The n=2 shell has 4 orbitals: 1s and 3p orbitals.

The total number of orbitals in an energy level is given by n^2. For n=4, it is 4^2 = 16.

The total number of orbitals in a shell is given by n^2. For n=4, it is 4^2 = 16.

The empty set has exactly one subset, which is itself: ∅.

The total number of subsets is 2^5 = 32.

Power (P) = I^2 * R = 5^2 * 4 = 25 * 4 = 100W.

In series, total resistance (R_total) = R1 + R2 = 10Ω + 5Ω = 15Ω.

1/R_eq = 1/12 + 1/4 => R_eq = 3 ohms.

In series, total resistance R_total = R1 + R2 = 12Ω + 4Ω = 16Ω.

1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/10 = 2/10. Thus, R_eq = 10/2 = 5 ohms.

In series, R_eq = R1 + R2 = 10 + 10 = 20 ohms.

1/R_eq = 1/R1 + 1/R2 = 1/12 + 1/12 = 2/12. Thus, R_eq = 12/2 = 6 ohms.

1/R_eq = 1/5 + 1/10 => R_eq = 3.33 ohms.

Using the formula V = I * R_eq. First, find R_eq = 1 / (1/10 + 1/20) = 6.67Ω. Then, V = 3A * 6.67Ω = 20V.

In a series circuit, the total voltage is equal to the voltage of the battery, which is 9V.

Atomic radius increases down a group due to the addition of electron shells.

Electronegativity increases from left to right across a period.

Ionization energy decreases as you move down the group in s-block elements due to increased atomic size.