Q. If a circuit has a total resistance of 12Ω and a current of 3A flows through it, what is the voltage across the circuit? (2020)
-
A.
36V
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B.
12V
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C.
4V
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D.
24V
Solution
Using Ohm's law, V = IR = 3A * 12Ω = 36V.
Correct Answer: A — 36V
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Q. If a circuit has a total resistance of 12Ω and a current of 4A, what is the voltage across the circuit? (2023)
-
A.
48V
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B.
36V
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C.
24V
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D.
12V
Solution
Using Ohm's law, V = IR = 4A * 12Ω = 48V.
Correct Answer: A — 48V
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Q. If a circuit has a total resistance of 5Ω and a current of 2A, what is the voltage across the circuit? (2022)
Solution
Using Ohm's law, V = I * R = 2A * 5Ω = 10V.
Correct Answer: A — 10V
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Q. If a circuit has a total resistance of 8Ω and a current of 4A, what is the voltage across the circuit? (2023)
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A.
32V
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B.
24V
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C.
16V
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D.
12V
Solution
Using Ohm's law, V = IR = 4A * 8Ω = 32V.
Correct Answer: A — 32V
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Q. If the current through a resistor is tripled, what happens to the power dissipated in the resistor? (2022)
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A.
Increases by 3 times
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B.
Increases by 9 times
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C.
Remains the same
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D.
Decreases by 3 times
Solution
Power is proportional to the square of the current (P = I²R). If I is tripled, P increases by 3² = 9 times.
Correct Answer: B — Increases by 9 times
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Q. If the resistance of a conductor is doubled, what happens to the current flowing through it when the voltage remains constant? (2022)
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A.
Doubles
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B.
Halves
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C.
Remains the same
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D.
Increases by 1.5 times
Solution
According to Ohm's law, I = V/R. If R is doubled, I will be halved.
Correct Answer: B — Halves
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Q. If the voltage across a resistor is halved, what happens to the current through it? (2020)
-
A.
It doubles
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B.
It halves
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C.
It remains the same
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D.
It quadruples
Solution
According to Ohm's law, if voltage is halved and resistance remains constant, the current also halves.
Correct Answer: B — It halves
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Q. If two resistors of 4Ω and 6Ω are connected in series, what is the total resistance? (2023)
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A.
10Ω
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B.
24Ω
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C.
2.4Ω
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D.
12Ω
Solution
In series, R_eq = R1 + R2 = 4Ω + 6Ω = 10Ω.
Correct Answer: A — 10Ω
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Q. In a circuit with a 24V battery and two 8Ω resistors in series, what is the total current? (2022)
Solution
Total resistance R = 8Ω + 8Ω = 16Ω. Current I = V/R = 24V / 16Ω = 1.5A.
Correct Answer: B — 2A
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Q. In a circuit with a 24V battery and two resistors of 4Ω and 8Ω in parallel, what is the total current supplied by the battery? (2022)
Solution
First, find the equivalent resistance: 1/R_eq = 1/4 + 1/8 = 3/8, so R_eq = 8/3Ω. Then, I = V/R_eq = 24V / (8/3)Ω = 9A.
Correct Answer: D — 6A
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Q. In a circuit with a 5Ω and a 10Ω resistor in parallel, what is the total current if the voltage across them is 20V? (2022)
Solution
First, find the equivalent resistance: 1/R_eq = 1/5 + 1/10 = 3/10, R_eq = 10/3Ω. Then, I = V/R_eq = 20V / (10/3)Ω = 6A.
Correct Answer: A — 4A
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the current flowing through the resistor? (2023)
Solution
Using Ohm's law, I = V/R = 9V / 3Ω = 3A.
Correct Answer: B — 2A
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated by the resistor? (2021)
Solution
Power is given by P = V²/R = (9V)² / 3Ω = 81V² / 3Ω = 27W.
Correct Answer: B — 9W
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated in the resistor? (2023)
Solution
Power P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.
Correct Answer: B — 9W
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Q. In a circuit, if the current is doubled while the resistance remains constant, what happens to the power? (2020)
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A.
It doubles
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B.
It quadruples
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C.
It remains the same
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D.
It halves
Solution
Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which is quadrupled.
Correct Answer: B — It quadruples
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Q. In a circuit, if the current is doubled while the resistance remains constant, what happens to the power consumed? (2020)
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A.
It doubles
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B.
It triples
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C.
It remains the same
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D.
It halves
Solution
Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which means power quadruples.
Correct Answer: A — It doubles
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Q. In a circuit, if the resistance is halved while the voltage remains constant, what happens to the current? (2022)
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A.
It halves
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B.
It doubles
-
C.
It remains the same
-
D.
It quadruples
Solution
According to Ohm's law, I = V/R. If R is halved, I will double.
Correct Answer: B — It doubles
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Q. In a circuit, if the voltage is doubled and the resistance remains constant, what happens to the current? (2020)
-
A.
Doubles
-
B.
Halves
-
C.
Remains the same
-
D.
Quadruples
Solution
According to Ohm's law, I = V/R. If V is doubled, I also doubles.
Correct Answer: A — Doubles
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Q. In a parallel circuit with two resistors of 4Ω and 12Ω, what is the total current if the voltage across the circuit is 24V? (2022)
Solution
First, find the equivalent resistance: 1/R_eq = 1/4 + 1/12 = 3/12 + 1/12 = 4/12, R_eq = 3Ω. Then, I = V/R_eq = 24V / 3Ω = 8A.
Correct Answer: C — 8A
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Q. In a parallel circuit with two resistors of 6Ω and 3Ω, what is the total current if a 12V battery is connected? (2021)
Solution
First, find the equivalent resistance: 1/R_eq = 1/6 + 1/3 = 1/2, so R_eq = 2Ω. Then, I = V/R_eq = 12V / 2Ω = 6A.
Correct Answer: C — 6A
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Q. In a parallel circuit with two resistors of 6Ω and 3Ω, what is the total resistance? (2019)
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A.
2Ω
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B.
4Ω
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C.
1.5Ω
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D.
9Ω
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, thus R_eq = 2Ω.
Correct Answer: B — 4Ω
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Q. In a parallel circuit, if one branch has a resistance of 4Ω and another has 8Ω, what is the equivalent resistance? (2020)
-
A.
2.67Ω
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B.
3Ω
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C.
4Ω
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D.
6Ω
Solution
1/R_eq = 1/4 + 1/8 = 2/8 + 1/8 = 3/8, so R_eq = 8/3Ω ≈ 2.67Ω.
Correct Answer: A — 2.67Ω
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Q. What happens to the total current in a parallel circuit if one branch is removed? (2021)
-
A.
Increases
-
B.
Decreases
-
C.
Remains the same
-
D.
Depends on the branch
Solution
Removing a branch in a parallel circuit decreases the total current.
Correct Answer: B — Decreases
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Q. What is the current through a 10Ω resistor connected to a 20V battery? (2020)
Solution
Using Ohm's law, I = V/R = 20V / 10Ω = 2A.
Correct Answer: B — 2A
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Q. What is the current through a 12Ω resistor connected to a 24V battery? (2023)
Solution
Using Ohm's law, I = V/R = 24V / 12Ω = 2A.
Correct Answer: B — 2A
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Q. What is the current through a 12Ω resistor when a voltage of 48V is applied? (2023)
Solution
Using Ohm's law, I = V/R = 48V / 12Ω = 4A.
Correct Answer: B — 6A
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Q. What is the current through a 15Ω resistor connected to a 45V source? (2021)
Solution
Using Ohm's law, I = V/R = 45V / 15Ω = 3A.
Correct Answer: A — 3A
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Q. What is the effect on the total resistance in a series circuit if one resistor is removed? (2023)
-
A.
Increases
-
B.
Decreases
-
C.
Remains the same
-
D.
Becomes zero
Solution
Removing a resistor from a series circuit decreases the total resistance since the sum of the remaining resistances is less.
Correct Answer: B — Decreases
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Q. What is the equivalent resistance of two 4Ω resistors in parallel? (2019)
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/4 + 1/4 = 1/2, thus R_eq = 2Ω.
Correct Answer: A — 2Ω
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Q. What is the equivalent resistance of two resistors of 4Ω and 12Ω in parallel? (2022)
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/4 + 1/12 = 1/3, so R_eq = 3Ω.
Correct Answer: A — 3Ω
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