The symmetric difference A Δ B includes elements in either A or B but not in both, which are {1, 2, 4, 5}.

First, A ∩ B = {3}. Then, A ∪ {3} = {1, 2, 3}.

The Cartesian product A × B is the set of all ordered pairs (a, b) where a ∈ A and b ∈ B, which is {(1, 3), (1, 4), (2, 3), (2, 4), (3, 3), (3, 4)}.

The number of subsets of a set with n elements is 2^n. Here, n = 3, so 2^3 = 8.

The power set of a set with n elements has 2^n subsets. Here, n=3, so the power set has 2^3 = 8 subsets.

The Cartesian product A × B consists of all ordered pairs (a, b) where a ∈ A and b ∈ B. Thus, A × B = {(1, x), (2, x)} for all odd integers x.

The intersection A ∩ B includes letters that are common in both words. The only common letter is 'A', so A ∩ B = {A}.

The intersection A ∩ B consists of common letters, which is {T}.

The intersection A ∩ B consists of common multiples, which is {0}.

Set A = {1, 2, 3, 4} and set B = {3, 4, 5, ...}. The intersection A ∩ B = {3, 4}.

The intersection A ∩ B includes all prime numbers less than 10, which are {2, 3, 5, 7}.

Set A = {1, 2, 3, 4} and set B = {1, 2}. Thus, A - B = {3, 4}.

The natural numbers less than 5 are {1, 2, 3, 4} and the prime numbers are {2, 3}. Their intersection is {2, 3}.

The intersection A ∩ B includes elements that are in both A and B. Here, A = {1, 2, 3, 4} and B = {1, 3}, so A ∩ B = {1, 3}.

Both sets A and B contain the same elements: {2, 3, 5, 7}. Therefore, A = B is True.

The set A consists of all prime numbers less than 10, which are {2, 3, 5, 7}.

The intersection A ∩ B is empty because no letter can be both a vowel and a consonant.

The union of sets A and B, A ∪ B, includes all even integers and all multiples of 3. Thus, A ∪ B = {0, 2, 3, 4, 6, 9, ...}.

A is the set of all even integers, while B is the set of multiples of 4. Not all even integers are multiples of 4 (e.g., 2 is even but not a multiple of 4), hence A is not a subset of B.

The only even prime number is 2, so A ∩ B = {2}.

A ∩ B = {2} as 2 is the only even prime number.

det(A) = (1)(4) - (2)(3) = 4 - 6 = -2.

det(A) = (1*4) - (2*3) = 4 - 6 = -2.

det(2A) = 2^2 * det(A) = 4 * (1*5 - 2*3) = 4 * (-1) = -4.

Power P = V^2 / R. Here, P = 9^2 / 3 = 81 / 3 = 27 W.

In this case, the reaction force at each support is half the load applied at the center.

Using the formula for minimum deviation, D = (n - 1)A. Here, n = √3 and A = 60 degrees. Thus, D = (√3 - 1) * 60 degrees, which approximates to 30 degrees.

Applying a force at an angle reduces the normal force because part of the applied force acts vertically upward, counteracting the weight of the block.

Speed upstream = distance/time = 20/4 = 5 km/h. Speed of current = speed of boat - speed upstream = 10 - 5 = 5 km/h.

Speed upstream = speed of boat - speed of current = 15 - 5 = 10 km/h.