Q. What is the rate law expression for a reaction with the rate equation rate = k[A]^2[B]?
A.
rate = k[A][B]
B.
rate = k[A]^2
C.
rate = k[A]^2[B]
D.
rate = k[B]
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Solution
The rate law expression is derived directly from the rate equation, which is given as rate = k[A]^2[B].
Correct Answer: C — rate = k[A]^2[B]
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Q. What is the real part of the complex number 5 - 7i?
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Solution
The real part of 5 - 7i is 5.
Correct Answer: A — 5
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Q. What is the real part of the complex number z = 2e^(iπ/3)?
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Solution
The real part is 2 * cos(π/3) = 2 * 1/2 = 1.
Correct Answer: B — 2
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Q. What is the real part of the complex number z = 4e^(iπ/3)?
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Solution
The real part is Re(z) = 4 * cos(π/3) = 4 * 1/2 = 2.
Correct Answer: C — 2√3
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Q. What is the real part of the complex number z = 5 - 2i?
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Solution
The real part of z = 5 - 2i is 5.
Correct Answer: A — 5
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Q. What is the real part of the complex number z = 5 - 4i?
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Solution
The real part of z = 5 - 4i is 5.
Correct Answer: A — 5
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Q. What is the real part of the complex number z = 5 - 6i?
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Solution
The real part of z = 5 - 6i is 5.
Correct Answer: A — 5
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Q. What is the real part of the complex number z = 5e^(iπ/3)?
A.
5/2
B.
5/√3
C.
5√3/2
D.
5
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Solution
The real part is Re(z) = 5cos(π/3) = 5 * 1/2 = 5/2.
Correct Answer: A — 5/2
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Q. What is the reducing agent in the reaction 2MnO4- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O?
A.
MnO4-
B.
C2O4^2-
C.
H+
D.
CO2
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Solution
C2O4^2- is the reducing agent as it donates electrons.
Correct Answer: B — C2O4^2-
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Q. What is the reducing agent in the reaction Zn + CuSO4 → ZnSO4 + Cu?
A.
Zn
B.
Cu
C.
CuSO4
D.
ZnSO4
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Solution
Zinc (Zn) is the reducing agent as it donates electrons to copper.
Correct Answer: A — Zn
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Q. What is the reduction half-reaction for the conversion of MnO4- to Mn2+ in acidic medium?
A.
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
B.
MnO4- + 5e- → Mn2+ + 8H+ + 4H2O
C.
MnO4- + 4H2O + 5e- → Mn2+ + 8H+
D.
MnO4- + 5e- + 4H2O → Mn2+ + 8H+
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Solution
The correct reduction half-reaction in acidic medium is MnO4- + 8H+ + 5e- → Mn2+ + 4H2O.
Correct Answer: A — MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
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Q. What is the reduction half-reaction for the reaction 2MnO4- + 16H+ + 10e- → 2Mn2+ + 8H2O?
A.
MnO4- + 8H2O + 10e- → Mn2+ + 16H+
B.
MnO4- + 10e- + 8H+ → Mn2+ + 4H2O
C.
MnO4- + 10e- → Mn2+ + 8H2O
D.
MnO4- + 16H+ → Mn2+ + 10e- + 8H2O
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Solution
The correct reduction half-reaction shows the gain of electrons and protons.
Correct Answer: B — MnO4- + 10e- + 8H+ → Mn2+ + 4H2O
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Q. What is the reduction half-reaction for the reaction of copper(II) ions with zinc?
A.
Cu^2+ + 2e^- → Cu
B.
Zn → Zn^2+ + 2e^-
C.
Cu → Cu^2+ + 2e^-
D.
Zn^2+ + 2e^- → Zn
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Solution
The reduction half-reaction is Cu^2+ + 2e^- → Cu.
Correct Answer: A — Cu^2+ + 2e^- → Cu
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Q. What is the reduction half-reaction for the reaction of MnO4- in acidic medium?
A.
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
B.
MnO4- + 3e- → MnO2 + 2H2O
C.
MnO4- + 2e- → MnO2 + 4H+
D.
MnO4- + 4e- + 8H+ → MnO2 + 4H2O
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Solution
In acidic medium, MnO4- is reduced to Mn2+.
Correct Answer: A — MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
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Q. What is the refractive index of a medium if the critical angle for total internal reflection is 30°?
A.
1.00
B.
1.15
C.
1.73
D.
2.00
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Solution
Using the formula n = 1/sin(θc), where θc = 30°, we find n = 1/sin(30°) = 1/0.5 = 2.00.
Correct Answer: C — 1.73
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Q. What is the refractive index of a medium if the critical angle for total internal reflection is 30° when light travels to air?
A.
1.73
B.
1.00
C.
1.41
D.
1.50
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Solution
Using sin(30°) = 0.5, n = 1/sin(30°) = 1/0.5 = 2. Therefore, the refractive index is 2.
Correct Answer: A — 1.73
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Q. What is the relationship between angular momentum L and moment of inertia I for a rotating object?
A.
L = Iω
B.
L = I²ω
C.
L = ω/I
D.
L = I + ω
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Solution
Angular momentum L is given by L = Iω, where ω is the angular velocity.
Correct Answer: A — L = Iω
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Q. What is the relationship between bulk modulus and compressibility?
A.
Bulk modulus is the inverse of compressibility
B.
Bulk modulus is equal to compressibility
C.
Bulk modulus is the square of compressibility
D.
There is no relationship
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Solution
Bulk modulus is defined as the reciprocal of compressibility, indicating how incompressible a material is.
Correct Answer: A — Bulk modulus is the inverse of compressibility
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Q. What is the relationship between Celsius and Kelvin?
A.
K = C + 273.15
B.
K = C - 273.15
C.
C = K + 273.15
D.
C = K - 273.15
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Solution
The relationship is K = C + 273.15, where K is the temperature in Kelvin and C is the temperature in Celsius.
Correct Answer: A — K = C + 273.15
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Q. What is the relationship between current and magnetic field in a long straight conductor?
A.
Directly proportional
B.
Inversely proportional
C.
Independent
D.
Exponential
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Solution
The magnetic field around a long straight conductor is directly proportional to the current flowing through it.
Correct Answer: A — Directly proportional
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Q. What is the relationship between current, voltage, and resistance in an electrical circuit?
A.
Ohm's Law
B.
Kirchhoff's Law
C.
Faraday's Law
D.
Ampere's Law
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Solution
Ohm's Law defines the relationship between current (I), voltage (V), and resistance (R) as V = IR.
Correct Answer: A — Ohm's Law
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Q. What is the relationship between electric field and electric potential?
A.
E = -dV/dr
B.
E = dV/dr
C.
E = V/r
D.
E = V^2
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Solution
The electric field E is the negative gradient of the electric potential V, given by E = -dV/dr.
Correct Answer: A — E = -dV/dr
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Q. What is the relationship between electric field E and electric potential V?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/d
D.
E = -V/d
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Solution
The electric field E is the negative gradient of the electric potential V, given by E = -dV/dx.
Correct Answer: A — E = -dV/dx
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Q. What is the relationship between electric field E and potential V in a uniform electric field?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/dx
D.
E = -V/dx
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Solution
In a uniform electric field, the relationship is given by E = -dV/dx, indicating that the electric field points in the direction of decreasing potential.
Correct Answer: A — E = -dV/dx
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Q. What is the relationship between electric field E and potential V in electrostatics?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/dx
D.
E = -V
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Solution
The electric field is the negative gradient of the electric potential, E = -dV/dx.
Correct Answer: A — E = -dV/dx
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Q. What is the relationship between electric field E and surface charge density σ on a conductor?
A.
E = σ/ε₀
B.
E = σ/2ε₀
C.
E = 2σ/ε₀
D.
E = σ/4ε₀
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Solution
The electric field just outside a charged conductor is given by E = σ/ε₀.
Correct Answer: A — E = σ/ε₀
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Q. What is the relationship between electric potential (V) and electric field (E) in a uniform field?
A.
V = E × d
B.
V = E/d
C.
E = V × d
D.
E = V/d
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Solution
In a uniform electric field, the electric potential difference V is given by V = E × d, where d is the distance moved in the direction of the field.
Correct Answer: A — V = E × d
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Q. What is the relationship between electric potential and electric field?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/d
D.
E = -V/d
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Solution
The electric field E is the negative gradient of the electric potential V, expressed as E = -dV/dx.
Correct Answer: A — E = -dV/dx
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Q. What is the relationship between enthalpy (H), internal energy (U), and pressure-volume work (PV)?
A.
H = U + PV
B.
H = U - PV
C.
H = U * PV
D.
H = U / PV
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Solution
The relationship is given by H = U + PV, where H is enthalpy, U is internal energy, and PV is the pressure-volume work.
Correct Answer: A — H = U + PV
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Q. What is the relationship between enthalpy (H), internal energy (U), pressure (P), and volume (V)?
A.
H = U + PV
B.
H = U - PV
C.
H = U + P/V
D.
H = U - P/V
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Solution
The relationship is given by H = U + PV, where H is enthalpy, U is internal energy, P is pressure, and V is volume.
Correct Answer: A — H = U + PV
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