Q. What is the general formula for alkenes?
A.
C_nH_(2n)
B.
C_nH_(2n+2)
C.
C_nH_(2n-2)
D.
C_nH_(2n+1)
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Solution
Alkenes are unsaturated hydrocarbons with the general formula CnH2n.
Correct Answer: A — C_nH_(2n)
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Q. What is the general formula for alkynes?
A.
C_nH_(2n+2)
B.
C_nH_(2n)
C.
C_nH_(2n-2)
D.
C_nH_(2n-1)
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Solution
The general formula for alkynes is C_nH_(2n-2), where n is the number of carbon atoms.
Correct Answer: C — C_nH_(2n-2)
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Q. What is the general formula for carbohydrates?
A.
C_n(H2O)_n
B.
C_nH_nO_n
C.
C_nH_2nO_n
D.
C_nH_2O_n
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Solution
The general formula for carbohydrates is C_n(H2O)_n, indicating that they are hydrates of carbon.
Correct Answer: A — C_n(H2O)_n
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Q. What is the general formula for carboxylic acids?
A.
C_nH_2nO_2
B.
C_nH_2n+1COOH
C.
C_nH_2nO
D.
C_nH_2n+2O
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Solution
The general formula for carboxylic acids is C_nH_2nO_2.
Correct Answer: A — C_nH_2nO_2
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Q. What is the general formula for cycloalkanes?
A.
CnH2n
B.
CnH2n+2
C.
CnH2n-2
D.
CnH2n-4
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Solution
The general formula for cycloalkanes is CnH2n.
Correct Answer: A — CnH2n
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Q. What is the general formula for ketones?
A.
CnH2nO
B.
CnH2n+2O
C.
CnH2n-2O
D.
CnH2nO2
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Solution
The general formula for ketones is CnH2nO, where n is the number of carbon atoms.
Correct Answer: A — CnH2nO
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Q. What is the general solution of the differential equation dy/dx = 3y?
A.
y = Ce^(3x)
B.
y = Ce^(-3x)
C.
y = 3x + C
D.
y = Cx^3
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Solution
The differential equation is separable. Integrating both sides gives ln|y| = 3x + C, hence y = Ce^(3x).
Correct Answer: A — y = Ce^(3x)
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Q. What is the general trend in the melting points of alkali metals as you move down the group?
A.
They increase
B.
They decrease
C.
They remain constant
D.
They fluctuate
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Solution
The melting points of alkali metals generally decrease as you move down the group due to the increase in atomic size and decrease in metallic bonding strength.
Correct Answer: B — They decrease
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Q. What is the general trend of ionization energy across a period?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Increases then decreases
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Solution
Ionization energy generally increases across a period due to increasing nuclear charge.
Correct Answer: A — Increases
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Q. What is the geometry of a molecule with sp3d hybridization?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Trigonal bipyramidal
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Solution
Molecules with sp3d hybridization have a trigonal bipyramidal geometry.
Correct Answer: D — Trigonal bipyramidal
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Q. What is the geometry of the complex ion [Ag(NH3)2]+?
A.
Linear
B.
Tetrahedral
C.
Octahedral
D.
Square planar
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Solution
The geometry of [Ag(NH3)2]+ is linear due to the presence of two ligands.
Correct Answer: A — Linear
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Q. What is the geometry of the complex ion [Cu(NH3)4]2+?
A.
Tetrahedral
B.
Square planar
C.
Octahedral
D.
Trigonal bipyramidal
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Solution
The geometry of the complex ion [Cu(NH3)4]2+ is square planar.
Correct Answer: B — Square planar
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Q. What is the geometry of the complex ion [Ni(CN)4]2-?
A.
Tetrahedral
B.
Square planar
C.
Octahedral
D.
Trigonal bipyramidal
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Solution
[Ni(CN)4]2- has a square planar geometry due to the presence of 4 ligands around the nickel ion.
Correct Answer: B — Square planar
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Q. What is the geometry of the complex [Ag(NH3)2]+?
A.
Linear
B.
Tetrahedral
C.
Square Planar
D.
Octahedral
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Solution
The geometry of [Ag(NH3)2]+ is linear due to the coordination number of 2.
Correct Answer: A — Linear
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Q. What is the geometry of [Ag(NH3)2]+?
A.
Linear
B.
Tetrahedral
C.
Octahedral
D.
Square planar
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Solution
The geometry of [Ag(NH3)2]+ is linear due to the presence of two ligands.
Correct Answer: A — Linear
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Q. What is the Gibbs Free Energy change (ΔG) at equilibrium?
A.
ΔG < 0
B.
ΔG = 0
C.
ΔG > 0
D.
ΔG = ΔH - TΔS
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Solution
At equilibrium, the Gibbs Free Energy change (ΔG) is zero, indicating that the system is at its lowest energy state.
Correct Answer: B — ΔG = 0
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Q. What is the Gibbs free energy change for a spontaneous process?
A.
Positive
B.
Negative
C.
Zero
D.
Undefined
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Solution
For a spontaneous process, the Gibbs free energy change is negative.
Correct Answer: B — Negative
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Q. What is the gravitational field strength at a distance 'R' from the center of a planet of radius 'R' and uniform density?
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Solution
Inside a uniform sphere, the gravitational field strength varies linearly with distance from the center, so at R/2 it is g/2.
Correct Answer: C — g/2
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Q. What is the gravitational field strength at a distance of 3R from the center of a planet of radius R?
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Solution
g = GM/r²; at 3R, g = GM/(3R)² = G/9.
Correct Answer: A — G/9
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Q. What is the gravitational field strength at a distance of 3R from the center of a planet of mass M and radius R?
A.
G*M/R²
B.
G*M/(3R)²
C.
G*M/(9R²)
D.
G*M/(6R²)
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Solution
g = GM/r², at 3R, g = GM/(3R)² = GM/9R².
Correct Answer: C — G*M/(9R²)
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Q. What is the gravitational field strength at a distance of 3R from the center of the Earth? (R = radius of Earth)
A.
g/9
B.
g/3
C.
g/6
D.
g/12
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Solution
Gravitational field strength (g') = g / (distance^2) = g / (3R)^2 = g / 9.
Correct Answer: A — g/9
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Q. What is the gravitational field strength at a distance of 4R from the center of a planet of radius R?
A.
G/16
B.
G/4
C.
G/2
D.
G
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Solution
Gravitational field strength g = GM/r². At 4R, g = GM/(4R)² = GM/16R² = G/16.
Correct Answer: A — G/16
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Q. What is the gravitational field strength at a distance of 4R from the center of a planet of mass M and radius R?
A.
GM/R²
B.
GM/4R²
C.
GM/16R²
D.
GM/8R²
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Solution
g = GM/r²; at 4R, g = GM/(4R)² = GM/16R².
Correct Answer: C — GM/16R²
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Q. What is the gravitational field strength at the surface of a planet of mass M and radius R?
A.
GM/R^2
B.
2GM/R^2
C.
GM/R
D.
G/R^2
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Solution
The gravitational field strength g at the surface of a planet is given by g = GM/R^2.
Correct Answer: A — GM/R^2
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Q. What is the gravitational field strength at the surface of a planet with mass 6 x 10^24 kg and radius 6.4 x 10^6 m?
A.
9.8 N/kg
B.
6.67 N/kg
C.
3.2 N/kg
D.
12.5 N/kg
Show solution
Solution
g = GM/R² = (6.67 x 10^-11 * 6 x 10^24) / (6.4 x 10^6)² = 9.8 N/kg
Correct Answer: A — 9.8 N/kg
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Q. What is the gravitational field strength at the surface of the Earth?
A.
9.8 N/kg
B.
10 N/kg
C.
11 N/kg
D.
12 N/kg
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Solution
The gravitational field strength at the surface of the Earth is approximately 9.8 N/kg.
Correct Answer: A — 9.8 N/kg
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Q. What is the gravitational force acting on a 1 kg mass at the surface of the Earth? (g = 9.8 m/s²)
A.
9.8 N
B.
19.6 N
C.
4.9 N
D.
0 N
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Solution
F = mg = 1 * 9.8 = 9.8 N.
Correct Answer: A — 9.8 N
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Q. What is the gravitational force acting on a 10 kg mass at the surface of the Earth?
A.
98 N
B.
10 N
C.
100 N
D.
9.8 N
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Solution
F = mg = 10 kg * 9.8 m/s^2 = 98 N.
Correct Answer: A — 98 N
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Q. What is the gravitational force acting on a 10 kg object at the surface of the Earth?
A.
98 N
B.
100 N
C.
10 N
D.
9.8 N
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Solution
Using F = mg, where m = 10 kg and g = 9.8 m/s², F = 10 * 9.8 = 98 N.
Correct Answer: A — 98 N
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Q. What is the gravitational force acting on a 10 kg object on the surface of the Earth? (g = 9.8 m/s²)
A.
9.8 N
B.
19.6 N
C.
29.4 N
D.
39.2 N
Show solution
Solution
F = mg = 10 * 9.8 = 98 N
Correct Answer: B — 19.6 N
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