Q. If the refractive index of a medium is 1.33, what is the maximum angle of incidence for total internal reflection when light travels to air?
-
A.
41.8°
-
B.
48.6°
-
C.
53.1°
-
D.
60.0°
Solution
The critical angle θc can be calculated as θc = sin^(-1)(n2/n1) = sin^(-1)(1.00/1.33) ≈ 48.6°.
Correct Answer: A — 41.8°
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Q. If the refractive index of a medium is 1.33, what is the speed of light in that medium if the speed of light in vacuum is 3 x 10^8 m/s?
-
A.
2.25 x 10^8 m/s
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B.
2.5 x 10^8 m/s
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C.
2.75 x 10^8 m/s
-
D.
3 x 10^8 m/s
Solution
Speed of light in medium = c/n = (3 x 10^8 m/s) / 1.33 ≈ 2.25 x 10^8 m/s.
Correct Answer: A — 2.25 x 10^8 m/s
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Q. If the refractive index of a medium is 1.5, what is the maximum angle of incidence for total internal reflection when light travels to air?
-
A.
41.8°
-
B.
48.6°
-
C.
60.0°
-
D.
90.0°
Solution
The critical angle θc is given by sin(θc) = n2/n1 = 1/1.5, which gives θc ≈ 41.8°.
Correct Answer: A — 41.8°
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Q. If the refractive index of a medium is 1.5, what is the speed of light in that medium? (Speed of light in vacuum = 3 x 10^8 m/s)
-
A.
2 x 10^8 m/s
-
B.
1.5 x 10^8 m/s
-
C.
3 x 10^8 m/s
-
D.
4.5 x 10^8 m/s
Solution
Speed of light in medium = c/n = (3 x 10^8 m/s) / 1.5 = 2 x 10^8 m/s.
Correct Answer: A — 2 x 10^8 m/s
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Q. If the refractive index of a medium is 1.5, what is the speed of light in that medium?
-
A.
2 x 10^8 m/s
-
B.
3 x 10^8 m/s
-
C.
1.5 x 10^8 m/s
-
D.
4.5 x 10^8 m/s
Solution
The speed of light in a medium is given by v = c/n. Here, c = 3 x 10^8 m/s and n = 1.5, so v = 3 x 10^8 / 1.5 = 2 x 10^8 m/s.
Correct Answer: A — 2 x 10^8 m/s
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Q. If the refractive index of a medium is 1.5, what is the wavelength of light in that medium if the wavelength in vacuum is 600 nm?
-
A.
400 nm
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B.
600 nm
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C.
800 nm
-
D.
900 nm
Solution
Wavelength in medium = λ/v = λ0/n = 600 nm / 1.5 = 400 nm.
Correct Answer: A — 400 nm
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Q. If the refractive index of a medium is 2.0, what is the critical angle for total internal reflection at the interface with air?
-
A.
30°
-
B.
45°
-
C.
60°
-
D.
90°
Solution
Using the formula sin(θc) = n2/n1, we have sin(θc) = 1.00/2.00, leading to θc ≈ 30°.
Correct Answer: C — 60°
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Q. If the refractive index of a medium is 2.0, what is the critical angle for total internal reflection?
-
A.
30°
-
B.
45°
-
C.
60°
-
D.
90°
Solution
Using the formula θc = sin^(-1)(1/n), where n = 2.0, we find θc = sin^(-1)(1/2) = 30°.
Correct Answer: C — 60°
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Q. If the refractive index of a medium is 2.0, what is the critical angle for total internal reflection when light travels from this medium to air?
-
A.
30°
-
B.
45°
-
C.
60°
-
D.
90°
Solution
Using the formula sin(θc) = n2/n1, where n1 = 2.0 (medium) and n2 = 1.0 (air), we find sin(θc) = 1.0/2.0 = 0.5, leading to θc = 60°.
Correct Answer: C — 60°
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Q. If the refractive index of a medium is 2.0, what is the maximum angle of incidence for total internal reflection when light travels to air?
-
A.
30°
-
B.
45°
-
C.
60°
-
D.
90°
Solution
Critical angle θc = sin⁻¹(n2/n1) = sin⁻¹(1.00/2.00) ≈ 30°; thus, maximum angle of incidence for total internal reflection is 60°.
Correct Answer: C — 60°
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Q. If the refractive index of a medium is greater than 1, how does it affect the speed of light in that medium?
-
A.
Increases speed
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B.
Decreases speed
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C.
No effect
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D.
Depends on wavelength
Solution
The speed of light in a medium is given by v = c/n, where n is the refractive index. If n > 1, the speed decreases.
Correct Answer: B — Decreases speed
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Q. If the refractive index of a medium is greater than 1, what happens to the speed of light in that medium?
-
A.
It increases
-
B.
It decreases
-
C.
It remains the same
-
D.
It becomes infinite
Solution
The speed of light in a medium is given by v = c/n, where n is the refractive index. If n > 1, then v < c, meaning the speed decreases.
Correct Answer: B — It decreases
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Q. If the refractive index of a medium is greater than 1, what happens to the speed of light in that medium compared to vacuum?
-
A.
It increases
-
B.
It decreases
-
C.
It remains the same
-
D.
It becomes infinite
Solution
The speed of light in a medium is less than that in vacuum, given by v = c/n, where n > 1.
Correct Answer: B — It decreases
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Q. If the refractive index of a medium is greater than 1, what happens to the wavelength of light in that medium?
-
A.
It increases
-
B.
It decreases
-
C.
It remains the same
-
D.
It becomes zero
Solution
The wavelength of light decreases in a medium with a refractive index greater than 1, as λ' = λ/n.
Correct Answer: B — It decreases
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Q. If the refractive index of a medium is greater than 1, what happens to the wavelength of light in that medium compared to its wavelength in vacuum?
-
A.
It increases
-
B.
It decreases
-
C.
It remains the same
-
D.
It becomes zero
Solution
The wavelength of light decreases in a medium with a refractive index greater than 1, as it is given by λ' = λ/n.
Correct Answer: B — It decreases
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Q. If the refractive index of a thin film is greater than that of the surrounding medium, what happens to the phase of the reflected wave?
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A.
No phase change
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B.
Phase change of π
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C.
Phase change of 2π
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D.
Phase change of λ/2
Solution
When light reflects off a medium with a higher refractive index, it undergoes a phase change of π (180 degrees).
Correct Answer: B — Phase change of π
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Q. If the refractive index of diamond is 2.42, what is the critical angle for total internal reflection when light travels from diamond to air?
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A.
24.4°
-
B.
30.0°
-
C.
36.9°
-
D.
41.8°
Solution
Using the formula sin(θc) = n2/n1, where n1 = 2.42 (diamond) and n2 = 1.00 (air), we find θc ≈ 24.4°.
Correct Answer: A — 24.4°
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Q. If the relation R on set A = {1, 2, 3} is defined as R = {(1, 1), (2, 2), (3, 3)}, is R reflexive?
-
A.
Yes
-
B.
No
-
C.
Only for 1
-
D.
Only for 2
Solution
A relation is reflexive if every element in the set is related to itself. Here, R includes (1, 1), (2, 2), and (3, 3), so R is reflexive.
Correct Answer: A — Yes
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Q. If the relation R on set A = {1, 2, 3} is defined as R = {(1, 2), (2, 3)}, is R reflexive?
-
A.
Yes
-
B.
No
-
C.
Depends on A
-
D.
None of the above
Solution
A relation is reflexive if every element is related to itself. Here, (1,1), (2,2), and (3,3) are not in R, so R is not reflexive.
Correct Answer: B — No
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Q. If the resistance in a circuit is doubled while keeping the voltage constant, what happens to the current?
-
A.
It doubles.
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B.
It halves.
-
C.
It remains the same.
-
D.
It quadruples.
Solution
According to Ohm's Law (I = V/R), if resistance (R) is doubled and voltage (V) remains constant, the current (I) will be halved.
Correct Answer: B — It halves.
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Q. If the resistance in a circuit is doubled while the voltage remains constant, what happens to the current?
-
A.
Doubles
-
B.
Halves
-
C.
Remains the same
-
D.
Increases exponentially
Solution
According to Ohm's law (V = IR), if resistance (R) is doubled and voltage (V) remains constant, the current (I) will be halved.
Correct Answer: B — Halves
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Q. If the resistance in one arm of a Wheatstone bridge is increased, what effect does it have on the balance condition?
-
A.
The bridge will always remain balanced.
-
B.
The bridge will become unbalanced.
-
C.
The balance condition will improve.
-
D.
It has no effect.
Solution
Increasing the resistance in one arm will disturb the balance condition, making the bridge unbalanced.
Correct Answer: B — The bridge will become unbalanced.
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Q. If the resistance in one arm of a Wheatstone bridge is increased, what happens to the balance condition?
-
A.
It remains balanced
-
B.
It becomes unbalanced
-
C.
It depends on other resistances
-
D.
It becomes short-circuited
Solution
Increasing the resistance in one arm will disturb the balance condition, making it unbalanced.
Correct Answer: B — It becomes unbalanced
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Q. If the resistance of a circuit is 10 ohms and the induced EMF is 20 V, what is the induced current?
-
A.
2 A
-
B.
0.5 A
-
C.
10 A
-
D.
5 A
Solution
Using Ohm's law, I = V/R. Here, I = 20 V / 10 Ω = 2 A.
Correct Answer: A — 2 A
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Q. If the resistance of a circuit is doubled while keeping the induced EMF constant, what happens to the induced current?
-
A.
It doubles
-
B.
It halves
-
C.
It remains the same
-
D.
It becomes zero
Solution
According to Ohm's law (I = V/R), if the resistance is doubled while the voltage (induced EMF) remains constant, the current will be halved.
Correct Answer: B — It halves
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Q. If the resistance of a circuit is doubled while the voltage remains constant, what happens to the current?
-
A.
It doubles
-
B.
It halves
-
C.
It remains the same
-
D.
It quadruples
Solution
According to Ohm's Law, I = V/R. If R is doubled, the current I will be halved.
Correct Answer: B — It halves
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Q. If the resistance of a wire is doubled, how does it affect the current flowing through it when connected to a constant voltage source?
-
A.
Current doubles
-
B.
Current halves
-
C.
Current remains the same
-
D.
Current quadruples
Solution
According to Ohm's law, if resistance is doubled and voltage remains constant, current will be halved.
Correct Answer: B — Current halves
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Q. If the resistance of a wire is doubled, what happens to the current flowing through it if the voltage remains constant?
-
A.
It doubles
-
B.
It halves
-
C.
It remains the same
-
D.
It quadruples
Solution
According to Ohm's law, if resistance increases while voltage remains constant, current decreases.
Correct Answer: B — It halves
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Q. If the resistance of a wire is doubled, what happens to the current flowing through it when the voltage remains constant?
-
A.
Doubles
-
B.
Halves
-
C.
Remains the same
-
D.
Increases by 50%
Solution
According to Ohm's law, if resistance increases while voltage remains constant, current decreases.
Correct Answer: B — Halves
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Q. If the resistance of one arm of a Wheatstone bridge is increased, what effect does it have on the balance condition?
-
A.
It remains balanced
-
B.
It becomes unbalanced
-
C.
It depends on the other resistances
-
D.
It increases the current
Solution
Increasing the resistance in one arm will disturb the balance condition, making the bridge unbalanced.
Correct Answer: B — It becomes unbalanced
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