Q. If the mass of an object is tripled, how does its gravitational potential energy change at a constant height?
A.
It triples
B.
It doubles
C.
It remains the same
D.
It increases by a factor of nine
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Solution
Gravitational potential energy U = mgh, so if mass is tripled, U also triples.
Correct Answer: A — It triples
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Q. If the mass of an object is tripled, how does the gravitational potential energy change for a constant height?
A.
It triples
B.
It doubles
C.
It halves
D.
It remains the same
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Solution
Gravitational potential energy is directly proportional to mass, so it triples.
Correct Answer: A — It triples
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Q. If the mass of the Earth is 6 x 10^24 kg and the radius is 6.4 x 10^6 m, what is the gravitational force on a 1 kg mass at the surface?
A.
9.8 N
B.
6.67 N
C.
10 N
D.
8.9 N
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Solution
Using F = G * (m1 * m2) / r^2, F = (6.67 x 10^-11) * (6 x 10^24 * 1) / (6.4 x 10^6)^2 = 9.8 N.
Correct Answer: A — 9.8 N
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Q. If the mass of the Earth is 6 x 10^24 kg and the radius is 6.4 x 10^6 m, what is the gravitational acceleration at the surface of the Earth?
A.
9.8 m/s²
B.
10 m/s²
C.
9.81 m/s²
D.
11 m/s²
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Solution
Using g = G * M / R², where G = 6.67 x 10^-11 N m²/kg², M = 6 x 10^24 kg, and R = 6.4 x 10^6 m, we find g ≈ 9.8 m/s².
Correct Answer: A — 9.8 m/s²
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Q. If the mass of the Earth is 6 × 10^24 kg and its radius is 6.4 × 10^6 m, what is the acceleration due to gravity at its surface?
A.
9.8 m/s²
B.
10 m/s²
C.
9.81 m/s²
D.
8.9 m/s²
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Solution
g = G * M / R² = (6.67 × 10^-11) * (6 × 10^24) / (6.4 × 10^6)² = 9.81 m/s²
Correct Answer: C — 9.81 m/s²
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Q. If the mass of the Earth is M and its radius is R, what is the gravitational acceleration at the surface of the Earth?
A.
g = GM/R^2
B.
g = GMR^2
C.
g = G/MR^2
D.
g = MR/G
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Solution
The gravitational acceleration at the surface of the Earth is given by g = GM/R^2.
Correct Answer: A — g = GM/R^2
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Q. If the mass of the Earth is M and the radius is R, what is the gravitational acceleration at the surface of the Earth?
A.
g = GM/R^2
B.
g = GMR^2
C.
g = G/R
D.
g = M/R^2
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Solution
The gravitational acceleration at the surface of the Earth is given by g = GM/R^2.
Correct Answer: A — g = GM/R^2
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Q. If the mass of the Earth is M and the radius is R, what is the gravitational force acting on a satellite of mass m at a height h?
A.
GmM/R^2
B.
GmM/(R+h)^2
C.
GmM/(R-h)^2
D.
GmM/h^2
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Solution
The gravitational force F acting on a satellite at height h is given by F = GmM/(R+h)^2, where G is the gravitational constant.
Correct Answer: B — GmM/(R+h)^2
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Q. If the mass of the Earth were to double while its radius remained the same, what would happen to the gravitational acceleration at its surface?
A.
It would double
B.
It would remain the same
C.
It would halve
D.
It would increase by a factor of four
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Solution
Gravitational acceleration is directly proportional to mass, so if the mass doubles, g also doubles.
Correct Answer: A — It would double
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Q. If the mass of the Earth were to double while its radius remains the same, what would happen to the gravitational acceleration at its surface?
A.
It would double
B.
It would remain the same
C.
It would halve
D.
It would increase by a factor of four
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Solution
Gravitational acceleration is directly proportional to mass; thus, if the mass doubles, g also doubles.
Correct Answer: A — It would double
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Q. If the mass of the Earth were to double while the radius remains the same, what would happen to the weight of an object on its surface?
A.
It would double
B.
It would remain the same
C.
It would increase by a factor of four
D.
It would decrease by half
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Solution
Weight is proportional to mass; thus, if the Earth's mass doubles, the weight of an object on its surface also doubles.
Correct Answer: A — It would double
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Q. If the mass of the Earth were to double, what would happen to the gravitational force it exerts on an object at its surface?
A.
It would double
B.
It would remain the same
C.
It would increase by a factor of four
D.
It would decrease by half
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Solution
If the mass of the Earth doubles, the gravitational force on an object at its surface would also double.
Correct Answer: A — It would double
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Q. If the mass of the Earth were to double, what would happen to the gravitational force between two objects on its surface?
A.
It would double
B.
It would remain the same
C.
It would be halved
D.
It would quadruple
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Solution
F = G * (m1 * m2) / r², doubling the mass of Earth doubles the force.
Correct Answer: A — It would double
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Q. If the mass of the Earth were to double, what would happen to the gravitational force between the Earth and an object on its surface?
A.
It would double
B.
It would remain the same
C.
It would halve
D.
It would quadruple
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Solution
F ∝ M; if M doubles, F also doubles.
Correct Answer: A — It would double
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Q. If the mass of the Earth were to double, what would happen to the weight of an object on its surface?
A.
It would double
B.
It would remain the same
C.
It would be halved
D.
It would be quartered
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Solution
Weight is directly proportional to mass. If the Earth's mass doubles, the weight of the object also doubles.
Correct Answer: A — It would double
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Q. If the mass of the Earth were to increase while the radius remains constant, what would happen to the gravitational force experienced by an object on its surface?
A.
It would decrease
B.
It would increase
C.
It would remain the same
D.
It would become zero
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Solution
If the mass of the Earth increases, the gravitational force experienced by an object on its surface would increase.
Correct Answer: B — It would increase
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Q. If the mean of a data set is 12 and there are 8 values, what is the total sum of the values?
A.
80
B.
90
C.
100
D.
110
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Solution
Total sum = Mean * Number of values = 12 * 8 = 96.
Correct Answer: A — 80
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Q. If the mean of a data set is 20 and the standard deviation is 4, what is the coefficient of variation?
A.
20%
B.
25%
C.
15%
D.
10%
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Solution
Coefficient of Variation = (Standard Deviation / Mean) * 100 = (4 / 20) * 100 = 20%.
Correct Answer: B — 25%
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Q. If the mean of a data set is 30 and there are 10 values, what is the total sum of the values?
A.
300
B.
310
C.
320
D.
330
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Solution
Total sum = Mean * Number of values = 30 * 10 = 300.
Correct Answer: A — 300
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Q. If the mean of a data set is 50 and the standard deviation is 10, what is the coefficient of variation?
A.
20%
B.
10%
C.
15%
D.
25%
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Solution
Coefficient of Variation = (Standard Deviation / Mean) * 100 = (10 / 50) * 100 = 20%.
Correct Answer: A — 20%
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Q. If the mean of a data set is 50 and there are 10 values, what is the total sum of the values?
A.
500
B.
600
C.
700
D.
800
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Solution
Total sum = Mean * Number of values = 50 * 10 = 500.
Correct Answer: A — 500
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Q. If the measured length of a rod is 20 cm with an error of 0.5 cm, what is the relative error in the measurement?
A.
0.025
B.
0.05
C.
0.0025
D.
0.005
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Solution
Relative error = (Absolute error / Measured value) = 0.5 / 20 = 0.025 or 2.5%
Correct Answer: B — 0.05
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Q. If the measured value of a quantity is 100 with a relative error of 0.02, what is the absolute error?
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Solution
Absolute error = Relative error * Measured value = 0.02 * 100 = 2.
Correct Answer: A — 2
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Q. If the measured value of a quantity is 75 with a relative error of 0.04, what is the true value?
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Solution
Relative error = Absolute error / True value. Let true value be x. 0.04 = |75 - x| / x. Solving gives x = 78.
Correct Answer: B — 78
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Q. If the median of the data set 3, 5, 7, 9, x is 7, what is the value of x?
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Solution
For median to be 7, x must be 7 or less, hence x = 7.
Correct Answer: D — 8
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Q. If the median of the data set {1, 2, 3, 4, 5, 6, 7, 8} is x, what is the value of x?
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Solution
Median = (4 + 5) / 2 = 9 / 2 = 4.5.
Correct Answer: B — 4.5
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Q. If the median of the data set {3, 1, 4, 2, 5} is x, what is the value of x?
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Solution
Sorted data set: {1, 2, 3, 4, 5}. Median = 3.
Correct Answer: B — 3
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Q. If the medians of a triangle are 6 cm, 8 cm, and 10 cm, what is the area of the triangle?
A.
48 cm²
B.
60 cm²
C.
72 cm²
D.
80 cm²
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Solution
Area = (4/3) * √[m1 * m2 * m3] = (4/3) * √[6 * 8 * 10] = 48 cm².
Correct Answer: B — 60 cm²
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Q. If the medians of a triangle are 6, 8, and 10, what is the area of the triangle?
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Solution
Area = (4/3) * √(s(s - m1)(s - m2)(s - m3)), where s = (6 + 8 + 10)/2 = 12. Area = (4/3) * √(12 * 6 * 4 * 2) = 48.
Correct Answer: C — 48
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Q. If the mode of a data set is 5, which of the following statements is true?
A.
5 occurs most frequently
B.
5 is the average
C.
5 is the middle value
D.
5 is the least value
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Solution
Mode is the value that appears most frequently in a data set.
Correct Answer: A — 5 occurs most frequently
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