Potential difference V = W/q = 0.04 J / (2 × 10^-6 C) = 20,000 V = 20 V.

Potential difference V = Work done / Charge = 15 J / 3 C = 5 V.

V = W/q = 0.04 J / (2 × 10^-6 C) = 20 V.

The potential energy U of a charge q in an electric potential V is given by U = qV.

Potential energy U = -p · E. When aligned, U = -pE.

U = k * (q1 * q2) / r = (9 × 10^9) * (3 × 10^-6 * 4 × 10^-6) / 0.2 = 0.54 J.

Potential energy U = k * (q1 * q2) / r = (9 × 10^9) * (3 × 10^-6) * (5 × 10^-6) / 0.2 = 6.75 J.

Potential energy U = k * q1 * q2 / r = (9 × 10^9) * (3 × 10^-6) * (-5 × 10^-6) / 0.3 = -0.45 J.

Potential energy U = k * (q1 * q2) / r = (9 × 10^9) * (5 × 10^-6) * (10 × 10^-6) / 0.2 = 0.225 J.

Potential energy U = k * (q1 * q2) / r = k * (q * q) / r = k*q²/r.

Potential energy U = k * q1 * q2 / r = (9 × 10^9) * (1 × 10^-6) * (-1 × 10^-6) / 0.1 = -0.09 J.

The potential energy U of a system of two point charges is given by U = k(q1q2)/r = -kq²/r for +q and -q.

The potential energy U of a system of two point charges is given by U = k * q1 * q2 / r.

The electric field E is the negative gradient of the electric potential V, given by E = -dV/dr.

The electric field E is the negative gradient of the electric potential V, given by E = -dV/dx.

In a uniform electric field, the relationship is given by E = -dV/dx, indicating that the electric field points in the direction of decreasing potential.

The electric field is the negative gradient of the electric potential, E = -dV/dx.

The electric field just outside a charged conductor is given by E = σ/ε₀.

In a uniform electric field, the electric potential difference V is given by V = E × d, where d is the distance moved in the direction of the field.

The electric field E is the negative gradient of the electric potential V, expressed as E = -dV/dx.

The total electric flux through a closed surface is given by Φ = Q_enc/ε₀, where Q_enc is the enclosed charge.

The unit of capacitance is the Farad (F), which is defined as one coulomb per volt.

The electric field is defined as the force per unit charge, hence its unit is Newton per Coulomb (N/C).

The unit of electric potential is the Volt (V), which is defined as one Joule per Coulomb.

Work done W = F * d = q * E * d = (2 × 10^-6 C) * (500 N/C) * (0.4 m) = 0.4 J = 80 J.

W = q * V = 2 × 10^-6 C * 10 V = 20 × 10^-6 J = 20 μJ.

Work done W = q * V = (2 × 10^-6 C) * (5 V) = 10 μJ.

Work done W = q * ΔV = 2 × 10^-6 C * (100 V - 50 V) = 2 × 10^-6 * 50 = 0.1 mJ.

Work done W = q * ΔV = (2 × 10^-6 C) * (100 V - 50 V) = 100 μJ.

Electric field lines point from positive to negative charges, indicating the direction of the electric field.