Two lines are parallel if their slopes are equal, which occurs when a/d = b/e.

Both lines have the same slope (2) but different y-intercepts, indicating they are parallel.

When two parallel lines are cut by a transversal, alternate interior angles and corresponding angles are equal, while consecutive interior angles are supplementary. Therefore, the correct answer is 'All of the above'.

Both alternate interior angles and corresponding angles are equal when two parallel lines are cut by a transversal.

Typically, partners who contribute more capital may negotiate for a larger share of profits.

To find x, subtract 3 from both sides: x = 7 - 3, which gives x = 4.

We have x = 8 and y = 4. Thus, x/y = 8/4 = 2.

Using the method of successive substitutions or the Chinese Remainder Theorem, the smallest solution is x = 26.

x + y ≡ 4 + 3 ≡ 7 (mod 7), which is equivalent to 0.

Product D would be last based on its Q4 sales figures.

'10' in base 3 is 3 and '11' is 4. Their product is 12, which is '110' in base 3.

'132' in base 4 is calculated as 1*4^2 + 3*4^1 + 2*4^0 = 16 + 12 + 2 = 30.

In base-5, '34' is 3*5 + 4 = 19 and '21' is 2*5 + 1 = 11. Their sum is 30, which is '100' in base-5.

The base-5 number 243 converts to decimal as 2*5^2 + 4*5^1 + 3*5^0 = 50 + 20 + 3 = 73.

In a base-5 numeral system, valid digits are 0, 1, 2, 3, and 4; thus, 5 is not valid.

'12' in base-6 is 1*6 + 2 = 8. '3' is 3. Their product is 8*3 = 24, which is '42' in base-6.

Since Team X scored more points than Team Y, Team X won the game.

The probability that both are smokers is 0.3 * 0.3 = 0.09.

The probability that it does not rain = 1 - P(rain) = 1 - 0.1 = 0.9.

Since 125 can be expressed as 5^3, we have 5^(x+1) = 5^3, thus x + 1 = 3, leading to x = 2.

The remainder when 123 is divided by 10 is 3, as 123 = 10*12 + 3.

The probability of losing all 5 games is (1 - 0.3)^5 = 0.168. Therefore, the probability of winning at least once is 1 - 0.168 = 0.832, which rounds to 0.836.

The relationship of direct proportionality is represented by the equation x = ky, where k is a constant.

Total parts = 5 + 3 = 8. Volume of milk = (5/8) * 32 = 20 liters.

Initial sugar = 1 part, water = 4 parts. Total = 5 parts. New sugar = 2 liters, water = 8 liters. Ratio = 2:8 = 1:4.

Let the initial amount of sugar be x liters and water be 4x liters. After adding 2 liters of sugar, the new ratio becomes (x + 2) : 4x.

'101' in binary is 5, so '111' in binary is 7.

'210' in base 3 is 2*3^2 + 1*3^1 + 0*3^0 = 18 + 3 + 0 = 21. Therefore, '102' in base 3 is 1*3^2 + 0*3^1 + 2*3^0 = 9 + 0 + 2 = 11.

'B' represents 11 in the same system where 'A' is 10.

'B' (18) is a multiple of 'A' (12) since 18 can be expressed as 12 multiplied by 1.5.