Circles that intersect at two points are said to be secant to each other.

The centers of the circles are equidistant from the intersection points, making option 0 true.

The combinations for a sum greater than 10 are (5,6), (6,5), (6,6), giving a probability of 3/36 = 1/12.

The combinations that give a sum of 7 are (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), totaling 6 combinations. The total outcomes are 36, so the probability is 6/36 = 1/6.

Two lines are parallel if their slopes are equal, which occurs when a/d = b/e.

Both lines have the same slope (2) but different y-intercepts, indicating they are parallel.

Both lines have the same slope (2) but different y-intercepts, indicating they are parallel.

Lines with the same slope but different y-intercepts are parallel and will never intersect.

The HCF of 18 and 24 is 6, as it is the largest number that divides both.

Both alternate interior angles and corresponding angles are equal when two parallel lines are cut by a transversal.

When two parallel lines are cut by a transversal, alternate interior angles and corresponding angles are equal, while consecutive interior angles are supplementary. Therefore, the correct answer is 'All of the above'.

The first step in dissolving a partnership is to draft a dissolution agreement that outlines the terms of the dissolution.

Typically, partners who contribute more capital may negotiate for a larger share of profits.

To find x, subtract 3 from both sides: x = 7 - 3, which gives x = 4.

Calculating, we find 2^3 + 3^2 = 8 + 9 = 17.

We have x = 8 and y = 4. Thus, x/y = 8/4 = 2.

x + y ≡ 2 + 1 ≡ 3 (mod 3), which is equivalent to 0, but since we are looking for the value, it is 0 mod 3.

Using the method of successive substitutions or the Chinese Remainder Theorem, the smallest solution is x = 26.

x + y ≡ 4 + 3 ≡ 7 (mod 7), which is equivalent to 0.

In base 3, the decimal number 5 is represented as '12' (1*3^1 + 2*3^0 = 3 + 2 = 5).

'54' in base 6 = 5*6^1 + 4*6^0 = 30 + 4 = 34.

'57' in base 8 is calculated as 5*8^1 + 7*8^0 = 40 + 7 = 47.

'10' in base 3 is 3 and '11' is 4. Their product is 12, which is '110' in base 3.

'210' in base-3 is 2*3^2 + 1*3^1 + 0*3^0 = 18 + 3 + 0 = 21 in decimal.

'132' in base 4 is calculated as 1*4^2 + 3*4^1 + 2*4^0 = 16 + 12 + 2 = 30.

The sum of '12' and '21' in base-4 is '30' in base-4.

2*5^2 + 4*5^1 + 3*5^0 = 50 + 20 + 3 = 73.

In base-5, '23' is 2*5 + 3 = 13 and '14' is 1*5 + 4 = 9. Their sum is 22 in decimal, which is '42' in base-5.

In base-5, '34' is 3*5 + 4 = 19 and '21' is 2*5 + 1 = 11. Their sum is 30, which is '100' in base-5.

The base-5 number 243 converts to decimal as 2*5^2 + 4*5^1 + 3*5^0 = 50 + 20 + 3 = 73.