The wavelength of light decreases in a medium with a refractive index greater than 1, as it is given by λ' = λ/n.

The wavelength of light decreases in a medium with a refractive index greater than 1, as λ' = λ/n.

When light reflects off a medium with a higher refractive index, it undergoes a phase change of π (180 degrees).

Using the formula sin(θc) = n2/n1, where n1 = 2.42 (diamond) and n2 = 1.00 (air), we find θc ≈ 24.4°.

When the slit width is equal to the wavelength, a wide central maximum is observed due to significant diffraction.

Halving the slit width increases the angular width of the central maximum, making it double.

If the slit width is halved, the width of the central maximum doubles, as it is inversely proportional to the slit width.

Speed of light in medium = c/n = (3 x 10^8 m/s) / 1.5 = 2 x 10^8 m/s.

The wavelength in a medium is given by λ' = λ/n. Thus, λ' = 600 nm / 1.5 = 400 nm.

Wavelength in glass (λ') = λ/n = 600 nm / 1.5 = 400 nm.

Frequency (f) is inversely proportional to wavelength (λ). If λ is halved, f doubles.

Halving the wavelength causes the minima to move closer together, as the angle for minima is directly proportional to the wavelength.

Halving the wavelength will halve the angle for the first minimum, as the position of minima is directly proportional to the wavelength.

Halving the wavelength results in the first minimum moving closer to the center, as the position of minima is directly related to the wavelength.

Increasing the wavelength results in a broader diffraction pattern as the angles for minima and maxima increase.

Distance between fringes = (λD)/d = (600 x 10^-9 m * 2 m) / (0.3 x 10^-3 m) = 0.004 m = 0.4 m.

Increasing the wavelength increases the fringe width, causing the fringes to move further apart.

Fringe separation β = λD/d = (500 x 10^-9 m)(2 m)/(0.1 x 10^-3 m) = 0.01 m.

Fringe separation (β) = λD/d. β = (600 x 10^-9 * 2) / 0.0001 = 0.012 m. Distance between first and second bright fringes = 2β = 0.024 m.

Fringe width (β) = (λD)/d = (600 x 10^-9 * 2)/(0.1 x 10^-3) = 0.012 mm = 0.06 mm.

When two coherent sources are in phase, they produce constructive interference, resulting in bright fringes.

When two coherent sources are in phase, they produce constructive interference, resulting in bright fringes.

A path difference of λ/2 corresponds to a phase difference of π radians, leading to destructive interference.

The phase difference (Δφ) is given by (2π/λ) * path difference. For a path difference of λ/4, Δφ = (2π/λ) * (λ/4) = π/2 radians.

A path difference of λ/2 results in destructive interference, as the waves will be out of phase.

When two polarizers are oriented at 90 degrees to each other, no light can pass through, resulting in zero intensity.

When two polarizers are oriented at 90 degrees to each other, no light passes through, resulting in zero intensity.

When two polarizers are at 90 degrees to each other, no light passes through, resulting in minimum intensity.

A phase difference of π radians results in destructive interference.

Constructive interference occurs when the path difference is nλ, where n is an integer.