Q. A loop of wire is moved into a magnetic field at a constant speed. What is the effect on the induced current as the loop enters the field?
A.It increases
B.It decreases
C.It remains constant
D.It becomes zero
Solution
As the loop enters the magnetic field, the area of the loop within the field increases, leading to an increase in magnetic flux and thus an increase in the induced current according to Faraday's law.
Q. A loop of wire is placed in a uniform magnetic field. If the angle between the field and the normal to the loop is 60 degrees, what is the effective magnetic flux?
A.0.5 B A
B.0.866 B A
C.0.866 B A²
D.B A
Solution
Effective magnetic flux (Φ) = B * A * cos(θ) = B * A * cos(60°) = 0.5 B A.
Q. A loop of wire is placed in a uniform magnetic field. What happens if the magnetic field strength is increased?
A.Induced current flows in the loop
B.No effect on the loop
C.The loop will heat up
D.The loop will move
Solution
According to Faraday's law of electromagnetic induction, a change in magnetic field strength induces an electromotive force (EMF) in the loop, causing a current to flow.
Correct Answer: A — Induced current flows in the loop
Q. A loop of wire is placed in a uniform magnetic field. What happens to the induced EMF if the area of the loop is increased?
A.Increases
B.Decreases
C.Remains the same
D.Depends on the magnetic field strength
Solution
According to Faraday's law of electromagnetic induction, the induced EMF is directly proportional to the rate of change of magnetic flux, which increases with an increase in the area of the loop.
Q. A particle with charge q moves with velocity v in a magnetic field B. What is the expression for the magnetic force acting on the particle?
A.F = qvB
B.F = qvB sin(θ)
C.F = qB
D.F = qvB cos(θ)
Solution
The magnetic force acting on a charged particle moving in a magnetic field is given by F = qvB sin(θ), where θ is the angle between the velocity vector and the magnetic field vector.
Q. A solenoid produces a uniform magnetic field inside it. What factors affect the strength of this magnetic field?
A.Length of the solenoid
B.Number of turns per unit length
C.Current through the solenoid
D.All of the above
Solution
The strength of the magnetic field inside a solenoid is affected by the number of turns per unit length and the current flowing through it, as well as the length of the solenoid.
Q. A solenoid with a length of 1 m and a cross-sectional area of 0.01 m² carries a current of 5 A. If the magnetic field inside the solenoid is uniform, what is the magnetic field strength?
A.0.1 T
B.0.2 T
C.0.5 T
D.1 T
Solution
The magnetic field inside a solenoid is given by B = μ₀ * (N/L) * I. Assuming N/L = 1 for simplicity, B = μ₀ * I = 4π × 10^-7 T*m/A * 5 A = 0.5 T.
Q. A transformer operates on the principle of electromagnetic induction. If the primary coil has 100 turns and the secondary coil has 50 turns, what is the relationship between the primary and secondary voltages?
A.V_primary = 2 * V_secondary
B.V_primary = 0.5 * V_secondary
C.V_primary = V_secondary
D.V_primary = 4 * V_secondary
Solution
The voltage ratio in a transformer is given by the turns ratio. Therefore, V_primary/V_secondary = N_primary/N_secondary = 100/50 = 2, which means V_primary = 2 * V_secondary.
Q. A transformer operates on the principle of electromagnetic induction. What is the primary function of a transformer?
A.To increase voltage
B.To decrease voltage
C.To convert AC to DC
D.To store energy
Solution
A transformer is designed to increase or decrease the voltage in an AC circuit through electromagnetic induction, depending on the turns ratio of the primary and secondary coils.
