Weight is proportional to mass; thus, if the Earth's mass doubles, the weight of an object on its surface also doubles.

F = G * (m1 * m2) / r², doubling the mass of Earth doubles the force.

If the mass of the Earth doubles, the gravitational force on an object at its surface would also double.

F ∝ M; if M doubles, F also doubles.

Weight is directly proportional to mass. If the Earth's mass doubles, the weight of the object also doubles.

If the mass of the Earth increases, the gravitational force experienced by an object on its surface would increase.

If the radius is halved, the gravitational acceleration becomes four times stronger, as g is inversely proportional to the square of the radius.

g ∝ 1/R². If R is halved, g becomes 4 times greater.

The distance from the center of the Earth to a geostationary satellite is approximately 42000 km.

g = G * M / R²; if R is doubled, g becomes g/4.

Gravitational force is inversely proportional to the square of the radius. If the radius is doubled, the force becomes 1/4 of the original.

The orbital speed v of a satellite is given by v = sqrt(GM/(R+h)), where M is the mass of the Earth and G is the gravitational constant.

A geostationary satellite orbits at a height of approximately 36,000 km above the Earth's surface, which is about R (the radius of the Earth) plus the height of the satellite.

The gravitational force acting on the satellite is given by Newton's law of gravitation, which states that F = G * (M * m) / (R + h)^2, where M is the mass of the Earth and m is the mass of the satellite.

At a height R above the Earth's surface, the gravitational acceleration is g/4, derived from the formula g' = g(R/(R+h))^2.

The radius of a geostationary orbit is approximately 3R, where R is the radius of the Earth.

Gravitational acceleration is inversely proportional to the square of the radius, so it would be quartered.

The gravitational force is inversely proportional to the square of the distance. If the radius doubles, the force decreases to one-fourth.

Weight is proportional to 1/r^2; if the radius doubles, the weight becomes four times less.

Gravitational acceleration is inversely proportional to the square of the radius. If the radius doubles, g becomes 1/(2^2) = 1/4 of the original value.

Gravitational acceleration is inversely proportional to the square of the radius. If the radius is halved, g becomes 4 times greater.

The orbital speed v is given by v = √(GM/r). If r is doubled, v decreases by a factor of √2.

As the distance between two masses decreases, the gravitational force increases according to the inverse square law.

If the distance is halved, the force becomes 1/(1/2)^2 = 4 times stronger.

F = G * (m1 * m2) / r^2 = (6.67 x 10^-11) * (1 * 1) / (1^2) = 6.67 x 10^-11 N.

If the distance is halved, the gravitational force increases by a factor of four, as it is inversely proportional to the square of the distance.

The gravitational potential energy is considered maximum at infinity, where it is defined to be zero.

A satellite experiences weightlessness when it is in free fall, as both the satellite and its occupants are accelerating towards the Earth at the same rate.

The gravitational field inside a uniform spherical shell is zero.

V = -g * r = -9.8 N/kg * 6.4 x 10^6 m = -62.72 x 10^6 J/kg.