Capacitance
Q. In a capacitor, if the plate area is increased while keeping the separation constant, what happens to the capacitance?
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A.
It increases
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B.
It decreases
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C.
It remains the same
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D.
It becomes zero
Solution
Capacitance is directly proportional to the plate area A. Increasing A increases capacitance.
Correct Answer: A — It increases
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Q. In a capacitor, what does the dielectric constant represent?
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A.
The ability to store charge
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B.
The ability to resist electric field
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C.
The ability to increase capacitance
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D.
The ability to conduct electricity
Solution
The dielectric constant represents the ability of a material to increase the capacitance of a capacitor compared to a vacuum.
Correct Answer: C — The ability to increase capacitance
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Q. In a capacitor, what is the relationship between charge (Q), capacitance (C), and voltage (V)?
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A.
Q = C + V
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B.
Q = C * V
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C.
Q = V / C
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D.
Q = C - V
Solution
The relationship is given by Q = C * V, where Q is the charge, C is the capacitance, and V is the voltage.
Correct Answer: B — Q = C * V
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Q. In a circuit, a capacitor is charged and then discharged through a resistor. What is the time constant of the circuit?
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A.
RC
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B.
C/R
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C.
R/C
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D.
1/RC
Solution
The time constant (τ) of an RC circuit is given by τ = R * C.
Correct Answer: A — RC
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Q. In a circuit, if a capacitor is fully charged, what is the voltage across it?
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A.
Zero
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B.
Equal to the source voltage
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C.
Half of the source voltage
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D.
Double the source voltage
Solution
When a capacitor is fully charged, the voltage across it is equal to the voltage of the source it was connected to.
Correct Answer: B — Equal to the source voltage
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Q. In a circuit, two capacitors of capacitance 2μF and 3μF are connected in parallel. What is the total capacitance?
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A.
5μF
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B.
6μF
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C.
1.2μF
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D.
0.6μF
Solution
The total capacitance C_total in parallel is the sum of individual capacitances: C_total = C1 + C2 = 2μF + 3μF = 5μF.
Correct Answer: A — 5μF
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Q. In a circuit, two capacitors of capacitance 3μF and 6μF are connected in parallel. What is the total capacitance?
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A.
9μF
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B.
2μF
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C.
18μF
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D.
1μF
Solution
In parallel, the total capacitance is the sum: C_total = C1 + C2 = 3μF + 6μF = 9μF.
Correct Answer: A — 9μF
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Q. In a circuit, two capacitors of capacitance 4μF and 6μF are connected in parallel. What is the total capacitance?
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A.
10μF
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B.
24μF
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C.
2.4μF
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D.
0.4μF
Solution
For capacitors in parallel, the total capacitance is the sum of the individual capacitances: C_total = C1 + C2 = 4μF + 6μF = 10μF.
Correct Answer: A — 10μF
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Q. In a parallel combination of capacitors, how is the total capacitance calculated?
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A.
C_eq = C1 + C2 + C3
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B.
1/C_eq = 1/C1 + 1/C2 + 1/C3
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C.
C_eq = 1/(C1 + C2 + C3)
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D.
C_eq = C1 * C2 * C3
Solution
In a parallel combination, the total capacitance is simply the sum of the individual capacitances: C_eq = C1 + C2 + C3.
Correct Answer: A — C_eq = C1 + C2 + C3
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Q. In a parallel plate capacitor, if the area of the plates is doubled while keeping the separation constant, what happens to the capacitance?
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A.
It doubles
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B.
It halves
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C.
It remains the same
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D.
It quadruples
Solution
Capacitance is directly proportional to the area of the plates. Doubling the area will double the capacitance.
Correct Answer: A — It doubles
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Q. Two capacitors, C1 = 2μF and C2 = 3μF, are connected in series. What is the equivalent capacitance?
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A.
1.2μF
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B.
5μF
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C.
6μF
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D.
0.6μF
Solution
For capacitors in series, the equivalent capacitance C_eq is given by 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/2 + 1/3 = 5/6, so C_eq = 6/5 = 1.2μF.
Correct Answer: A — 1.2μF
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Q. Two capacitors, C1 and C2, are connected in series. What is the equivalent capacitance?
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A.
C1 + C2
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B.
1 / (1/C1 + 1/C2)
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C.
C1 * C2 / (C1 + C2)
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D.
C1 - C2
Solution
The equivalent capacitance of capacitors in series is given by 1 / (1/C1 + 1/C2).
Correct Answer: B — 1 / (1/C1 + 1/C2)
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Q. What happens to the capacitance of a capacitor if the dielectric constant is doubled?
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A.
It doubles
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B.
It halves
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C.
It remains the same
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D.
It quadruples
Solution
The capacitance C of a capacitor is directly proportional to the dielectric constant k. If k is doubled, C also doubles.
Correct Answer: A — It doubles
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Q. What happens to the energy stored in a capacitor if the voltage across it is doubled?
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A.
It doubles
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B.
It quadruples
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C.
It remains the same
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D.
It halves
Solution
The energy stored in a capacitor is given by U = 1/2 C V². If the voltage is doubled, the energy increases by a factor of four.
Correct Answer: B — It quadruples
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Q. What happens to the potential difference across a capacitor when it is fully charged?
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A.
It becomes zero
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B.
It becomes maximum
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C.
It becomes minimum
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D.
It fluctuates
Solution
When a capacitor is fully charged, the potential difference across its plates becomes maximum and remains constant until it is discharged.
Correct Answer: B — It becomes maximum
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Q. What happens to the voltage across a capacitor when it is fully charged?
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A.
It becomes zero
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B.
It equals the supply voltage
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C.
It becomes negative
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D.
It fluctuates
Solution
When a capacitor is fully charged, the voltage across it equals the supply voltage.
Correct Answer: B — It equals the supply voltage
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Q. What is the capacitance of a parallel plate capacitor with area A and separation d?
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A.
ε₀ * A / d
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B.
A / (ε₀ * d)
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C.
d / (ε₀ * A)
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D.
ε₀ * d / A
Solution
The capacitance C of a parallel plate capacitor is given by the formula C = ε₀ * A / d, where ε₀ is the permittivity of free space.
Correct Answer: A — ε₀ * A / d
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Q. What is the capacitance of a parallel plate capacitor with plate area A and separation d?
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A.
ε₀A/d
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B.
d/ε₀A
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C.
A/ε₀d
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D.
ε₀d/A
Solution
The capacitance C of a parallel plate capacitor is given by the formula C = ε₀A/d, where ε₀ is the permittivity of free space.
Correct Answer: A — ε₀A/d
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Q. What is the effect of increasing the plate area of a capacitor on its capacitance?
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A.
Capacitance increases
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B.
Capacitance decreases
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C.
Capacitance remains the same
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D.
Capacitance becomes zero
Solution
Increasing the plate area A of a capacitor increases its capacitance, as C is directly proportional to A.
Correct Answer: A — Capacitance increases
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Q. What is the effect of increasing the plate area of a parallel plate capacitor?
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A.
Capacitance decreases
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B.
Capacitance increases
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C.
Capacitance remains the same
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D.
Capacitance becomes zero
Solution
Increasing the plate area A of a parallel plate capacitor increases its capacitance, as C = ε₀ * A / d.
Correct Answer: B — Capacitance increases
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Q. What is the effect of inserting a dielectric material between the plates of a capacitor?
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A.
Increases capacitance
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B.
Decreases capacitance
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C.
No effect on capacitance
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D.
Changes the voltage across the plates
Solution
Inserting a dielectric material increases the capacitance of the capacitor by a factor equal to the dielectric constant of the material.
Correct Answer: A — Increases capacitance
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Q. What is the effect of temperature on the capacitance of a capacitor?
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A.
Increases capacitance
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B.
Decreases capacitance
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C.
No effect
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D.
Depends on the dielectric
Solution
The effect of temperature on capacitance depends on the dielectric material used in the capacitor.
Correct Answer: D — Depends on the dielectric
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Q. What is the energy stored in a capacitor of capacitance C charged to a voltage V?
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A.
1/2 CV
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B.
CV
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C.
1/2 C/V
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D.
C/V
Solution
The energy (U) stored in a capacitor is given by the formula U = 1/2 CV².
Correct Answer: A — 1/2 CV
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Q. What is the energy stored in a capacitor with capacitance C charged to a voltage V?
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A.
1/2 CV²
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B.
CV
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C.
1/2 V²/C
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D.
C²V
Solution
The energy (U) stored in a capacitor is given by the formula U = 1/2 CV².
Correct Answer: A — 1/2 CV²
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Q. What is the energy stored in a capacitor with capacitance C charged to voltage V?
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A.
1/2 CV
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B.
CV
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C.
1/2 C/V
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D.
C/V
Solution
The energy (U) stored in a capacitor is given by the formula U = 1/2 CV².
Correct Answer: A — 1/2 CV
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Q. What is the unit of capacitance?
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A.
Farad
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B.
Coulomb
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C.
Volt
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D.
Ohm
Solution
The unit of capacitance is the Farad (F), which is defined as one coulomb per volt.
Correct Answer: A — Farad
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