Current Electricity
Q. If the galvanometer in a Wheatstone bridge shows a deflection, what does it indicate?
A.
The bridge is balanced.
B.
The bridge is unbalanced.
C.
The resistances are equal.
D.
The circuit is open.
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Solution
A deflection in the galvanometer indicates that the bridge is unbalanced, meaning the ratios of resistances are not equal.
Correct Answer: B — The bridge is unbalanced.
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Q. If the galvanometer shows a deflection in a Wheatstone bridge, what can be inferred?
A.
The bridge is balanced
B.
The bridge is unbalanced
C.
The resistances are equal
D.
The circuit is open
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Solution
A deflection in the galvanometer indicates that there is a potential difference across it, meaning the bridge is unbalanced.
Correct Answer: B — The bridge is unbalanced
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Q. If the galvanometer shows a deflection when the Wheatstone bridge is not balanced, what does it indicate?
A.
The bridge is balanced
B.
The resistances are equal
C.
There is a potential difference
D.
The circuit is open
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Solution
A deflection in the galvanometer indicates that there is a potential difference across it, meaning the bridge is not balanced.
Correct Answer: C — There is a potential difference
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Q. If the internal resistance of a cell is negligible, how does it affect the accuracy of a potentiometer measurement?
A.
It increases accuracy
B.
It decreases accuracy
C.
It has no effect
D.
It makes the measurement impossible
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Solution
If the internal resistance of a cell is negligible, it increases the accuracy of the potentiometer measurement as it does not affect the voltage being measured.
Correct Answer: A — It increases accuracy
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Q. If the known voltage in a potentiometer is 12 V and the length of the wire is 6 m, what is the potential gradient?
A.
2 V/m
B.
3 V/m
C.
4 V/m
D.
6 V/m
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Solution
The potential gradient is calculated as V/L = 12 V / 6 m = 2 V/m.
Correct Answer: A — 2 V/m
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Q. If the length of a wire is doubled while keeping the cross-sectional area constant, how does its resistance change?
A.
Remains the same
B.
Doubles
C.
Halves
D.
Quadruples
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Solution
Resistance is directly proportional to length; doubling the length doubles the resistance.
Correct Answer: B — Doubles
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Q. If the length of the potentiometer wire is increased while keeping the voltage constant, what will happen to the balance point when measuring a cell's EMF?
A.
It will move to a longer length.
B.
It will move to a shorter length.
C.
It will remain unchanged.
D.
It will become unstable.
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Solution
Increasing the length of the potentiometer wire while keeping the voltage constant will increase the balance point length for the same EMF.
Correct Answer: A — It will move to a longer length.
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Q. If the length of the potentiometer wire is increased, what effect does it have on the maximum measurable voltage?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes zero
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Solution
Increasing the length of the potentiometer wire increases the maximum measurable voltage due to a larger potential gradient.
Correct Answer: A — It increases
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Q. If the resistance in a circuit is doubled while keeping the voltage constant, what happens to the current?
A.
It doubles.
B.
It halves.
C.
It remains the same.
D.
It quadruples.
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Solution
According to Ohm's Law (I = V/R), if resistance (R) is doubled and voltage (V) remains constant, the current (I) will be halved.
Correct Answer: B — It halves.
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Q. If the resistance in one arm of a Wheatstone bridge is increased, what effect does it have on the balance condition?
A.
The bridge will always remain balanced.
B.
The bridge will become unbalanced.
C.
The balance condition will improve.
D.
It has no effect.
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Solution
Increasing the resistance in one arm will disturb the balance condition, making the bridge unbalanced.
Correct Answer: B — The bridge will become unbalanced.
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Q. If the resistance in one arm of a Wheatstone bridge is increased, what happens to the balance condition?
A.
It remains balanced
B.
It becomes unbalanced
C.
It depends on other resistances
D.
It becomes short-circuited
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Solution
Increasing the resistance in one arm will disturb the balance condition, making it unbalanced.
Correct Answer: B — It becomes unbalanced
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Q. If the resistance of a circuit is doubled while the voltage remains constant, what happens to the current?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
According to Ohm's Law, I = V/R. If R is doubled, the current I will be halved.
Correct Answer: B — It halves
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Q. If the resistance of a wire is doubled, how does it affect the current flowing through it when connected to a constant voltage source?
A.
Current doubles
B.
Current halves
C.
Current remains the same
D.
Current quadruples
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Solution
According to Ohm's law, if resistance is doubled and voltage remains constant, current will be halved.
Correct Answer: B — Current halves
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Q. If the resistance of a wire is doubled, what happens to the current flowing through it if the voltage remains constant?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
According to Ohm's law, if resistance increases while voltage remains constant, current decreases.
Correct Answer: B — It halves
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Q. If the resistance of a wire is doubled, what happens to the current flowing through it when the voltage remains constant?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases by 50%
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Solution
According to Ohm's law, if resistance increases while voltage remains constant, current decreases.
Correct Answer: B — Halves
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Q. If the resistance of one arm of a Wheatstone bridge is increased, what effect does it have on the balance condition?
A.
It remains balanced
B.
It becomes unbalanced
C.
It depends on the other resistances
D.
It increases the current
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Solution
Increasing the resistance in one arm will disturb the balance condition, making the bridge unbalanced.
Correct Answer: B — It becomes unbalanced
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Q. If the resistance of one arm of a Wheatstone bridge is increased, what will happen to the balance condition?
A.
The bridge will remain balanced
B.
The bridge will become unbalanced
C.
The bridge will balance at a different point
D.
The bridge will short circuit
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Solution
Increasing the resistance in one arm will disturb the balance condition, causing the bridge to become unbalanced.
Correct Answer: B — The bridge will become unbalanced
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Q. If the resistance of one of the arms in a Wheatstone bridge is increased, what effect does it have on the balance condition?
A.
The bridge remains balanced.
B.
The bridge becomes unbalanced.
C.
The current through the galvanometer increases.
D.
The potential difference across the galvanometer decreases.
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Solution
Increasing the resistance in one arm disrupts the balance condition, causing the bridge to become unbalanced.
Correct Answer: B — The bridge becomes unbalanced.
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Q. If the resistance of one of the resistors in a Wheatstone bridge is changed, what will happen to the balance condition?
A.
It will remain unchanged.
B.
It will become balanced.
C.
It will become unbalanced.
D.
It will depend on the value of the changed resistor.
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Solution
Changing the resistance of one of the resistors will alter the ratio, thus making the bridge unbalanced.
Correct Answer: C — It will become unbalanced.
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Q. If the resistance of the potentiometer wire is increased, what effect does it have on the potential gradient?
A.
It increases.
B.
It decreases.
C.
It remains the same.
D.
It becomes zero.
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Solution
Increasing the resistance of the potentiometer wire decreases the potential gradient, as the same voltage is now distributed over a higher resistance.
Correct Answer: B — It decreases.
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Q. If the resistance of the potentiometer wire is increased, what effect does it have on the measurement accuracy?
A.
Increases accuracy
B.
Decreases accuracy
C.
No effect
D.
Depends on the length of the wire
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Solution
Increasing the resistance of the potentiometer wire can lead to a larger voltage drop, which may decrease measurement accuracy due to increased error in balancing.
Correct Answer: B — Decreases accuracy
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Q. If the resistance P in a Wheatstone bridge is 10 ohms, Q is 15 ohms, R is 5 ohms, and S is 7.5 ohms, what is the condition for the bridge to be balanced?
A.
P/Q = R/S
B.
P/R = Q/S
C.
P/S = Q/R
D.
P + Q = R + S
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Solution
The condition for balance is P/Q = R/S, which is not satisfied here.
Correct Answer: A — P/Q = R/S
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Q. If the resistance R1 in a Wheatstone bridge is increased, what effect does it have on the balance condition?
A.
The bridge becomes balanced
B.
The bridge becomes unbalanced
C.
No effect
D.
Depends on other resistances
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Solution
Increasing R1 changes the ratio R1/R2, which can lead to the bridge becoming unbalanced if the other resistances remain constant.
Correct Answer: B — The bridge becomes unbalanced
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Q. If the resistance R1 in a Wheatstone bridge is increased, what happens to the balance condition?
A.
The bridge remains balanced
B.
The bridge becomes unbalanced
C.
The bridge becomes balanced again
D.
The current through the galvanometer increases
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Solution
Increasing R1 will disturb the balance condition, making the bridge unbalanced.
Correct Answer: B — The bridge becomes unbalanced
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Q. If the resistance R1 in a Wheatstone bridge is increased, what happens to the current through the galvanometer?
A.
It increases.
B.
It decreases.
C.
It remains the same.
D.
It becomes zero.
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Solution
Increasing R1 will unbalance the bridge, causing a current to flow through the galvanometer, which indicates a decrease in current through it.
Correct Answer: B — It decreases.
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Q. If the resistance R1 is increased in a Wheatstone bridge, what happens to the balance condition?
A.
It remains balanced
B.
It becomes unbalanced
C.
It depends on R2
D.
It depends on R3 and R4
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Solution
Increasing R1 will disturb the balance unless R2 is also adjusted accordingly.
Correct Answer: B — It becomes unbalanced
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Q. If the resistance R2 in a Wheatstone bridge is halved, what effect does it have on the balance condition?
A.
The bridge remains balanced
B.
The bridge becomes unbalanced
C.
The bridge becomes balanced again
D.
The current through the galvanometer decreases
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Solution
Halving R2 will disturb the balance condition, making the bridge unbalanced.
Correct Answer: B — The bridge becomes unbalanced
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Q. If the resistance R4 in a Wheatstone bridge is decreased, what effect does it have on the balance condition?
A.
The bridge becomes balanced
B.
The bridge becomes unbalanced
C.
The current through the galvanometer decreases
D.
The voltage across R1 increases
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Solution
Decreasing R4 will disturb the balance condition, making the bridge unbalanced.
Correct Answer: B — The bridge becomes unbalanced
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Q. If the resistance values in a Wheatstone bridge are all equal, what can be inferred about the bridge?
A.
It is always balanced.
B.
It is always unbalanced.
C.
The current through the galvanometer is zero.
D.
The potential difference across the galvanometer is maximum.
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Solution
If all resistances are equal, the bridge is balanced, leading to zero current through the galvanometer.
Correct Answer: A — It is always balanced.
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Q. If the resistance values in a Wheatstone bridge are all equal, what can be said about the bridge?
A.
It is always balanced
B.
It is always unbalanced
C.
It depends on the circuit configuration
D.
It cannot be determined
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Solution
If all resistance values are equal, the Wheatstone bridge is always balanced, resulting in zero current through the galvanometer.
Correct Answer: A — It is always balanced
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