In a balanced Wheatstone bridge, the potential difference across the galvanometer is zero.

In a balanced Wheatstone bridge, the ratio of the resistances in one arm equals the ratio in the other arm, hence R1/R2 = R3/R4.

The effect of temperature on resistance measurements in a Wheatstone bridge depends on the material of the resistors, as different materials have different temperature coefficients.

In general, the resistance of conductors increases with temperature due to increased atomic vibrations.

Temperature changes can affect the resistance values of the resistors, thus affecting the balance condition.

Non-ideal resistors can introduce errors in the measurements due to their tolerance and temperature coefficients.

When all resistances are equal, the bridge is balanced regardless of the configuration.

Changing one resistor can either balance or unbalance the bridge depending on the new value relative to the others.

Using the balance condition P/Q = R/S, we find S = 15Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 30) / 10 = 45Ω.

Using the balance condition R1/R2 = R3/R4, we have 10/20 = 30/R4, which gives R4 = 20Ω.

For balance, R1/R2 = R3/R4. Thus, 10/20 = 15/R4, giving R4 = 30Ω.

Using the balance condition R1/R2 = R3/R4, we have 1/2 = 3/R4. Solving gives R4 = 6Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (30 * 10) / 20 = 15Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (30 * 10) / 20 = 15Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (3 * 6) / 2 = 9Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (3 * 6) / 2 = 9Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = 6Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (6 * 12) / 4 = 18Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (10 * 15) / 5 = 30Ω.

Using the balance condition R1/R2 = R3/R4, we have 5/10 = 15/x, solving gives x = 7.5Ω.

In a balanced Wheatstone bridge, the current through the galvanometer is zero.

In a balanced Wheatstone bridge, the voltage is divided equally across the resistors, so each resistor will have 6V.

With equal resistances, the voltage across the galvanometer is 0V.

The balance condition depends on the ratio of resistances, not the voltage.

In a balanced Wheatstone bridge, the ratio of the resistances in one branch is equal to the ratio in the other branch, hence R1/R2 = R3/R4.

When the Wheatstone bridge is unbalanced, a current flows through the galvanometer, indicating a difference in potential across it.

A current in the galvanometer indicates that the bridge is unbalanced.

A current in the galvanometer indicates that the bridge is unbalanced.

If the galvanometer shows a current, it indicates that the bridge is unbalanced.