1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6 = 1. Therefore, R_eq = 3Ω.

The formula for equivalent resistance in parallel is 1/R_eq = 1/R1 + 1/R2 + 1/R3. Thus, 1/R_eq = 1/6 + 1/3 + 1/2 = 1/6 + 2/6 + 3/6 = 6/6 = 1, so R_eq = 1 ohm.

The equivalent resistance in parallel is given by 1/R_total = 1/R1 + 1/R2 + 1/R3. Thus, 1/R_total = 1/2 + 1/3 + 1/6 = 1Ω.

For parallel resistors, 1/R_eq = 1/R1 + 1/R2. Thus, 1/R_eq = 1/4 + 1/6 = 5/12, so R_eq = 12/5 = 2.4 ohms.

First, find the equivalent resistance: 1/R_eq = 1/4 + 1/6 => R_eq = 2.4 ohms. Then, I = V/R_eq = 12V / 2.4Ω = 5 A.

First, find the equivalent resistance: 1/R_eq = 1/4 + 1/6 => R_eq = 2.4 ohms. Then, I = V/R_eq = 12 V / 2.4 ohms = 5 A.

First, find the equivalent resistance: 1/R_eq = 1/4 + 1/6 => R_eq = 2.4Ω. Then, I = V/R_eq = 12V / 2.4Ω = 5A.

Using the formula for resistors in parallel, 1/R_eq = 1/R1 + 1/R2, we have 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6. Therefore, R_eq = 6/3 = 2 ohms.

1/R_eq = 1/R1 + 1/R2 = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, thus R_eq = 2Ω.

In a parallel circuit, if one resistor fails, the total current decreases because the total resistance increases.

In a parallel circuit, removing a resistor decreases the total resistance.

In a parallel combination, the total capacitance is simply the sum of the individual capacitances: C_eq = C1 + C2 + C3.

Capacitance is directly proportional to the area of the plates. Doubling the area will double the capacitance.

The electric potential V is directly proportional to the distance d between the plates, so if d is doubled, V also doubles.

Capacitance C = ε₀ * A / d. If d is halved, C doubles.

In a parallel RLC circuit, increasing frequency generally increases the total current due to lower reactance.

Increasing the intensity of light increases the number of photons hitting the surface, which in turn increases the number of emitted electrons.

If the frequency of light is just above the threshold frequency, the emitted electrons will have zero kinetic energy, as all the energy is used to overcome the work function.

Increasing the stopping potential indicates that the emitted electrons have higher kinetic energy, as more energy is required to stop them.

The stopping potential does not affect the energy of the emitted electrons; it only affects the number of electrons reaching the detector.

Increasing the stopping potential increases the maximum kinetic energy of the emitted electrons, as the stopping potential is directly related to the kinetic energy of the electrons.

Increasing the stopping potential reduces the number of electrons reaching the anode, thus decreasing the current.

Relative uncertainty = (absolute uncertainty / measured value) = 1 / 50 = 0.02.

Kinetic energy = 0.5 * m * v²; maximum error = m * v * uncertainty in v = m * 20.0 * 0.4 = 8 J (assuming m = 1 kg).

In a plane mirror, the image is formed at the same distance behind the mirror as the object is in front, so the image is at 10 cm.

The potential gradient is V/L = 1.5V/0.5m = 3 V/m, but since the total length is 1m, the gradient is 1.5 V/m.

The potential gradient is defined as the potential difference per unit length. If the length is doubled while keeping the potential difference constant, the potential gradient halves.

Doubling the length of the wire doubles the potential difference across it, as the potential gradient remains constant.

The potential gradient is defined as the potential difference per unit length. If the length is doubled with the same potential difference, the gradient halves.

The emf can be calculated using the formula: emf = potential gradient × length. Here, emf = 2 V/m × 4 m = 8 V.